Python - 将嵌套项添加到一个嵌套列表

Posted 2023-02-19

【中文标题】Python - 将嵌套项添加到一个嵌套列表

【英文标题】：Python - Add nested items to one nested list

【发布时间】：2022-01-20 23:21:06

【问题描述】：

我正在尝试创建一个名为 Results 的嵌套 Python 字典。

我正在使用 AWS Rekognition 获取图像并输出结果。

results_dict 编译后只包含一个结果，我希望将所有结果放在一个嵌套循环中

我想得到：

    "Results": [
        
            "Name": "Human",
            "Confidence": 98.87621307373047,
        ,
                
            "Name": "Face",
            "Confidence": 98.87621307373047,
        ,
        
            "Name": "Person",
            "Confidence": 98.87621307373047,
        ,
        
    ]

但我得到：

    'Results': 
        
          'Name': 'Paper', 
          'Confidence': 57.299766540527344
        

代码正在替换文本，我想添加另一组名称和置信度。

我的代码是：

import boto3
import json

BUCKET = "*****"

FOLDER = 'testing/'
JOEY =  FOLDER + "Joey_30_Sept.png"
BEYONCE = FOLDER + "beyonce_rekognition_moderation_testing.jpg"
MANBEARD = FOLDER + "man_beard.jpg"
MEN = FOLDER + "men_group.jpg"


client = boto3.client('rekognition')
                                
response = client.detect_labels(Image=
                                'S3Object': 
                                    'Bucket': BUCKET,
                                    'Name': JOEY
                                ,
                                MaxLabels = 10,
                                MinConfidence=0)
 

results_dict = 
results_dict['Results'] = 
results_dict['Results']['Name'] = ""
results_dict['Results']['Confidence'] = ""
               
for label in response['Labels']:
    name = label['Name'] #to get the whole bounding box.
    confidence = label['Confidence'] 
    
    name_str = str(name)
    conf_str = str(confidence)
    
    results_dict["Results"]["Name"] = label['Name']
    results_dict["Results"]["Confidence"] = label['Confidence']

print(results_dict)

【参考方案1】：

您将results_dict['Results'] 定义为字典而不是字典列表：

...
results_dict = 
results_dict['Results'] = []
results_dict['Results']['Name'] = ""
results_dict['Results']['Confidence'] = ""
               
for label in response['Labels']:
    name = label['Name'] #to get the whole bounding box.
    confidence = label['Confidence'] 
    
    name_str = str(name)
    conf_str = str(confidence)
    
    results_dict['Results'].append(["Name": name_str, "Confidence": conf_str )
print(results_dict)

【讨论】：

完美！谢谢你。我整天都在不停地写代码。我需要另一双眼睛才能看到错误。谢谢。