SQL Server：按正确列的顺序匹配两个表和结果
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【中文标题】SQL Server：按正确列的顺序匹配两个表和结果【英文标题】：SQL Server: matching two tables and results in the order of proper column 【发布时间】：2019-02-27 13:46:02 【问题描述】：我有两张桌子JOB 和EMP；结构和值是这样的：
CREATE TABLE JOB
(
JOBID SMALLINT UNIQUE NOT NULL,
JOBNAME CHAR(15)
);
CREATE TABLE EMP
(
EMPID SMALLINT,
JOBID SMALLINT,
SAL SMALLINT,
CITYID SMALLINT,
YEAR SMALLINT,
STATUS CHAR(1)
);
INSERT INTO JOB(JOBID, JOBNAME)
VALUES (1, 'DEVELOPMENT'),
(2, 'DEVELOPMENT'),
(3, 'TESTING'),
(4, 'TESTING'),
(7, 'TESTING'),
(9, 'RESEARCH'),
(8, 'HR');
INSERT INTO EMP (EMPID , JOBID, SAL, CITYID, YEAR, STATUS)
VALUES (100, 1, 1000, 10, 2015, 'A'),
(200, 2, 2000, 10, 2015, 'A'),
(300, 1, 2500, 20, 2015, 'A'),
(400, 3, 1000, 10, 2016, 'A'),
(500, 6, 3000, 10, 2015, 'E'),
(600, 8, 1000, 30, 2015, 'A'),
(700, 8, 2000, 10, 2015, 'E'),
(800, 9, 1500, 10, 2015, 'A');
我想显示所有职位名称计数和平均工资；对于jobname，如果jobid不存在则显示0
对于给定的输入cityid、YEAR和STATUS（Emp表），为每个jobname（来自job表）取所有jobid并匹配Emp表，如果存在，则显示 count（Emp 表中的 jobid 计数）和 avgsal else 0 用于 count 和 avgsal。而Sal 是根据Status 计算出来的。如果Status 是'A' Sal 转到Status-A-Sal else Status-E-Sal。对于每个匹配的即非零记录，将“X”放在另一个字段中
Cityid 的 2015 年第 10 年和第 20 年的输出应如下所示。应首先显示 Status 'A' 和 Status 'E' 的结果。在结果中添加了状态类型字段。
Cityid Status-type jobname count STATUS sal
--------------------------------------------------------------
10 STATUSA development 2 X 1500
10 STATUSA TESTING 0 0
10 STATUSA RESEARCH 1 X 1500
10 STATUSA HR 0 0
10 total 3 0
10 STATUSE development 0 0
10 STATUSE TESTING 0 0
10 STATUSE RESEARCH 0 0
10 STATUSE HR 1 X 2000
10 total 1 2000
20 STATUSA development 1 X 2500
20 STATUSA TESTING 0 0
20 STATUSA RESEARCH 0 0
20 STATUSA HR 0 0
20 total 1 2500
20 STATUSE development 0 0
20 STATUSE TESTING 0 0
20 STATUSE RESEARCH 0 0
20 STATUSE HR 0 0
20 total 0 0
如何让结果一个接一个？
我试过这样，但它扔了
SELECT C.CITYID AS CITYID,
CASE WHEN P.STATUS ='A' THEN 'STATUSA' ELSE 'STATUSE' END AS STATUS_TYPE ,
COALESCE(J.JOBNAME, 'TOTAL') AS JOBNAME,
COUNT(CASE WHEN P.STATUS ='A' THEN P.CITYID END ) AS COUNT ,
COALESCE(AVG(CAST(CASE WHEN P.STATUS = 'A' THEN P.SAL END AS DECIMAL(13,2)))/12 , 0) AS "AVG SAL",
COUNT(CASE WHEN P.STATUS ='E' THEN P.CITYID END ) AS COUNT ,
COALESCE(AVG(CAST(CASE WHEN P.STATUS = 'E' THEN P.SAL END AS DECIMAL(13,2)))/12 , 0) AS "AVG SAL"
FROM JOB1 J
CROSS JOIN
(SELECT DISTINCT CITYID
FROM EMP1 B WHERE CITYID = 10
) C
LEFT JOIN EMP1 P ON P.JOBID = J.JOBID
