Javascript：自动将数字转换为前缀

Posted 2023-04-13

【中文标题】Javascript：自动将数字转换为前缀

【英文标题】：Javascript: Auto Converting numbers to prefixes

【发布时间】：2016-01-15 05:09:38

【问题描述】：

我正在创建一个空闲游戏（Cookie Clicker 等），似乎当我的玩家达到高点击量时，游戏开始变慢。 高数字也不适合游戏，因为它占用了太多空间。那么是否有一个脚本可以将每个数字转换为prefix？

例子：

10 = 10

10000000 变成 100 万。

1,000,000,000 变成 10 亿

1,000,000,000,000 变成 1 万亿

1.4 万亿就是 1400000000000000 它与this 非常相似。

Cookie Clicker 和 swarm 模拟器具有我正在寻找的功能。

编辑：谢谢，Drew Quick！

对于那些感兴趣的人：

var count = 1;

function main() 
  count += 1000;
  
var str = count.toString();
var tmpCount = '';
if (count < 1000000) 
    tmpCount = "";
 else if (count > 1000000 && count < 1000000000) 
    str = "Million";
    tmpCount = (count / 1000000).toFixed(2);
 else if (count > 1000000000 && count < 1000000000000) 
    str = "Billion";
    tmpCount = (count / 1000000000).toFixed(2);
 else if (count > 1000000000000 && count < 1000000000000000) 
    str = "Trillion";
    tmpCount = (count / 1000000000000).toFixed(2);
 else if (count > 1000000000000000 && count < 1000000000000000000) 
str = "Quadrillion";
    tmpCount = (count / 1000000000000000).toFixed(2);
     else if (count > 1000000000000000000 && count < 1000000000000000000000) 
    str = "Quintillion";
    tmpCount = (count / 1000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000 && count < 1000000000000000000000000) 
    str = "Sextillion";
    tmpCount = (count / 1000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000 && count < 1000000000000000000000000000) 
    str = "Septillion";
    tmpCount = (count / 1000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000 && count < 1000000000000000000000000000000) 
    str = "Octillion";
    tmpCount = (count / 1000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000 && count < 1000000000000000000000000000000000) 
    str = "Nonillion";
    tmpCount = (count / 1000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000 && count < 1000000000000000000000000000000000000) 
    str = "Decillion";
    tmpCount = (count / 1000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000) 
    str = "Undecillion";
    tmpCount = (count / 1000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000) 
    str = "Duodecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000) 
    str = "Tredecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000) 
    str = "Quattuordecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000000) 
    str = "Quindecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000000000) 
    str = "Sexdecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000000000000) 
    str = "Septendecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000000000000000) 
    str = "Octodecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000000000000000 && count < 1000000000000000000000000000000000000000000000000000000000000000) 
    str = "Novemdecillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 1000000000000000000000000000000000000000000000000000000000000000 && count < 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) 
    str = "Vigintillion";
    tmpCount = (count / 1000000000000000000000000000000000000000000000000000000000000000).toFixed(2);
 else if (count > 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 && count) 
    str = "Googol";
    tmpCount = (count / 10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000).toFixed(2);



  document.getElementById("count").innerText = tmpCount + ' ' + str;
  setTimeout(function() 
    main();
  , 1);


main();

<span id="count">test</span>

希望对你有帮助！！

【问题讨论】：

这些可怜的人要点击多少次？

有一些自动点击升级。我会说高达一万亿左右。

1,000,000,000 becomes 1 billion. ... 1,000,000,001 会变成什么？

我数学不好，可以是 1.000000001，也可以是科学计数法。但我更喜欢它是短期的。 (onlineconversion.com/large_numbers.htm) 也可以四舍五入。

【参考方案1】：

How can I convert numbers into scientific notation?

var clicks = 100000000000000000000000;
alert(clicks.toExponential());

编辑：像这样简单直接的东西怎么样？顺便说一句，这很粗糙。只是为了传达这个想法。

var count = 1;

function main() 
  count += 1000;

  var str = count.toString();
  var tmpCount;
  if (count < 1000000) 
    tmpCount = "";
   else if (count > 1000000 && count < 1000000000) 
    str = "million";
    tmpCount = (count / 1000000).toFixed(2);
   else if (count > 1000000000 && count < 1000000000000) 
    str = "billion";
    tmpCount = (count / 1000000000).toFixed(2);
  

  document.getElementById("count").innerText = tmpCount + ' ' + str;
  setTimeout(function() 
    main();
  , 1);


main();

<span id="count">test</span>

【讨论】：

谢谢，虽然我不希望它采用科学计数法！如果没有其他选项可供我使用，我将使用它。

谢谢！这正是我要找的！