查询结果未按预期返回
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【中文标题】查询结果未按预期返回【英文标题】：Query Result Not Returned As Expected 【发布时间】：2020-03-28 19:23:47 【问题描述】：我正在努力解决几天前根据一位 SO 用户的建议尝试的查询，并使其与以下内容一起使用：
WITH your_table(ID,STOREDATE,VALUE,INFO)
AS
(
SELECT 1122,'1/1/2020',2,'DONE' UNION ALL
SELECT 1122,'1/2/2020',1,'DONE' UNION ALL
SELECT 1122,'1/3/2020',7,'DONE' UNION ALL
SELECT 1122,'1/4/2020',8,'DONE'
),
CTE AS
(
SELECT ID,
STOREDATE,
VALUE,
CASE
WHEN VALUE = 8 THEN 0
WHEN VALUE + LAG(VALUE) OVER(ORDER BY STOREDATE) = 8 THEN 0
WHEN VALUE + LEAD(VALUE) OVER(ORDER BY STOREDATE) = 8 THEN 0
ELSE VALUE
END VALUE2,
INFO
FROM your_table
)
SELECT *,
CASE
WHEN
(
SELECT COUNT(*) FROM CTE A
WHERE A.VALUE2 = 0 AND A.STOREDATE < B.STOREDATE
) >= 1 AND B.VALUE = 8 THEN B.VALUE
ELSE B.VALUE2
END VALUE3
FROM CTE B
注意：我的想法是在任何给定的行中求和 8。所以对于上面的输入，我预期的输出是这样的。
输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 0 //1 + 7 = 8; it'll update both the rows with zero
1122 1/3/2020 0 //For this, it's just fine
1122 1/4/2020 8 DONE
现在我的问题在于以下输入，我无法弄清楚如何获得预期的结果集。
输入：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 1 DONE
1122 1/3/2020 2 DONE
1122 1/4/2020 7 DONE
预期输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 0
1122 1/3/2020 2 DONE
1122 1/4/2020 0
输入：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 2 DONE
1122 1/3/2020 2 DONE
1122 1/4/2020 2 DONE
预期输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 0
1122 1/2/2020 0
1122 1/3/2020 0
1122 1/4/2020 0
我可能有几个 id 来获得如下的确切结果，但是对查询进行调整并不能达到我想要的结果。任何建议将不胜感激 - 谢谢。
WITH your_table(ID,STOREDATE,VALUE,INFO)
AS
(
SELECT 1122,'1/1/2020',2,'DONE' UNION ALL
SELECT 1122,'1/2/2020',7,'DONE' UNION ALL
SELECT 1122,'1/3/2020',1,'DONE' UNION ALL
SELECT 1122,'1/4/2020',8,'DONE' UNION ALL
SELECT 4466,'1/1/2020',2,'DONE' UNION ALL
SELECT 4466,'1/2/2020',7,'DONE' UNION ALL
SELECT 4466,'1/3/2020',1,'DONE' UNION ALL
SELECT 4466,'1/4/2020',8,'DONE'
),
CTE AS
(
SELECT ID,
STOREDATE,
VALUE,
CASE
WHEN VALUE = 8 THEN 0
WHEN VALUE + LAG(VALUE) OVER(ORDER BY STOREDATE) = 8 THEN 0
WHEN VALUE + LEAD(VALUE) OVER(ORDER BY STOREDATE) = 8 THEN 0
ELSE VALUE
END VALUE2,
INFO
FROM your_table
)
SELECT *,
CASE
WHEN
(
SELECT COUNT(*) FROM CTE A
WHERE A.VALUE2 = 0 AND A.STOREDATE < B.STOREDATE
) >= 1 AND B.VALUE = 8 THEN B.VALUE
ELSE B.VALUE2
END VALUE3
FROM CTE B
预期输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 0
1122 1/3/2020 0
1122 1/4/2020 8 DONE
4466 1/1/2020 2 DONE
4466 1/2/2020 0
4466 1/3/2020 0
4466 1/4/2020 8 DONE
更新 1：请检查以下内容
