未从 main.cpp C++ 调用 C 函数
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【中文标题】未从 main.cpp C++ 调用 C 函数【英文标题】:C function not called from main.cpp C++ 【发布时间】:2017-08-17 13:26:33 【问题描述】:extern "C"
#include "CLAHE.h"
#include "opencv2/opencv.hpp" // opencv general include file
#include "opencv2/highgui/highgui.hpp" // opencv GUI include file
using namespace cv;
#include <vector>
#include "stdlib.h"
#include <QDebug>
#define WIDTH 704
#define HEIGHT 576
int main(int argc, int * argv[])
int width = 0, height = 0;
unsigned char * cbuf, *obuf;
Mat gray;
Mat img = imread("path/to/image", CV_LOAD_IMAGE_ANYCOLOR | CV_LOAD_IMAGE_ANYDEPTH);
cvtColor(img, gray, CV_BGR2GRAY);
width = gray.cols; height = gray.rows;
qDebug() << "Width = " << width << ", Height = " << height;
CLAHE_OBJ *obj = new CLAHE_OBJ;
init_clahe(obj, width, height, 64, 64, 256, 0, 255);
return 0;
CLAHE.h 具有 CLAHE_OBJ 结构:
typedef struct CLAHE_OBJ
int *m_blocks_histogram;
int *m_blocks_he_map;
int m_image_width;
int m_image_height;
int m_image_pixels;
int m_window_size_wd;
int m_window_size_ht;
int m_window_pixels;
int m_width_blocks_num;
int m_height_blocks_num;
int m_blocks_num;
//optional
int m_grayscale_levels; //Default: 256, Max: 256
int *m_map_to_histogram_bins;
int m_input_min_pixel_value;
int m_input_max_pixel_value;
CLAHE_OBJ;
int init_clahe(CLAHE_OBJ *clahe_obj, int frame_width, int frame_height,
int window_size_width, int window_size_height,
int grayscale_levels, int min_pixel_value, int max_pixel_value)
printf("Break point 1\n");
if(frame_width <= 0 || frame_height <= 0)
printf("Frame width and height must be greater that 0.");
return -1;
printf("Break point 2\n");
if(grayscale_levels == 0)
printf("Number of grayscale values must be greater than 0.");
return -1;
if(frame_width % window_size_width > 0 ||
frame_height % window_size_height > 0)
printf("Set window size (width, height) such that the frame can be divided"
" into equal sized blocks,i.e., "
"frame_width % window_size_width == 0;frame_height % window_size_height > 0;");
return -1;
printf("Break point 3\n");
clahe_obj->m_image_width = frame_width;
clahe_obj->m_image_height = frame_height;
clahe_obj->m_image_pixels = frame_width * frame_height;
clahe_obj->m_window_size_wd = window_size_width;
clahe_obj->m_window_size_ht = window_size_height;
clahe_obj->m_window_pixels = window_size_height * window_size_width;
if((clahe_obj->m_width_blocks_num = frame_width / window_size_width) < 2 ||
(clahe_obj->m_height_blocks_num = frame_height / window_size_height) < 2)
printf("Number of blocks that the frame can be divide into must be greater than 4, i.e.,"
"frame_width / window_size_width >= 2;frame_height / window_size_height >= 2;");
return -1;
printf("Break point 4\n");
clahe_obj->m_blocks_num = clahe_obj->m_width_blocks_num * clahe_obj->m_height_blocks_num;
if(clahe_obj->m_blocks_num > 256)
printf("Number of blocks that the frame can be divide into must be lesser than 256.");
return -1;
clahe_obj->m_grayscale_levels = (grayscale_levels >= 256) ? 256 : grayscale_levels;
map_to_histogram_bins(clahe_obj, min_pixel_value, max_pixel_value);
clahe_obj->m_blocks_histogram = (int*)malloc(clahe_obj->m_blocks_num *
clahe_obj->m_grayscale_levels *
sizeof(int));
if(!clahe_obj->m_blocks_histogram)
printf("Unable to allocate memory for histograms for each block");
return -1;
memset(clahe_obj->m_blocks_histogram, 0, clahe_obj->m_blocks_num *
clahe_obj->m_grayscale_levels * sizeof(int));
printf("Break point 5\n");
clahe_obj->m_blocks_he_map = (int*)malloc(clahe_obj->m_blocks_num *
clahe_obj->m_grayscale_levels *
sizeof(int));
if(!clahe_obj->m_blocks_he_map)
printf("Unable to allocate memory for equalized histograms for each block");
return -1;
printf("Break point 6\n");
return 0;
使用“imread”读取输入图像后程序立即崩溃。 'init_clahe' 永远不会被调用,即 printf("Break Point ..") 永远不会被执行。我无法弄清楚出了什么问题。我什至尝试过使用 malloc 而不是 new,但问题仍然存在。
请帮忙。
编辑#1: qDebug() 语句被执行。我确实得到了正确的宽度和高度值。
【问题讨论】:
'程序在读取输入图像后立即崩溃' - 它读取了吗? 'imread()' 如何标记错误?它是否引发异常,('因为我看不到任何捕获处理程序?) 您不能使用调试器来指示崩溃的位置(以及原因)吗?int main(int argc, int * argv[])
导致未定义的行为(假设是托管环境)。
我应该将 int main() 改为 void main() 吗?
@Scheff 你打错字了,假设你的意思是char **argv
或char *argv[]
。
【参考方案1】:
您似乎正在将您的应用程序与第三方库链接。只需确保您对它们都使用相同的运行时库,而不是混合发布和调试运行时库。
【讨论】:
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