修复在 Amazon Redshift 上计算 DAU 和 MAU 时的 MAU 问题

Posted 2023-03-31

【中文标题】修复在 Amazon Redshift 上计算 DAU 和 MAU 时的 MAU 问题

【英文标题】：Fix the MAU problem while calculating DAU and MAU on Amazon Redshift

【发布时间】：2018-12-18 18:40:34

【问题描述】：

我正在使用以下查询来计算 MAU 和 DAU，根据this 帖子：

WITH dau AS
(
  SELECT TRUNC(created_at) AS created_at,
         COUNT(DISTINCT member_id) AS dau
  FROM table ds
  WHERE ds.created_at BETWEEN '2018-09-03' AND '2018-09-08'
  GROUP BY TRUNC(created_at)
)
SELECT created_at,
       dau,
       (SELECT COUNT(DISTINCT member_id)
        FROM table ds
        WHERE ds.created_at BETWEEN created_at - 29*INTERVAL '1 day' AND created_at) AS mau
FROM dau
ORDER BY created_at

我尝试运行此查询并得到以下结果：

2018-09-03  12844   3976132
2018-09-04  54236   3976132
2018-09-05  58631   3976132
2018-09-06  59786   3976132
2018-09-07  52317   3976132
2018-09-08  4   3976132

可以清楚的看到MAU列有重复值。 我该如何解决？任何指针都会有所帮助。

【参考方案1】：

您应该为列名添加前缀：

WITH dau AS
(
  SELECT TRUNC(created_at) AS created_at,
         COUNT(DISTINCT member_id) AS dau
  FROM table ds
  WHERE ds.created_at BETWEEN '2018-09-03' AND '2018-09-08'
  GROUP BY TRUNC(created_at)
)
SELECT created_at,
       dau,
       (SELECT COUNT(DISTINCT member_id)
        FROM table ds
        WHERE ds.created_at 
          BETWEEN dau.created_at - 29*INTERVAL '1 day' AND dau.created_at) AS mau
          -- here
FROM dau
ORDER BY created_at

或：

SELECT TRUNC(created_at) AS created_at,
     COUNT(DISTINCT member_id) AS dau,
     COUNT(DISTINCT member_id) 
     FILTER(WHERE TRUNC(created_at)>=TRUNC(created_at)-29*INTERVAL '1 day') AS mau
FROM table ds
WHERE ds.created_at BETWEEN '2018-09-03' AND '2018-09-08'
GROUP BY TRUNC(created_at)
ORDER BY created_at

【讨论】：

这对我来说是一个非常愚蠢的错误。非常感谢您指出这一点:)。

@Patthebug 太好了。还请检查FILTER 子句是否返回相同的结果