AND P.CITYID = C.CITYID and
YEAR = 2015
GROUP BY ROLLUP(C.CITYID, J.JOBNAME );
错误： 列“EMP1.STATUS”在选择列表中无效，因为它既不包含在聚合函数中，也不包含在 GROUP BY 子句中。
【问题讨论】：
请分享您目前编写的查询和您面临的挑战，这样会很容易为您提供帮助。 添加了我有问题的查询 【参考方案1】：IF OBJECT_ID('tempdb..#JOB') IS NOT NULL
DROP TABLE #JOB
CREATE TABLE #JOB
(
JOBID SMALLINT UNIQUE NOT NULL,
JOBNAME CHAR(15)
);
IF OBJECT_ID('tempdb..#EMP') IS NOT NULL
DROP TABLE #EMP
CREATE TABLE #EMP
(
EMPID SMALLINT,
JOBID SMALLINT,
SAL SMALLINT,
CITYID SMALLINT,
YEAR SMALLINT,
STATUS CHAR(1)
);
INSERT INTO #JOB(JOBID, JOBNAME)
VALUES (1, 'DEVELOPMENT'),
(2, 'DEVELOPMENT'),
(3, 'TESTING'),
(4, 'TESTING'),
(7, 'TESTING'),
(9, 'RESEARCH'),
(8, 'HR');
INSERT INTO #EMP (EMPID , JOBID, SAL, CITYID, YEAR, STATUS)
VALUES (100, 1, 1000, 10, 2015, 'A'),
(200, 2, 2000, 10, 2015, 'A'),
(300, 1, 2500, 20, 2015, 'A'),
(400, 3, 1000, 10, 2016, 'A'),
(500, 6, 3000, 10, 2015, 'E'),
(600, 8, 1000, 30, 2015, 'A'),
(700, 8, 2000, 10, 2015, 'E'),
(800, 9, 1500, 10, 2015, 'A');
;with cteJobDict as (
select
distinct
j.JOBNAME
from
#JOB j
)
,cteStatusDict as(
select
distinct STATUS
from
#EMP e
),cteCityDict as (
select
distinct CITYID
from
#EMP
)
,cteJobStatusCityMatrix as(
select
*
from
cteJobDict
cross apply cteStatusDict
cross apply cteCityDict
)
,cteEmpWithJobName as (
select
e.*
,j.JOBNAME
from
#EMP e
join #JOB j on j.JOBID=e.JOBID
), cteData as (
SELECT
m.CITYID
,CASE WHEN m.STATUS ='A' THEN 'STATUSA' ELSE 'STATUSE' end as [Status-type]
,CASE WHEN m.STATUS ='A' THEN 1 ELSE 3 end as [Status-order]
,m.JOBNAME
,count(distinct e.EMPID) count
,iif(count(distinct e.EMPID)>0,'X','') status
,isnull(avg(e.sal),0) sal
FROM
cteJobStatusCityMatrix m
left join cteEmpWithJobName e on e.CITYID=m.CITYID and e.STATUS=m.STATUS and e.JOBNAME=m.JOBNAME and e.YEAR=2015
where
m.CITYID in (10,20)
group by
m.CITYID
,m.STATUS
,m.JOBNAME
union
SELECT
m.CITYID
,'total' as [Status-type]
,CASE WHEN m.STATUS ='A' THEN 2 ELSE 4 end as [Status-order]
,null
,count(distinct e.EMPID) count
,iif(count(distinct e.EMPID)>0,'X','') status
,isnull(avg(e.sal),0) sal
FROM
cteJobStatusCityMatrix m
left join cteEmpWithJobName e
on e.CITYID=m.CITYID
and e.STATUS=m.STATUS
and e.JOBNAME=m.JOBNAME
and e.YEAR=2015 -- here goes year
where
m.CITYID in (10,20) -- here goes cityid
group by
m.CITYID
,m.STATUS)
select
CITYID
,[Status-type]
,JOBNAME
,count
,status
,sal
from
cteData
order by
CITYID
,[Status-order]
【讨论】：
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