如何使用改造和 gson 异步解析 json

Posted 2023-04-19

【中文标题】如何使用改造和 gson 异步解析 json

【英文标题】：How to parse json with retrofit and gson asynchronously

【发布时间】：2016-08-23 10:45:35

【问题描述】：

我有 1 个请求，可以得到 2 个不同的响应：

登录名和密码正确时：

    "token": "token..",
    "expires": "2016-04-28T10:46:36+0000"

错误时：

    "error": 
        "id": "0123456789",
        "code": 401,
        "message": "invalid credentials"
    

虽然更正它解析成功，但是当我得到错误的响应（错误的登录名或密码）时，它返回 null（未解析）。

Error.java

public class Error 
    @SerializedName("id")
    @Expose
    public String id;
    @SerializedName("code")
    @Expose
    public int code;
    @SerializedName("message")
    @Expose
    public String message;

    public Error() 

    public Error(String id, int code, String message) 
        this.id = id;
        this.code = code;
        this.message = message;
    

Auth.java

public class Auth 
    @SerializedName("token")
    @Expose
    public String token;

    @SerializedName("expires")
    @Expose
    public String expires;

    @SerializedName("error")
    @Expose
    public Error error;

    public Auth(String token, String expires, Error error) 
        this.token = token;
        this.expires = expires;
        this.error = error;
    

    public Auth() 
        error = new Error();
    

ApiRequests.java

public interface ApiRequests 
    @FormUrlEncoded
    @POST("auth/token")
    Call<Auth> auth(@Field("login") String login, @Field("password") String password);

Api.java

Gson gson = new GsonBuilder()
        .setDateFormat(DATE_FORMAT)
        .create();

Retrofit retrofit = new Retrofit.Builder()
        .baseUrl(URL_MAIN)
        .addConverterFactory(GsonConverterFactory.create(gson))
        .build();

ApiRequests service = retrofit.create(ApiRequests.class);
Call<Auth> call = service.auth("login", "password");

call.enqueue(new Callback<Auth>() 
    @Override
    public void onResponse(Call<Auth> call, Response<Auth> response) 
        Auth responseBody = response.body(); // null when login/password are wrong
    

    @Override
    public void onFailure(Call<Auth> call, Throwable t) 

    
);

build.gradle

dependencies 
    compile 'com.squareup.retrofit2:retrofit:2.0.2'
    compile 'com.squareup.retrofit2:converter-gson:2.0.2'
    compile 'com.google.code.gson:gson:2.6.2'

【参考方案1】：

Auth.java

public class Auth implements Serializable 

    private String token;
    private String expires;
    private Error error;

    //Implements getters and setters

错误.java

public class Error implements Serializable 

    private String id;
    private int code;
    private String message;

    //Implements getters and setters

API.java

call.enqueue(new Callback<Auth>() 
    @Override
    public void onResponse(Call<Auth> call, Response<Auth> response) 
        if(response.code() == 401)
            //failure
            Log.e("Error", response.body().getError().getMessage());
         else
            //success
            Log.e("Success", response.body().getToken());
        
    

    @Override
    public void onFailure(Call<Auth> call, Throwable t) 

    
);

【讨论】：

在“onResponse()”方法“response.body() = null”中添加了“实现可序列化”。 “response.code() = 401”，为什么不是 200？我在“www.hurl.it”上检查了它，服务器返回 JSON 和代码 401

检查您的API，但它意味着身份验证失败