Android- 创建 JSON 数组和 JSON 对象
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【中文标题】Android- 创建 JSON 数组和 JSON 对象【英文标题】：Android- create JSON Array and JSON Object 【发布时间】：2013-07-22 12:20:32 【问题描述】：如何在 android 中创建具有这种格式的 JSON： 由于我将传递的 API 将解析 JsonArray 然后解析对象。 或者如果只是传递一个json对象可以吗？因为每次服务调用我只需插入 1 个事务。
"student": [
"id": 1,
"name": "John Doe",
"year": "1st",
"curriculum": "Arts",
"birthday": 3/3/1995
,
"id": 2,
"name": "Michael West",
"year": "2nd",
"curriculum": "Economic",
"birthday": 4/4/1994
]
我所知道的只是 JSONObject。 喜欢这个。
JSONObject obj = new JSONObject();
try
obj.put("id", "3");
obj.put("name", "NAME OF STUDENT");
obj.put("year", "3rd");
obj.put("curriculum", "Arts");
obj.put("birthday", "5/5/1993");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
任何想法。谢谢
【问题讨论】：
reference link 将 JSONObject 放入 JSONArray 以实现发布的格式.. 看看JSONArray类developer.android.com/reference/org/json/JSONArray.html @ChintanKhetiya ：你救了我的一天，先生。调试器:) 【参考方案1】：使用以下代码：
JSONObject student1 = new JSONObject();
try
student1.put("id", "3");
student1.put("name", "NAME OF STUDENT");
student1.put("year", "3rd");
student1.put("curriculum", "Arts");
student1.put("birthday", "5/5/1993");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
JSONObject student2 = new JSONObject();
try
student2.put("id", "2");
student2.put("name", "NAME OF STUDENT2");
student2.put("year", "4rd");
student2.put("curriculum", "scicence");
student2.put("birthday", "5/5/1993");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
JSONArray jsonArray = new JSONArray();
jsonArray.put(student1);
jsonArray.put(student2);
JSONObject studentsObj = new JSONObject();
studentsObj.put("Students", jsonArray);
String jsonStr = studentsObj.toString();
System.out.println("jsonString: "+jsonStr);
【讨论】：
完美的例子！【参考方案2】：public JSONObject makJsonObject(int id[], String name[], String year[],
String curriculum[], String birthday[], int numberof_students)
throws JSONException
JSONObject obj = null;
JSONArray jsonArray = new JSONArray();
for (int i = 0; i < numberof_students; i++)
obj = new JSONObject();
try
obj.put("id", id[i]);
obj.put("name", name[i]);
obj.put("year", year[i]);
obj.put("curriculum", curriculum[i]);
obj.put("birthday", birthday[i]);
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
jsonArray.put(obj);
JSONObject finalobject = new JSONObject();
finalobject.put("student", jsonArray);
return finalobject;
【讨论】：
感谢这个简单的方法。【参考方案3】： JSONObject obj = new JSONObject();
try
obj.put("id", "3");
obj.put("name", "NAME OF STUDENT");
obj.put("year", "3rd");
obj.put("curriculum", "Arts");
obj.put("birthday", "5/5/1993");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
JSONArray js=new JSONArray(obj.toString());
JSONObject obj2 = new JSONObject();
obj2.put("student", js.toString());
【讨论】：
我假设 'JSONObject obj2 = new JSONObject(); 中的 'obj' obj.put("学生", js.toString());'是 'obj2' 吗？【参考方案4】：您可以创建一个方法并将参数传递给它并获取 json 作为响应。
private JSONObject jsonResult(String Name,int id, String curriculum) throws JSONException
JSONObject json = null;
json = new JSONObject("\"" + "Name" + "\":" + "\"" + Name+ "\""
+ "," + "\"" + "Id" + "\":" + id + "," + "\"" + "Curriculum"
+ "\":" + "\"" + curriculum+ "\"" + "");
return json;
希望对你有所帮助。
【讨论】：
【参考方案5】：这是一个更简单（但不是那么短）的版本，不需要 try-catch：
Map<String, String> data = new HashMap<>();
data.put("user", "mark@facebook.com");
