为啥我会收到此语法错误？ （Python）

Posted 2023-02-22

【中文标题】为啥我会收到此语法错误？ （Python）

【英文标题】：Why am I getting this syntax error? (Python)为什么我会收到此语法错误？ （Python）

【发布时间】：2022-01-23 08:53:32

【问题描述】：

这里是 Python 菜鸟。今天下午参加了“猜数字游戏”。 对我来说一切都很好，但我在第 26 行不断收到语法错误：

else player_number >= secret_number：

我已经尝试了所有方法，但我根本无法弄清楚。 感谢您的帮助。

import random, sys
secret_number = random.randint(1, 99)
countdown_timer = 7

print("This is a number guessing game.")
print("You have to guess a number between 1 and 99!")
print("You have 7 attempts to guess the correct number")
print("Good luck!")
print("\n")
print("Your first guess is: ")

while countdown_timer != 0:
    player_number = int(input())
    countdown_timer = (countdown_timer - 1)
    if player_number == secret_number:
        print("\n")
        print("That's it!! The number was: " + secret_number)
        print("\n")
        print("Congratulations!")
        print("Please try again.")
        quit()
    elif player_number <= secret_number:
        print("Higher!")
        print("You have " + int(countdown_timer) + "guesses left.")
        print("Please enter your next guess: ")
    else player_number >= secret_number:
        print("Lower!")
        print("You have " + int(countdown_timer) + "guesses left.")
        print("Please enter your next guess: ")
        
print("You are out of guesses, sorry.")
print("The correct number was: " + secret_number)
print("Please try again.")

【问题讨论】：

什么是语法错误？

【参考方案1】：

将 else 语句更改为 elif。 else 语句不带任何表达式。因此：

elif player_number >= secret_number:
    print("Lower!")
    print("You have " + int(countdown_timer) + "guesses left.")
    print("Please enter your next guess: ")

在实际运行代码后，我看到您正在尝试连接整数和字符串，但这不起作用。要使其工作，请使用 f' 打印。

代码如下：

import random
secret_number = random.randint(1, 99)
countdown_timer = 7

print("This is a number guessing game.")
print("You have to guess a number between 1 and 99!")
print("You have 7 attempts to guess the correct number")
print("Good luck!")
print("\n")
print("Your first guess is: ")

while countdown_timer != 0:
    player_number = int(input())
    countdown_timer = (countdown_timer - 1)
    if player_number == secret_number:
        print("\n")
        print(f"That's it!! The number was: secret_number") # f' print here
        print("\n")
        print("Congratulations!")
        print("Please try again.")
        quit()
    elif player_number <= secret_number:
        print("Higher!")
        print(f"You have   countdown_timer guesses left.")  # here
        print("Please enter your next guess: ")
    elif player_number >= secret_number:
        print("Lower!")
        print(f"You have   countdown_timer guesses left.") #here
        print("Please enter your next guess: ")
        
print("You are out of guesses, sorry.")
print(f"The correct number was: secret_number") # and here
print("Please try again.") 

【讨论】：

已解决！！！谢谢！

【参考方案2】：

我会用“else:”替换整行并添加注释：

    if player_number == secret_number:
        ...
    elif player_number <= secret_number:
        ...
    else:
        # player_number >= secret_number
        ...