在javascript中平均2个十六进制颜色
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【中文标题】在javascript中平均2个十六进制颜色【英文标题】:Average 2 hex colors together in javascript 【发布时间】:2011-09-16 01:22:39 【问题描述】:好吧,我想我会把这个扔出去让大家思考。
给定一个 函数 (用 javascript 编写),它期望两个字符串的格式类似于十六进制颜色(ex #FF0000)
返回一个十六进制颜色,它是所传递的两种颜色的平均值。
function averageColors(firstColor,secondColor)
...
return avgColor;
--编辑--
平均值将被定义为
如果传递的颜色是黄色而第二个是浅紫色,则返回的颜色将是中等橙色
【问题讨论】:
您将什么定义为“平均”?这有多种可能的含义,具体取决于您使用的色彩空间等等。 @Amber,我更新了问题以澄清 嗅关于这个的作业的明显气味...... 不抱歉@Marc B 没有作业,只是个人项目。我希望我的 CS 课程能教 JS:/ 【参考方案1】:以下是一组紧凑的相关(相互依赖)函数:
Hex ⟷ RGB 颜色转换:
function hexToRgb(h)return['0x'+h[1]+h[2]|0,'0x'+h[3]+h[4]|0,'0x'+h[5]+h[6]|0]
function rgbToHex(r,g,b)return"#"+((1<<24)+(r<<16)+(g<<8)+ b).toString(16).slice(1);
计算 2 种十六进制颜色的平均值:需要转换函数(上)
function avgHex(h1,h2)a=hexToRgb(h1);b=hexToRgb(h2); return rgbToHex(~~((a[0]+b[0])/2),~~((a[1]+b[1])/2),~~((a[2]+b[2])/2));
生成随机十六进制颜色:
function rndHex()return'#'+('00000'+(Math.random()*(1<<24)|0).toString(16)).slice(-6);
运行 sn-p 进行演示:
// color functions (average/random/conversion)
function hexToRgb(h)return['0x'+h[1]+h[2]|0,'0x'+h[3]+h[4]|0,'0x'+h[5]+h[6]|0]
function rgbToHex(r,g,b)return"#"+((1<<24)+(r<<16)+(g<<8)+ b).toString(16).slice(1);
function rndHex()return'#'+('00000'+(Math.random()*(1<<24)|0).toString(16)).slice(-6);
function avgHex(h1,h2)a=hexToRgb(h1);b=hexToRgb(h2);return rgbToHex(~~((a[0]+b[0])/2),~~((a[1]+b[1])/2),~~((a[2]+b[2])/2));
//code below is just for the demo
function auto()if(chk.checked)tmr=setInterval(rnd,1000)elseclearTimeout(tmr)auto();
function rnd(go)for(h of[h1,h2])h.value=rndHex();avgInput();
addEventListener('input',avgInput);
function avgInput() // get avg & colorize
ha.value=avgHex(h1.value,h2.value);
for(h of [h1,h2,ha])h.style.background=h.value;
*font-family:monospace;font-size:5vw;
<label>Color 1 → <input id='h1'></label><br>
<label>Average → <input id='ha'></label><br>
<label>Color 2 → <input id='h2'></label><br>
<label>Type hex colors or <input type='checkbox' id='chk' onclick='auto()' style=' transform: scale(1.5)'checked>Autorandom</label>
【讨论】:
【参考方案2】:一种按指定百分比混合两种十六进制颜色的快速/脏/方便/ES6 方法:
// blend two hex colors together by an amount
function blendColors(colorA, colorB, amount)
const [rA, gA, bA] = colorA.match(/\w\w/g).map((c) => parseInt(c, 16));
const [rB, gB, bB] = colorB.match(/\w\w/g).map((c) => parseInt(c, 16));
const r = Math.round(rA + (rB - rA) * amount).toString(16).padStart(2, '0');
const g = Math.round(gA + (gB - gA) * amount).toString(16).padStart(2, '0');
const b = Math.round(bA + (bB - bA) * amount).toString(16).padStart(2, '0');
return '#' + r + g + b;
console.log(blendColors('#00FF66', '#443456', 0.5));
amount
应该是 0
到 1
,0
正好是 colorA
,1
正好是 colorB
,0.5
是“中点”。
【讨论】:
警告,此代码不做任何输入有效性检查。它假定它将始终接收格式良好的 6 位十六进制颜色。仅在您确定它始终会收到该信息时才使用。【参考方案3】:参加这个聚会很晚,但我个人一直在寻找一种方法来平均未定义数量的 HEX 值。基于答案@RobG,我想出了这个。当然,您添加的颜色越多,它们得到的棕色/灰色就越多,但是,也许它会有所帮助!
/**
* Averages an array of hex colors. Returns one hex value (with leading #)
*
* @param Array colors - An array of hex strings, e.g. ["#001122", "#001133", ...]
