在使用 POSTMAN 时，AJAX POST 请求不起作用

Posted 2023-05-08

【中文标题】在使用 POSTMAN 时，AJAX POST 请求不起作用

【英文标题】：AJAX POST request not working while working on POSTMAN

【发布时间】：2021-12-24 01:34:58

【问题描述】：

我正在尝试通过 AJAX 请求发布数据。 这是执行此操作的代码：

console.log(quote)
$.ajax(
         url: ' path('set_products_in_db') ',
         type: 'POST',
         contentType: "application/json",
         dataType: 'json',
         data: quote,
         success: function (data, status) 
         result = data;
         if (status === 'success') 
         console.log(data)
         
         
         )

ajax 请求返回 500 错误。 如您所见，我之前做了一个 console.log 来查看我发送的内容。 该对象似乎是正确的。 我从检查窗口复制对象并将其粘贴到 Postman 中，它正在工作。 我想问题出在我的 Ajax 请求中，我发送的对象仍然在这里：

    "name": "Test",
    "firstname": "Test2",
    "company": "Company",
    "phone": "123456789",
    "email": "[e-mail]",
    "TVA": "123456789",
    "street": "Rue du test",
    "number": "3",
    "cpt": "A",
    "postalCode": "1000",
    "city": "Paris",
    "country": "France",
    "products": [
        
            "name": "Produit1",
            "price": "10",
            "reference": "Ref1"
        ,
        
            "name": "Produit2",
            "price": "15",
            "reference": "Ref2"
        
    ]

尽管我不确定是否有必要，这是我的 php 后端

 public function setProducts(Request $request)
    
        $productsRepo = $this->getDoctrine()
            ->getRepository(Product::class);
        $allproducts = $productsRepo->findAll();
        $allref = array_map(function ($e) 
            return is_object($e) ? $e->getReference() : $e['Reference'];
        , $allproducts);
        dump($allproducts);
        dump(array_column($allproducts, 'reference'));
        $JSONrequest = json_decode($request->getContent());
        $products = $JSONrequest->products;
        $name = $JSONrequest->name;
        $firstname = $JSONrequest->firstname;
        $company = $JSONrequest->company;
        $phone = $JSONrequest->phone;
        $email = $JSONrequest->email;
        $street = $JSONrequest->street;
        $number = $JSONrequest->number;
        $cpt = $JSONrequest->cpt;
        $postalCode = $JSONrequest->postalCode;
        $city = $JSONrequest->city;
        $country = $JSONrequest->country;
        $TVA = $JSONrequest->TVA;
        $entityManager = $this->getDoctrine()->getManager();
        $repoGathering = $this->getDoctrine()
            ->getRepository(Gathering::class);
        $gathering = $repoGathering->findOneBy([
            'id' => 1,
        ]);
        foreach ($products as $product) 
            $nameProduct = $product->name;
            $price = $product->price;
            $reference = $product->reference;
            if (!in_array($reference, $allref)) 
                $newProduct = new Product();
                $newProduct->setName($nameProduct);
                $newProduct->setPrice($price);
                $newProduct->setReference($reference);
                $newProduct->setGathering($gathering);
                $entityManager->persist($newProduct);
                $entityManager->flush();
            
        
//        return $this->render('product/test.html.twig', [
//
//        ]);
        return $this->json([
            'products' => $products,
            'name' => $name,
            'firstname' => $firstname,
            'company' => $company,
            'phone' => $phone,
            'email' => $email,
            'street' => $street,
            'number' => $number,
            'cpt' => $cpt,
            'postalCode' => $postalCode,
            'city' => $city,
            'country' => $country,
            'TVA' => $TVA,
        ]);
    

我看不出错误来自哪里，知道吗？

【参考方案1】：

因为您使用的是“application/json”内容类型，所以试试这个

         contentType: "application/json",
         dataType: 'json',
         data: JSON.stringify(quote),
         ....

或删除

 contentType: "application/json",

【讨论】：

确实，我正要删除我的问题。谢谢 ！那我就不说了:)

不客气！请不要忘记接受答案，因为它很有帮助。否则它将被否决。

是的，我想要，但我仍然需要等待。我当然会