当您不知道键的名称时访问对象内部的数据

Posted 2023-02-22

【中文标题】当您不知道键的名称时访问对象内部的数据

【英文标题】：Accessing the data inside an object when you dont know the name of the key

【发布时间】：2021-12-10 14:18:08

【问题描述】：

我有一组数据，其中数据的关键是不可预测的。我正在尝试读取嵌套对象，但似乎无法访问它，因此我可以检查下一个键 Physicians 或 NonPhysicians 的值。我尝试使用嵌套值的键来访问它，但它只返回未定义。当我安慰 item 时，我得到了预期值，当我安慰 org 时，我得到了对象上的键，所以我不确定这里出了什么问题。

const NEWRATES = 
  standard: [
    
      "ORG A": 
        Physicians: 
          telehealth: 
            weekdayEncounters: 15,
            weeknightEncounters: 16.25,
            weekendDayEncounters: 16.25,
            weekendNightEncounters: 17.25,
            holidayEncounters: 17.25,
            stipend: 0,
          ,
        ,
        NonPhysicians: 
          telehealth: 
            orgName: "Standard",
            weekdayEncounters: 15,
            weeknightEncounters: 16.25,
            weekendDayEncounters: 16.25,
            weekendNightEncounters: 17.25,
            holidayEncounters: 17.25,
            stipend: 0,
          ,
        ,
        date: "07-2021",
        orgName: "some org",
        ltc: false,
      ,
    ,
    
      "ORG B": 
        Physicians: 
          telehealth: 
            weekdayEncounters: 15,
            weeknightEncounters: 16.25,
            weekendDayEncounters: 16.25,
            weekendNightEncounters: 17.25,
            holidayEncounters: 17.25,
            stipend: 0,
          ,
        ,
        NonPhysicians: 
          telehealth: 
            orgName: "Standard",
            weekdayEncounters: 15,
            weeknightEncounters: 16.25,
            weekendDayEncounters: 16.25,
            weekendNightEncounters: 17.25,
            holidayEncounters: 17.25,
            stipend: 0,
          ,
        ,
        date: "07-2021",
        orgName: "some org",
        ltc: false,
      ,
    ,
  ],
  ltc: [
    
      Infinity: 
        Physicians: 
          associates: 
            roundingHours: 10,
            onCallHours: 10,
            weekdayEncounters: 16,
            weeknightEncounters: 17.25,
            weekendDayEncounters: 18.25,
            weekendNightEncounters: 19.25,
            holidayEncounters: 20.25,
            stipend: 0,
          ,
        ,
        NonPhysicians: 
          associates: 
            roundingHours: 0,
            onCallHours: 0,
            weekdayEncounters: 15,
            weeknightEncounters: 16.25,
            weekendDayEncounters: 16.25,
            weekendNightEncounters: 17.25,
            holidayEncounters: 17.25,
            stipend: 0,
          ,
        ,
        date: "07-2021",
        orgName: "some org",
        ltc: true,
      ,
    ,
  ],
;

const sortData = Object.values(NEWRATES);
  const NEWfiltered = !!NEWRATES && sortData;
  const byProviderType =
    !!NEWfiltered &&
    NEWfiltered.map((item, idx) => 
      for (let i = 0; i < item.length; i++) 
        let list = [];
        let org = Object.keys(item[i]).toString();

        console.log(item[org]);
      
    );

【问题讨论】：

Object.values()

这是一个正在运行的堆栈闪电战：stackblitz.com/edit/js-6gbjyk

【参考方案1】：

你很接近。你需要继续更深一层。

// Your Code Now
console.log(item[org]);

// SHOULD BE
console.log(item[i][org]);

进行此更新，您将看到它正常工作。 HERE is a working version 在 stackblitz 上。