如何在 Spark Scala 中读取带有根元素的多行 json?
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【中文标题】如何在 Spark Scala 中读取带有根元素的多行 json?【英文标题】:How to read multiline json with root element in Spark Scala? 【发布时间】:2018-12-12 19:18:02 【问题描述】:这是一个示例 JSON 文件。我一般都想这样做,比如如果我有根标签,那么如何将 JSON 数据读入 Dataframe 并在控制台中打印。
"Crimes": [
"ID": 11034701,
"Case Number": "JA366925",
"Date": "01/01/2001 11:00:00 AM",
"Block": "016XX E 86TH PL",
"IUCR": "1153",
"Primary Type": "DECEPTIVE PRACTICE",
"Description": "FINANCIAL IDENTITY THEFT OVER $ 300",
"Location Description": "RESIDENCE",
"Arrest": false,
"Domestic": false,
"Beat": 412,
"District": 4,
"Ward": 8,
"Community Area": 45,
"FBI Code": "11",
"Year": 2001,
"Updated On": "08/05/2017 03:50:08 PM"
,
"ID": 11162428,
"Case Number": "JA529032",
"Date": "11/28/2017 09:43:00 PM",
"Block": "026XX S CALIFORNIA BLVD",
"IUCR": "5131",
"Primary Type": "OTHER OFFENSE",
"Description": "VIOLENT OFFENDER: ANNUAL REGISTRATION",
"Location Description": "JAIL / LOCK-UP FACILITY",
"Arrest": true,
"Domestic": false,
"Beat": 1034,
"District": 10,
"Ward": 12,
"Community Area": 30,
"FBI Code": "26",
"X Coordinate": 1158280,
"Y Coordinate": 1886310,
"Year": 2017,
"Updated On": "02/11/2018 03:54:58 PM",
"Latitude": 41.843778126,
"Longitude": -87.694637678,
"Location": "(41.843778126, -87.694637678)"
,
"ID": 4080525,
"Case Number": "HL425503",
"Date": "06/16/2005 09:40:00 PM",
"Block": "062XX N KIRKWOOD AVE",
"IUCR": "1365",
"Primary Type": "CRIMINAL TRESPASS",
"Description": "TO RESIDENCE",
"Location Description": "RESIDENCE",
"Arrest": false,
"Domestic": false,
"Beat": 1711,
"District": 17,
"Ward": 39,
"Community Area": 12,
"FBI Code": "26",
"X Coordinate": 1145575,
"Y Coordinate": 1941395,
"Year": 2005,
"Updated On": "02/28/2018 03:56:25 PM",
"Latitude": 41.99518667,
"Longitude": -87.739863972,
"Location": "(41.99518667, -87.739863972)"
,
"ID": 4080539,
"Case Number": "HL422433",
"Date": "06/15/2005 12:55:00 PM",
"Block": "042XX S ST LAWRENCE AVE",
"IUCR": "0460",
"Primary Type": "BATTERY",
"Description": "SIMPLE",
"Location Description": "SCHOOL, PUBLIC BUILDING",
"Arrest": false,
"Domestic": false,
"Beat": 213,
"District": 2,
"Ward": 4,
"Community Area": 38,
"FBI Code": "08B",
"X Coordinate": 1180964,
"Y Coordinate": 1877123,
"Year": 2005,
"Updated On": "02/28/2018 03:56:25 PM",
"Latitude": 41.818075262,
"Longitude": -87.611675899,
"Location": "(41.818075262, -87.611675899)"
]
我正在使用此代码。
val conf = new SparkConf().setAppName("demo").setMaster("local");
val sc = new SparkContext(conf);
val spark = SparkSession.builder().master("local").appName("ValidationFrameWork").getOrCreate()
val sqlContext = new SQLContext(sc)
sc.hadoopConfiguration.set("mapreduce.fileoutputcommitter.marksuccessfuljobs", "false")
sc.hadoopConfiguration.set("parquet.enable.summary-metadata", "false")
val jsonRDD = sc.wholeTextFiles("D:/FinalScripts/output/Crimes1.json").map(x=>x._2)
val namesJson = sqlContext.read.json(jsonRDD)
namesJson.printSchema
namesJson.registerTempTable("JSONdata")
val data=sqlContext.sql("select * from JSONdata")
data.show()
对于此代码,我将一列视为犯罪,并且在一行中完整的数据即将到来。如何忽略根元素并仅获取原始数据。
我什至如何将嵌套的 JSON 读入 Dataframe 并在控制台本身中打印。
【问题讨论】:
你想得到"Crimes"
的数组作为输出DataFrame中的行吗?
【参考方案1】:
试试看:
import org.apache.spark.sql.functions._
ds.select(explode($"Crimes") as "exploded").select("exploded.*")
其中 ds
是您从 JSON 记录创建的 Dataset<Row>
。
请注意,如果您的数据量很大,Spark 将需要将整个数据保存在内存中,然后再将其展平。
【讨论】:
好的,先生。仅对于此代码,它对我来说工作正常。 :) 非常感谢!以上是关于如何在 Spark Scala 中读取带有根元素的多行 json?的主要内容,如果未能解决你的问题,请参考以下文章
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