输入：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 1 DONE
1122 1/3/2020 2 DONE
1122 1/4/2020 7 DONE
预期输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 0
1122 1/3/2020 2 DONE
1122 1/4/2020 0
输入：
ID STOREDATE VALUE INFO
1122 1/1/2020 2 DONE
1122 1/2/2020 2 DONE
1122 1/3/2020 2 DONE
1122 1/4/2020 2 DONE
预期输出：
ID STOREDATE VALUE INFO
1122 1/1/2020 0
1122 1/2/2020 0
1122 1/3/2020 0
1122 1/4/2020 0
【问题讨论】：
【参考方案1】：您的第一个大错误是“stordate”不是日期，而是日期的字符串表示形式。因此，所有比较都将是字符串的比较，而不是日期的比较。作为字符串，首先出现的是“01/02/2020”或“02/01/2019”。
WITH your_table(ID,STOREDATE,VALUE,INFO)
AS
(
SELECT 1122,to_date('01/01/2020','dd/mm/yyyy'),2,'DONE' UNION ALL
SELECT 1122,to_date('01/02/2020','dd/mm/yyyy'),1,'DONE' UNION ALL
SELECT 1122,to_date('01/03/2020','dd/mm/yyyy'),7,'DONE' UNION ALL
SELECT 1122,to_date('01/04/2020','dd/mm/yyyy'),8,'DONE'
),
【讨论】：
AFAIK，TO_DATE 是 oracle 的内置函数，上面的示例用于 SQL Server @EdStevens。
@user8512043。该线程被标记为 oracle 和 sqlserver。这本身就是 OP 的一个错误，因为众所周知，解决方案很少是“数据库不可知论者”。开始问题中的第一个代码示例对我来说就像 oracle sql。无论如何，基本原则仍然成立——它将字符串视为日期，因此，比较不会按预期进行。【参考方案2】：
你能检查一下下面的解决方案吗-
DEMO HERE
DEMO2 HERE
WITH your_table(ID,STOREDATE,VALUE,INFO)
AS
(
SELECT 1122,'1/1/2020',2,'DONE' UNION ALL
SELECT 1122,'1/2/2020',7,'DONE' UNION ALL -- This two returns zero
SELECT 1122,'1/3/2020',1,'DONE' UNION ALL -- As 1 and 7 have sum of 8; it should check once I mean the sum
SELECT 1122,'1/4/2020',7,'DONE' UNION ALL -- Unfortunately this returns zero as well
SELECT 4466,'1/1/2020',2,'DONE' UNION ALL
SELECT 4466,'1/2/2020',7,'DONE' UNION ALL
SELECT 4466,'1/3/2020',1,'DONE' UNION ALL
SELECT 4466,'1/4/2020',8,'DONE'
),
CTE AS
(
SELECT ID,
STOREDATE,
VALUE,
CASE
WHEN VALUE = 8 THEN 0
WHEN VALUE + LAG(VALUE) OVER(ORDER BY ID, STOREDATE) = 8
AND ID = LAG(ID) OVER(ORDER BY ID, STOREDATE) THEN 0
WHEN VALUE + LEAD(VALUE) OVER(ORDER BY ID, STOREDATE) = 8
AND ID = LEAD(ID) OVER(ORDER BY ID, STOREDATE) THEN 0
ELSE VALUE
END VALUE2,
INFO
FROM your_table
)
SELECT *,
CASE
WHEN
(
SELECT COUNT(*) FROM CTE A
WHERE A.VALUE2 = 0 AND A.STOREDATE < B.STOREDATE
AND A.ID = B.ID
) >= 1 AND B.VALUE = 8 THEN B.VALUE
WHEN
(
SELECT SUM(A.VALUE)
FROM CTE A
WHERE A.VALUE2 = 0
AND A.STOREDATE < B.STOREDATE
AND A.ID = B.ID
)>= 8 THEN B.VALUE
ELSE B.VALUE2
END VALUE3
FROM CTE B
【讨论】：
以上适用于多个 id @mkRabbani。但是没有返回预期的输出，请参阅我的输入示例 - 再次感谢。检查我在此处修改的输入样本 - dbfiddle.uk/… 好的，我会检查的。 @user8512043 请查看我更新的答案并参考链接 DEMO2 已经检查并工作了@mkRabbani。虽然最后两种类型不匹配。如果可以，请使用 Update 1 示例查看我更新的帖子。再次感谢您的时间和精力。 不确定您要指示哪个样本数据集:(以上是关于查询结果未按预期返回的主要内容，如果未能解决你的问题，请参考以下文章