data.put("pass", "123");
JSONObject jsonData = new JSONObject(data);
如果你想在字段中添加一个jsonObject，你可以这样做：
data.put("socialMedia", (new JSONObject()).put("facebookId", "1174989895893400"));
data.put("socialMedia", (new JSONObject()).put("googleId", "106585039098745627377"));
不幸的是，由于 put() 方法，它需要一个 try-catch。
如果你想避免再次try-catch（不是很推荐，但如果你能保证格式正确的json字符串也可以），你可以这样做：
data.put("socialMedia", " 'facebookId': '1174989895893400' ");
你可以对 JsonArrays 等做同样的事情。
干杯。
【讨论】：
【参考方案6】：现在回答太晚了，很抱歉，创建以下正文：
"username": "ًRajab",
"email": "rajab.mohammadi@gmail.com",
"phone": "+93767626554",
"password": "123asd",
"carType": "600fdcc646bc6409ae97e2ab",
"fcmToken":"lljlkdsajfljasldfj;lsa",
"profilePhoto": "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg",
"documents":
"DL": [
"_id": "5fccb687c5b4260011810125",
"uriPath": "https://webfume-onionai.s3.amazonaws.com/guest/public/document/326634-beats_by_dre-wallpaper-1366x768.jpg"
],
"Registration": [
"_id": "5fccb687c5b4260011810125",
"uriPath": "https://webfume-onionai.s3.amazonaws.com/guest/public/document/326634-beats_by_dre-wallpaper-1366x768.jpg"
],
"Insurance":[
"_id": "5fccb687c5b4260011810125",
"uriPath": "https://webfume-onionai.s3.amazonaws.com/guest/public/document/326634-beats_by_dre-wallpaper-1366x768.jpg"
],
"CarInside":[
"_id": "5fccb687c5b4260011810125",
"uriPath": "https://webfume-onionai.s3.amazonaws.com/guest/public/document/326634-beats_by_dre-wallpaper-1366x768.jpg"
],
"CarOutside":[
"_id": "5fccb687c5b4260011810125",
"uriPath": "https://webfume-onionai.s3.amazonaws.com/guest/public/document/326634-beats_by_dre-wallpaper-1366x768.jpg"
]
您可以像下面的代码一样动态创建：
JSONObject jsonBody = new JSONObject();
try
jsonBody.put("username", userName);
jsonBody.put("email", email);
jsonBody.put("phone", contactNumber);
jsonBody.put("password", password);
jsonBody.put("carType", carType);
jsonBody.put("fcmToken", "lljlkdsajfljasldfj;lsa");
jsonBody.put("profilePhoto", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg");
JSONObject document = new JSONObject();
try
document.put("DL", createDocument("5fccb687c5b4260011810125", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg"));
document.put("Registration", createDocument("5fccb687c5b4260011810125", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg"));
document.put("Insurance", createDocument("5fccb687c5b4260011810125", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg"));
document.put("CarInside", createDocument("5fccb687c5b4260011810125", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg"));
document.put("CarOutside", createDocument("5fccb687c5b4260011810125", "https://st.depositphotos.com/2101611/3925/v/600/depositphotos_39258143-stock-illustration-businessman-avatar-profile-picture.jpg"));
catch (JSONException e)
e.printStackTrace();
jsonBody.put("documents", document.toString());
Log.i("MAHDI", "Hello: Mahdi: Data: " + jsonBody);
catch (JSONException e)
e.printStackTrace();
以及createDocument方法代码：
public JSONArray createDocument(String id, String imageUrl)
JSONObject dlObject = new JSONObject();
try
dlObject.put("_id", id);
dlObject.put("uriPath", imageUrl);
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
JSONArray dlArray = new JSONArray();
dlArray.put(dlObject);
return dlArray;
【讨论】：
【参考方案7】：一直在努力解决这个问题，直到我找到答案：
使用 GSON 库：
Gson gson = Gson();
