显示2个不同实体表的数据表需要从数据库表中获取另一列值
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【中文标题】显示2个不同实体表的数据表需要从数据库表中获取另一列值【英文标题】：Datatable displaying 2 different entity tables with relation need to get the another column values from database table 【发布时间】：2016-07-08 20:24:17 【问题描述】：我需要从 UI jsf 的单个数据表中的 LangDef 实体类中获取语言名称的列值。请让我尽快
<p:dataTable id="dataTable" emptyMessage="#res.NO_RECORDS_FOUND" var="lab" value="#labelsMB.listData" editable="true" editMode="cell" paginator="true" rows="10" paginatorTemplate=" FirstPageLink PreviousPageLink PageLinks NextPageLink LastPageLink RowsPerPageDropdown" rowsPerPageTemplate="5,10,15">
<p:column headerText="#res.CAPTION_DET" sortBy="#lab.captionDet" filterBy="#lab.captionDet" filterMatchMode="contains" filterStyle="width: 360px;">
<p:cellEditor>
<f:facet name="output">
<h:outputText value="#lab.captionDet" />
</f:facet>
<f:facet name="input">
<h:inputText value="#lab.captionDet" style="width:96%"/>
</f:facet>
</p:cellEditor>
</p:column>
<p:column headerText="#res.LABEL_NO" sortBy="#lab.iasLabelsPK.labelNo" filterBy="#lab.iasLabelsPK.labelNo">
<p:outputLabel value="#lab.iasLabelsPK.labelNo" />
</p:column>
<p:column headerText="#res.LANGUAGE_NO" sortBy="#lab.iasLabelsPK.langNo" filterBy="#lab.iasLabelsPK.langNo" >
<p:outputLabel value="#lab.iasLabelsPK.langNo" />
</p:column>
<p:column headerText="#res.LANGUAGE_NAME" sortBy="#lab.???????" filterBy="#lab.?????" >
<p:outputLabel value="#lab...?????" />
</p:column>
</p:dataTable>
IAS_LABELS DAO 实体：
public interface ILabelsDAO extends CrudRepository<IasLabels, IasLabelsPK>
@Query List<IasLabels> findAll();
LabelService 服务类
@Service
@Transactional
public class LabelService
static Logger logger = Logger.getLogger(LabelService.class);
@Autowired
private ILabelsDAO labelRepo;
public ILabelsDAO getLabelRepo()
return labelRepo;
public void setLabelRepo(ILabelsDAO labelRepo)
this.labelRepo = labelRepo;
public List<IasLabels> getAllLabels()
if (this.getLabelRepo() != null)
return this.getLabelRepo().findAll();
return null;
public Iterable<IasLabels> saveData(List<IasLabels> originalValue)
return labelRepo.save(originalValue);
LabelsMB ManagedBean 实施
@ManagedBean
@SessionScoped
public class LabelsMB
static Logger logger = Logger.getLogger(LabelsMB.class);
List<IasLabels> labelsList = null;
@ManagedProperty(value = "#labelService")
private LabelService labelService;
public LabelService getLabelService()
return labelService;
public void setLabelService(LabelService labelService)
this.labelService = labelService;
public List<IasLabels> getListData()
if (labelsList == null || labelsList.isEmpty())
if (this.getLabelService() != null)
labelsList = this.getLabelService().getAllLabels();
return labelsList;
LangDef 实体类
@Entity
@Table(name = "LANG_DEF")
@XmlRootElement
@NamedQueries(
@NamedQuery(name = "LangDef.findAll", query = "SELECT l FROM LangDef l"),
@NamedQuery(name = "LangDef.findByLangNo", query = "SELECT l FROM LangDef l WHERE l.langNo = :langNo"),
@NamedQuery(name = "LangDef.findByLangName", query = "SELECT l FROM LangDef l WHERE l.langName = :langName"),
@NamedQuery(name = "LangDef.findByRepExt", query = "SELECT l FROM LangDef l WHERE l.repExt = :repExt"),
@NamedQuery(name = "LangDef.findByLangDflt", query = "SELECT l FROM LangDef l WHERE l.langDflt = :langDflt"),
@NamedQuery(name = "LangDef.findByLangDir", query = "SELECT l FROM LangDef l WHERE l.langDir = :langDir"),
@NamedQuery(name = "LangDef.findByFlgSt", query = "SELECT l FROM LangDef l WHERE l.flgSt = :flgSt"),
@NamedQuery(name = "LangDef.findByLangExt", query = "SELECT l FROM LangDef l WHERE l.langExt = :langExt"))
public class LangDef implements Serializable
private static final long serialVersionUID = 1L;
@Id
@Basic(optional = false)
@NotNull
@Column(name = "LANG_NO")
private Short langNo;
@Size(max = 60)
@Column(name = "LANG_NAME")
private String langName;
@Size(max = 10)
@Column(name = "REP_EXT")
private String repExt;
@Column(name = "LANG_DFLT")
private Short langDflt;
@Column(name = "LANG_DIR")
private Short langDir;
@Column(name = "FLG_ST")
private Short flgSt;
@Size(max = 10)
@Column(name = "LANG_EXT")
private String langExt;
public LangDef()
public LangDef(Short langNo)
this.langNo = langNo;
public Short getLangNo()
return langNo;
public void setLangNo(Short langNo)
this.langNo = langNo;
public String getLangName()
return langName;
public void setLangName(String langName)
this.langName = langName;
我需要从 UI jsf 的单个数据表中的 LangDef 实体类中获取语言名称的列值。请让我尽快
【问题讨论】：
您需要将 List你只需要像下面这样改变你的代码
在 xhtml 中：
<p:column headerText="#res.LANGUAGE_NAME" sortBy="#lab.langDef.langName" filterBy="#lab.langDef.langName" >
<p:outputLabel value="#lab.langDef.langName" />
</p:column>
实体IasLabels：
@Entity
@Table(name = "LAS_LABELS")
public class IasLabels implements Serializable
private LangDef langDef;
@OneToOne(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
@JoinColumn(name = "LANG_NO", nullable = false)
public LangDef getLangDef()
return this.langDef;
public void setLangDef(LangDef langDef)
this.langDef = langDef;
希望对你有所帮助..
已编辑：
你需要在你的spring配置文件中添加以下内容
@Autowired
SessionFactory sessionFactory;
@Override
public void addInterceptors(InterceptorRegistry registry)
registry.addWebRequestInterceptor(openSessionInViewInterceptor());
@Bean
public OpenSessionInViewInterceptor openSessionInViewInterceptor()
OpenSessionInViewInterceptor openSessionInterceptor = new OpenSessionInViewInterceptor();
openSessionInterceptor.setSessionFactory(sessionFactory);
return openSessionInterceptor;
【讨论】：
运行我的项目时出现此错误...HTTP 状态 500 - 无法提取 ResultSet； SQL [不适用]；嵌套异常是 org.hibernate.exception.SQLGrammarException: could not extract ResultSet 你需要从代码中移除 fetch = FetchType.LAZY 并尝试一下 在做之后...得到相同的异常无法提取结果集； SQL [不适用]；嵌套异常是 org.hibernate.exception.SQLGrammarException: could not extract ResultSet 我想你忘了在你的配置中写这行请看我的编辑答案 因为它对我有用，我在单个表中得到了结果以上是关于显示2个不同实体表的数据表需要从数据库表中获取另一列值的主要内容，如果未能解决你的问题，请参考以下文章