将数组中的多个值匹配到对象数组

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【中文标题】将数组中的多个值匹配到对象数组【英文标题】:Matching multiple values from array to object array 【发布时间】:2022-01-17 04:26:49 【问题描述】:

我正在尝试创建一个预订应用程序并标记出不可用的插槽。不可用的插槽在数组中,例如:

const unavailable = [ "11:00am a 12:00pm", "17:00pm a 18:00pm"]

总槽数为

 let slots = [ 
    slot: "9:00am a 10:00am",
    isReserved: false,
  ,
  
    slot: "10:00am a 11:00am",
    isReserved: false,
  ,
   slot: "11:00am a 12:00pm", isReserved: false ,
  
    slot: "15:00pm a 16:00pm",
    isReserved: false,
  ,
  
    slot: "17:00pm a 18:00pm",
    isReserved: false,
  ,
  
    slot: "18:00pm a 19:00pm",
    isReserved: false,
  ,
   slot: "19:00pm a 20:00pm", isReserved: false ,
];

我的目标是使用不可用的数组和其中的每个值,并找到如何将该字段更改为

isReserved: true

我试过这样过滤

    const matches = slots.filter((same) => same.slot === unavailable);

但不起作用。做了什么样的工作是

    const matches = slots.filter((same) => same.slot === unavailable[0]);

但那只匹配第一个值,我仍然不知道如何更改 isReserved 字段。

【问题讨论】:

你想要一个新数组还是改变旧数组? 我想变异,但要么或应该为我需要的东西工作 【参考方案1】:

如果找到插槽,您可以迭代和更新。

const
    unavailable = ["11:00am a 12:00pm", "17:00pm a 18:00pm"],
    slots = [ slot: "9:00am a 10:00am", isReserved: false ,  slot: "10:00am a 11:00am", isReserved: false ,  slot: "11:00am a 12:00pm", isReserved: false ,  slot: "15:00pm a 16:00pm", isReserved: false ,  slot: "17:00pm a 18:00pm", isReserved: false ,  slot: "18:00pm a 19:00pm", isReserved: false ,  slot: "19:00pm a 20:00pm", isReserved: false ];

slots.forEach(o => 
    if (unavailable.some(slot => slot === o.slot)) o.isReserved = true;
);

console.log(slots);
.as-console-wrapper  max-height: 100% !important; top: 0; 

如果您不想改变原始数组,可以使用新属性映射对象。

const
    unavailable = ["11:00am a 12:00pm", "17:00pm a 18:00pm"],
    slots = [ slot: "9:00am a 10:00am", isReserved: false ,  slot: "10:00am a 11:00am", isReserved: false ,  slot: "11:00am a 12:00pm", isReserved: false ,  slot: "15:00pm a 16:00pm", isReserved: false ,  slot: "17:00pm a 18:00pm", isReserved: false ,  slot: "18:00pm a 19:00pm", isReserved: false ,  slot: "19:00pm a 20:00pm", isReserved: false ],
    result = slots.map(o => (
        ...o,
        isReserved: o.isReserved || unavailable.some(slot => slot === o.slot)
    ));

console.log(result);
.as-console-wrapper  max-height: 100% !important; top: 0; 

【讨论】:

您提供的第二个选项效果很好!为我节省了很多时间,非常感谢!【参考方案2】:

你可以使用地图操作符,可以做到这一点。

const unavailable = [ "11:00am a 12:00pm", "17:00pm a 18:00pm"]
let slots = [ 
    slot: "9:00am a 10:00am",
    isReserved: false,
  ,
  
    slot: "10:00am a 11:00am",
    isReserved: false,
  ,
   slot: "11:00am a 12:00pm", isReserved: false ,
  
    slot: "15:00pm a 16:00pm",
    isReserved: false,
  ,
  
    slot: "17:00pm a 18:00pm",
    isReserved: false,
  ,
  
    slot: "18:00pm a 19:00pm",
    isReserved: false,
  ,
   slot: "19:00pm a 20:00pm", isReserved: false ,
];

const slots = slots.map(slotobj=>
if(unavailable.includes(slotobj.slot))
 slotobj.isReserved =true

return slotobj;
)

【讨论】:

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