为啥非规范化不返回嵌套对象？

Posted 2023-02-22

【中文标题】为啥非规范化不返回嵌套对象？

【英文标题】：Why denormalize not return nested object?为什么非规范化不返回嵌套对象？

【发布时间】：2019-10-11 01:45:20

【问题描述】：

我使用来自normalizr 包的denormalize 作为以下代码：

import  normalize, schema, denormalize  from 'normalizr';

const categoriesData = [
   id: 1, name: 'category-1' ,
   id: 2, name: 'category-2' ,
   id: 3, name: 'category-3' ,
   id: 40, name: 'category-40' ,
];

const subCategoriesData = [
   id: 1, name: 'sub-category-a', category: 1 ,
   id: 2, name: 'sub-category-b', category: 2 ,
   id: 3, name: 'sub-category-c', category: 1 ,
   id: 4, name: 'sub-category-d', category: 3 ,
   id: 500, name: 'sub-category-e', category: 40 ,
]

const category = new schema.Entity('categories');
const categories = new schema.Array(category);

const subcategory = new schema.Entity('subCategories');
const subcategories = new schema.Array(subcategory);

const normalizedData = normalize(categoriesData, categories);
const denormalizedData = denormalize(normalizedData.result, categories, normalizedData.entities);

console.log( normalizedData );
console.log( denormalizedData );

const normalizedData2 = normalize(subCategoriesData, subcategories);
const denormalizedData2 = denormalize(normalizedData2.result, subcategories, normalizedData2.entities);

console.log( normalizedData2 );
console.log( denormalizedData2 );

denormalizedData2 的输出是

id: 1, name: "sub-category-a", category: 1,
...

而我期待的是：

id: 1, name: "sub-category-a", category:  id: 1, name: 'category-1'  ,
...

如何使用normalizr实现目标？

【问题讨论】：

因为这里没有将categoriesData 带入denormalizedData2 的代码。

我编辑我的问题。

【参考方案1】：

老问题，但万一有人需要答案。 您的架构是错误的。 而不是

const subcategory = new schema.Entity('subCategories');

你应该写

const subcategory = new schema.Entity('subCategories', category: category );

这意味着子类别具有category 属性，由category 架构描述。