String str_json = gson.tojson(jsonArray);`
传递 json 数组。这将被自动字符串化。这个选项非常适合我。
【讨论】：
【参考方案8】：JSONObject jsonResult = new JSONObject();
try
jsonResult.put("clave", "valor");
jsonResult.put("username", "iesous");
jsonResult.put("password", "1234");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
Log.d("DEV","jsonResult->"+jsonResult);
【讨论】：
你应该添加一些叙述来解释你的答案并改进格式。【参考方案9】： Map<String, String> params = new HashMap<String, String>();
//** Temp array
List<String[]> tmpArray = new ArrayList<>();
tmpArray.add(new String[]"b001","book1");
tmpArray.add(new String[]"b002","book2");
//** Json Array Example
JSONArray jrrM = new JSONArray();
for(int i=0; i<tmpArray.size(); i++)
JSONArray jrr = new JSONArray();
jrr.put(tmpArray.get(i)[0]);
jrr.put(tmpArray.get(i)[1]);
jrrM.put(jrr);
//Json Object Example
JSONObject jsonObj = new JSONObject();
try
jsonObj.put("plno","000000001");
jsonObj.put("rows", jrrM);
catch (JSONException ex)
ex.printStackTrace();
// Bundles them
params.put("user", "guest");
params.put("tb", "book_store");
params.put("action","save");
params.put("data", jsonObj.toString());
// Now you can send them to the server.
【讨论】：
【参考方案10】： public void DataSendReg(String picPath, final String ed2, String ed4, int bty1, String bdatee, String ed1, String cno, String address , String select_item, String select_item1, String height, String weight)
final ProgressDialog dialog=new ProgressDialog(SignInAct.this);
dialog.setMessage("Process....");
AsyncHttpClient httpClient=new AsyncHttpClient();
RequestParams params=new RequestParams();
File pic = new File(picPath);
try
params.put("image",pic);
catch (FileNotFoundException e)
e.printStackTrace();
params.put("height",height);
params.put("weight",weight);
params.put("pincode",select_item1);
params.put("area",select_item);
params.put("address",address);
params.put("contactno",cno);
params.put("username",ed1);
params.put("email",ed2);
params.put("pass",ed4);
params.put("bid",bty1);
params.put("birthdate",bdatee);
params.put("city","Surat");
params.put("state","Gujarat");
httpClient.post(WebAPI.REGAPI,params,new JsonHttpResponseHandler()
@Override
public void onStart()
dialog.show();
@Override
public void onSuccess(int statusCode, Header[] headers, JSONObject response)
try
String done=response.get("msg").toString();
if(done.equals("s"))
Toast.makeText(SignInAct.this, "Registration Success Fully", Toast.LENGTH_SHORT).show();
DataPrefrenceMaster.SetRing(ed2);
startActivity(new Intent(SignInAct.this, LoginAct.class));
finish();
else if(done.equals("ex"))
Toast.makeText(SignInAct.this, "email already exist", Toast.LENGTH_SHORT).show();
else Toast.makeText(SignInAct.this, "Registration failed", Toast.LENGTH_SHORT).show();
catch (JSONException e)
Toast.makeText(SignInAct.this, "e :: ="+e.getMessage(), Toast.LENGTH_SHORT).show();
@Override
public void onFailure(int statusCode, Header[] headers, Throwable throwable, JSONObject errorResponse)
Toast.makeText(SignInAct.this, "Server not Responce", Toast.LENGTH_SHORT).show();
Log.d("jkl","error");
@Override
public void onFinish()
dialog.dismiss();
);
【讨论】：
这将有助于在您的代码中添加一些上下文解释，因为您似乎在回答错误的问题...【参考方案11】：你应该使用 JSONObject.put 方法
https://developer.android.com/reference/org/json/JSONObject.html#put(java.lang.String,%20double)
【讨论】：
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