如何使用 Listview 访问多个 JSONArray？

Posted 2023-05-07

【中文标题】如何使用 Listview 访问多个 JSONArray？

【英文标题】：How to access Multiple JSONArrays with Listview?

【发布时间】：2016-03-14 07:16:07

【问题描述】：

我有两个Listview，我从服务器收到两个JSONArray，我收到以下响应

[
    [
        
            "user_status": "1",
            "pooja_name": "Festival Sevas",
            "sess_date": "Mon Nov 30 2015",
            "session_status": "Completed",
            "message": "What ever message you want"
        
    ],
    [
        
            "user_status": "1",
            "pooja_name": "Pushpalankara Seva",
            "sess_date": "Tue Dec 15 2015",
            "session_status": "Pending",
            "message": "What ever message you want"
        
    ]
]

我能够解析这两个数组，但在我的两个 listview 中都显示 Pushpalankara Seva，我正在尝试在我的第一个列表视图中显示 Pushpalankara Seva 和第二个 Festival Sevas

class LoadPoojas extends AsyncTask<String, String, ArrayList<HashMap<String,String>>> 
        /**
         * Before starting background thread Show Progress Dialog
         * */
        @Override
        protected void onPreExecute() 
            super.onPreExecute();
            pDialog = new ProgressDialog(AboutUsFragment.this.getActivity());
            pDialog.setMessage("Loading...");
            pDialog.setIndeterminate(true);
            pDialog.setIndeterminateDrawable(getResources().getDrawable(R.drawable.custom_progress));
            pDialog.setCancelable(false);
            pDialog.show();
        
        protected ArrayList<HashMap<String,String>> doInBackground(String... args) 
            ServiceHandler sh = new ServiceHandler();
            // Making a request to url and getting response
            ArrayList<HashMap<String,String>> data = new ArrayList<HashMap<String, String>>();
            ArrayList<HashMap<String,String>> upcomingdata = new ArrayList<HashMap<String, String>>();
            String jsonStr = sh.makeServiceCall(POOJA_LISTING_URL, ServiceHandler.GET);
            map = new HashMap<String, String>();
            Log.d("Response: ", "> " + jsonStr);

            if (jsonStr != null) 
                try 
                    JSONArray jsonObj = new JSONArray(jsonStr);

                    // Getting JSON Array node

                    JSONArray pastarray = jsonObj.getJSONArray(0);
                    for (int i = 0; i < pastarray.length(); i++) 
                        JSONObject c = pastarray.getJSONObject(i);
                        // creating new HashMap

                        // adding each child node to HashMap key => value
                        map.put(POOJA_LISTING_NAME, c.getString(POOJA_LISTING_NAME));


                    


                    JSONArray upcoming = jsonObj.getJSONArray(1);
                    for (int i = 0; i < upcoming.length(); i++) 
                        JSONObject c = upcoming.getJSONObject(i);
                        // creating new HashMap
                      //  HashMap<String, String> upcomingmap = new HashMap<String, String>();
                        // adding each child node to HashMap key => value
                        map.put(POOJA_LISTING_NAME, c.getString(POOJA_LISTING_NAME));



                    
                    data.add(map);
                 catch (JSONException e) 
                    e.printStackTrace();
                
             else 
                Log.e("ServiceHandler", "Couldn't get any data from the url");
            
            return data;
        
        protected void onPostExecute(ArrayList<HashMap<String,String>> result) 
            super.onPostExecute(result);
            /*if(interestaccept == null || interestaccept.length() == 0)
                // Toast.makeText(getApplicationContext(), "No response", Toast.LENGTH_SHORT).show();
                noacpt.setText("  No Accepted List  ");
            
            else
            
                noacpt.setVisibility(View.INVISIBLE);
            */
            // dismiss the dialog after getting all albums
            if (pDialog.isShowing())
                pDialog.dismiss();
            // updating UI from Background Thread

            aList = new ArrayList<HashMap<String, String>>();
            aList.addAll(result);
            adapter = new CustomAdapterPooja(getActivity(),result);
            completedpooja.setAdapter(adapter);
            adapterupcoming = new CustomAdapterPoojaUpcoming(getActivity(),result);
            notcompletedpooja.setAdapter(adapterupcoming);
            adapter.notifyDataSetChanged();
            adapterupcoming.notifyDataSetChanged();



            completedpooja.setOnItemClickListener(new AdapterView.OnItemClickListener() 
                @Override
                public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) 


                
            );


           /* upcomingaList = new ArrayList<HashMap<String, String>>();
            upcomingaList.addAll(result);
            adapterupcoming = new CustomAdapterPoojaUpcoming(getActivity(),result);
            notcompletedpooja.setAdapter(adapterupcoming);

            adapterupcoming.notifyDataSetChanged();

            notcompletedpooja.setOnItemClickListener(new AdapterView.OnItemClickListener() 
                @Override
                public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) 


                
            );*/

        

    

【参考方案1】：

我检查了您的代码，发现您在两个数组（在两个 For 循环内）中的 hashmap with same key 中确实出错了。所以它会按照 hashmap 的规则用最新的值覆盖。

解决方案：

选项1：获取hashmap的arraylist并为每个新记录创建新的hashmap。

选项2：取POJO类的arraylist。

编辑：

public class UserPOJO 


    public String user_status;
    public String pooja_name;
    public String sess_date;
    public String session_status;
    public String message;

获取 POJO 类的数组列表，如下所示

public ArrayList<UserPOJO> userPOJOs = new ArrayList<UserPOJO>();

现在从 JSONArray 向数组列表中插入数据。

【讨论】：

需要创建anther arraylist？？

如果我需要没有 pojo 怎么办

在for循环中每次创建map对象，并在for循环的最后一点添加到hashmap的arraylist中。

data.add(map);在最后一行的 for 循环中。

让我们continue this discussion in chat。