如何创建 SQL 运算符组合,如 ALL IN,NOT ALL IN
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【中文标题】如何创建 SQL 运算符组合,如 ALL IN,NOT ALL IN【英文标题】:How to create SQL Operators Combination like ALL IN, NOT ALL IN 【发布时间】:2011-05-16 03:18:28 【问题描述】:我在 Filter 类中有以下 4 个属性。我将解析以下 4 个属性到 StoredProcedure 并获得过滤后的结果。
/// <summary>
/// Gets and sets comma seperated condition ids.
/// Patients must have all these conditions in order to satisfy the filter.
/// </summary>
public string MustHaveAllConditions get; set;
/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must not have all of these conditions in order to satisfy the filter.
/// </summary>
public string MustNotHaveAllConditions get; set;
/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must have at least one of these conditions in order to satisfy the filter.
/// </summary>
public string MustHaveAtLeastOneCondition get; set;
/// <summary>
/// Gets and sets comma separated condition ids.
/// Patients must not have at least one of these conditions in order to satisfy the filter.
/// </summary>
public string MustNotHaveAtLeastOneCondition get; set;
我的存储过程将有四个参数,如下所示。 例如:
@*MustHaveAll*Conditions = "1,2"
@*MustNotHaveAll*Conditions = "3,4"
@*MustHaveAtLeastOne*Condition = "5,6,7,8"
@*MustNotHaveAtLeastOne*Condition = "9, 10"
我正在使用一个 UDF,它返回一个带有 Ids 列的表。
我的问题:
基本上我可以使用 SQL“IN”运算符来查找具有至少一个 Condition 的患者(即:@MustHaveAtLeastOneCondition)和“NOT IN”运算符组合来过滤 @MustNotHaveAnyConditions。
是否有任何 SQL 运算符(或其他方法)来过滤 MustHaveAllConditions、MustNotHaveAllConditions 参数?
【问题讨论】:
【参考方案1】:-- Patients
declare @Patient table (PatientID int)
-- Conditions per patient
declare @PatientCondition table (PatientID int, ConditionID int)
-- Conditions table generated from param string
declare @Condition table (ConditionID int)
-- Test data
insert into @Patient
select 1 union all
select 2 union all
select 3
insert into @PatientCondition
select 1, 1 union all
select 1, 2 union all
select 1, 3 union all
select 2, 1 union all
select 3, 3
insert into @Condition
select 1 union all
select 2
-- MustHaveAll
select *
from @Patient as P
where P.PatientID in
(
select PC.PatientID
from @PatientCondition as PC
inner join @Condition as C
on PC.ConditionID = C.ConditionID
group by PC.PatientID
having count(PC.ConditionID) = (select count(ConditionID) from @Condition)
)
--MustNotHaveAll
select *
from @Patient as P
where P.PatientID not in
(
select PC.PatientID
from @PatientCondition as PC
inner join @Condition as C
on PC.ConditionID = C.ConditionID
group by PC.PatientID
having count(PC.ConditionID) = (select count(ConditionID) from @Condition)
)
-- MustHaveAtLeastOne
select *
from @Patient as P
where P.PatientID in
(
select PC.PatientID
from @PatientCondition as PC
left outer join @Condition as C
on PC.ConditionID = C.ConditionID
where C.ConditionID is not null
)
--MustNotHaveAtLeastOne
select *
from @Patient as P
where P.PatientID not in
(
select PC.PatientID
from @PatientCondition as PC
left outer join @Condition as C
on PC.ConditionID = C.ConditionID
where C.ConditionID is not null
)
【讨论】:
这太棒了。如果我想在一个 sql 查询中合并这四个条件以获得最终的患者列表,你能告诉我最有效的方法吗? @CharithJ – 您可以将不同查询中的 where 子句添加到一个查询中,并用and
分隔。 where PatientID in (...) and PatientID in (...) and ...
等【参考方案2】:
确实没有一种简单的方法可以完成您所描述的操作。我会做的可能是把你的字符串拆分成一个表变量,然后使用右、左和内连接的组合从另一个表变量中删除结果,这是我的输出。
【讨论】:
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