*/
function averageHex(colors)
// transform all hex codes to integer arrays, e.g. [[R, G, B], [R,G,B], ...]
let numbers = colors.map(function(hex)
// split in seperate R, G and B
let split = hex.match(/[\da-z]2/gi);
// transform to integer values
return split.map(function(toInt)
return parseInt(toInt, 16);
);
);
// reduce the array by averaging all values, resulting in an average [R, G, B]
let averages = numbers.reduce(function(total, amount, index, array)
return total.map(function(subtotal, subindex)
// if we reached the last color, average it out and return the hex value
if (index == array.length - 1)
let result = Math.round((subtotal + amount[subindex]) / array.length).toString(16);
// add a leading 0 if it is only one character
return result.length == 2 ? '' + result : '0' + result;
else
return subtotal + amount[subindex];
);
);
// return them as a single hex string
return "#" + averages.join('');
console.log(averageHex(["#FF110C", "#0000AA", "#55063d", "#06551e"]));
// expected: #571b44, see also https://www.colorhexa.com/ and enter "#FF110C+#0000AA+#55063d+#06551e"
【讨论】:
嗯,现在我看到 @Endorox 之前的回答正是这样做的......【参考方案4】:这里是函数
function avgColor(color1, color2)
//separate each color alone (red, green, blue) from the first parameter (color1)
//then convert to decimal
let color1Decimal =
red: parseInt(color1.slice(0, 2), 16),
green: parseInt(color1.slice(2, 4), 16),
blue: parseInt(color1.slice(4, 6), 16)
//separate each color alone (red, green, blue) from the second parameter (color2)
//then convert to decimal
let color2Decimal =
red: parseInt(color2.slice(0, 2), 16),
green: parseInt(color2.slice(2, 4), 16),
blue: parseInt(color2.slice(4, 6), 16),
// calculate the average of each color (red, green, blue) from each parameter (color1,color2)
let color3Decimal =
red: Math.ceil((color1Decimal.red + color2Decimal.red) / 2),
green: Math.ceil((color1Decimal.green + color2Decimal.green) / 2),
blue: Math.ceil((color1Decimal.blue + color2Decimal.blue) / 2)
//convert the result to hexadecimal and don't forget if the result is one character
//then convert it to uppercase
let color3Hex =
red: color3Decimal.red.toString(16).padStart(2, '0').toUpperCase(),
green: color3Decimal.green.toString(16).padStart(2, '0').toUpperCase(),
blue: color3Decimal.blue.toString(16).padStart(2, '0').toUpperCase()
//put the colors (red, green, blue) together to have the output
let color3 = color3Hex.red + color3Hex.green + color3Hex.blue
return color3
console.log(avgColor("FF33CC", "3300FF"))
// avgColor("FF33CC", "3300FF") => "991AE6"
console.log(avgColor("991AE6", "FF0000"))
// avgColor("991AE6", "FF0000") => "CC0D73"
console.log(avgColor("CC0D73", "0000FF"))
// avgColor("CC0D73", "0000FF") => "6607B9"
要检查您可以使用此链接和中点 1,然后混合 https://meyerweb.com/eric/tools/color-blend/#CC0D73:0000FF:1:hex
【讨论】:
【参考方案5】:我闻起来像家庭作业,但这是我的线索。
取 R、G 和 B 的每个十六进制值,并对它们进行平均。如有必要,转换为十进制以进行数学运算。
function d2h(d) return d.toString(16).padStart(2,'0');
函数 h2d(h) return parseInt(h,16);
然后返回一个包含三个元素的连接值的字符串。
【讨论】:
很好的电话@Deleplace。我更新了添加 .padStart() 的函数。【参考方案6】:这是我的功能,希望对你有帮助。
function averageColors( colorArray )
var red = 0, green = 0, blue = 0;
for ( var i = 0; i < colorArray.length; i++ )
red += hexToR( "" + colorArray[ i ] + "" );
green += hexToG( "" + colorArray[ i ] + "" );
blue += hexToB( "" + colorArray[ i ] + "" );
//Average RGB
red = (red/colorArray.length);
green = (green/colorArray.length);
blue = (blue/colorArray.length);
console.log(red + ", " + green + ", " + blue);
return new THREE.Color( "rgb("+ red +","+ green +","+ blue +")" );
//get the red of RGB from a hex value
function hexToR(h) return parseInt((cutHex( h )).substring( 0, 2 ), 16 )
//get the green of RGB from a hex value
function hexToG(h) return parseInt((cutHex( h )).substring( 2, 4 ), 16 )
//get the blue of RGB from a hex value
function hexToB(h) return parseInt((cutHex( h )).substring( 4, 6 ), 16 )
//cut the hex into pieces
function cutHex(h) if(h.charAt(1) == "x")return h.substring( 2, 8 ); else return h.substring(1,7);
【讨论】:
【参考方案7】:我讨厌听起来像是破烂的 jQuery 记录,但有 jQuery plugin for this already。
【讨论】:
【参考方案8】:如果您不想打扰很多不必要的东西,只需要几行 POJS:
// Expects input as 'nnnnnn' where each nn is a
// 2 character hex number for an RGB color value
// e.g. #3f33c6
// Returns the average as a hex number without leading #
var averageRGB = (function ()
// Keep helper stuff in closures
var reSegment = /[\da-z]2/gi;
// If speed matters, put these in for loop below
function dec2hex(v) return v.toString(16);
function hex2dec(v) return parseInt(v,16);
return function (c1, c2)
// Split into parts
var b1 = c1.match(reSegment);
var b2 = c2.match(reSegment);
var t, c = [];
// Average each set of hex numbers going via dec
// always rounds down
for (var i=b1.length; i;)
t = dec2hex( (hex2dec(b1[--i]) + hex2dec(b2[i])) >> 1 );
// Add leading zero if only one character
c[i] = t.length == 2? '' + t : '0' + t;
return c.join('');
());
【讨论】:
谢谢你,我向你致敬,RobG以上是关于在javascript中平均2个十六进制颜色的主要内容,如果未能解决你的问题,请参考以下文章
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