调用存储过程时接收消息找不到对应的参数

Posted 2023-03-27

【中文标题】调用存储过程时接收消息找不到对应的参数

【英文标题】：Receiving Message Unable to locate the Corresponding Parameter when calling Stored Procedure

【发布时间】：2016-04-22 22:06:37

【问题描述】：

我一直在阅读以下 Spring 教程

http://www.tutorialspoint.com/spring/calling_stored_procedure.htm

一切正常，唯一的问题是我收到以下消息。

Apr 22, 2016 3:50:51 PM org.springframework.context.support.ClassPathXmlApplicationContext prepareRefresh
INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@5910e440: startup date [Fri Apr 22 15:50:51 MDT 2016]; root of context hierarchy
Apr 22, 2016 3:50:51 PM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
INFO: Loading XML bean definitions from class path resource [Beans.xml]
Apr 22, 2016 3:50:51 PM org.springframework.jdbc.datasource.DriverManagerDataSource setDriverClassName
INFO: Loaded JDBC driver: net.sourceforge.jtds.jdbc.Driver
----Listing Record with ID = 2 -----
Apr 22, 2016 3:50:52 PM org.springframework.jdbc.core.metadata.CallMetaDataContext matchInParameterValuesWithCallParameters
WARNING: Unable to locate the corresponding parameter value for 'outName' within the parameter values provided: [inID]
Apr 22, 2016 3:50:52 PM org.springframework.jdbc.core.metadata.CallMetaDataContext matchInParameterValuesWithCallParameters
WARNING: Unable to locate the corresponding parameter value for 'outAge' within the parameter values provided: [inID]
ID : 3, Name : Ayan, Age : 15

唯一的区别是我使用的是 MSSQL。如您所见，结果返回。我什至传入了一个不同的参数并且值发生了变化，所以我知道它正在工作。我只是不确定为什么我会收到这些消息。我已验证参数名称与类中的名称匹配。

package com.tutorialspoint;
import java.util.List;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import com.tutorialspoint.StudentJDBCTemplate;

public class MainApp 
   public static void main(String[] args) 
      ApplicationContext context = 
             new ClassPathXmlApplicationContext("Beans.xml");
      
      
      StudentJDBCTemplate studentJDBCTemplate = 
      (StudentJDBCTemplate)context.getBean("studentJDBCTemplate");
      /*
      System.out.println("------Records Creation--------" );
      studentJDBCTemplate.create("Zara", 11);
      studentJDBCTemplate.create("Nuha", 2);
      studentJDBCTemplate.create("Ayan", 15);

      System.out.println("------Listing Multiple Records--------" );
      List<Student> students = studentJDBCTemplate.listStudents();
      for (Student record : students) 
         System.out.print("ID : " + record.getId() );
         System.out.print(", Name : " + record.getName() );
         System.out.println(", Age : " + record.getAge());
      
	  */
      
      System.out.println("----Listing Record with ID = 2 -----" );
      
      Student student = studentJDBCTemplate.getStudent(3);
      System.out.print("ID : " + student.getId() );
      System.out.print(", Name : " + student.getName() );
      System.out.println(", Age : " + student.getAge());
	  
   

package com.tutorialspoint;

import java.sql.ResultSet;
import java.sql.SQLException;
import org.springframework.jdbc.core.RowMapper;

public class StudentMapper implements RowMapper<Student> 
   public Student mapRow(ResultSet rs, int rowNum) throws SQLException 
      Student student = new Student();
      student.setId(rs.getInt("id"));
      student.setName(rs.getString("name"));
      student.setAge(rs.getInt("age"));
      return student;
   

package com.tutorialspoint;

import java.util.Map;
import java.util.List;

import javax.sql.DataSource;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.jdbc.core.namedparam.SqlParameterSource;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;

public class StudentJDBCTemplate implements StudentDAO 
	
	private DataSource dataSource;
	private SimpleJdbcCall jdbcCall;
	
	public void setDataSource(DataSource dataSource)	
		this.dataSource = dataSource;
		this.jdbcCall = new SimpleJdbcCall(dataSource).withProcedureName("getRecord");
	
	
	public void create(String name, Integer age)
		JdbcTemplate jdbcTemplateObject = new JdbcTemplate(dataSource);
		String SQL = "INSERT INTO Student(name,age) VALUES (?,?)";
		jdbcTemplateObject.update(SQL,name,age);
		System.out.println("Created Record Name = " + name + " Age = " + age);
		return;
	
	
	public Student getStudent(Integer id)
		
		SqlParameterSource in = new MapSqlParameterSource().addValue("inID", id);
		Map<String, Object> out = jdbcCall.execute(in);
		
		Student student = new Student();
		student.setId(id);
		student.setName((String) out.get("outName"));
		student.setAge((Integer) out.get("outAge"));

		return student;
	
	
	public List<Student> listStudents()
		String SQL = "SELECT * FROM Student";
		JdbcTemplate jdbcTemplateObject = new JdbcTemplate(dataSource);
		List <Student> students = jdbcTemplateObject.query(SQL,	new StudentMapper());		
		return students;
	

package com.tutorialspoint;

public class Student 
   private Integer age;
   private String name;
   private Integer id;

   public void setAge(Integer age) 
      this.age = age;
   
   public Integer getAge() 
      return age;
   

   public void setName(String name) 
      this.name = name;
   
   public String getName() 
      return name;
   

   public void setId(Integer id) 
      this.id = id;
   
   public Integer getId() 
      return id;
   

【问题讨论】：

请在问题中包含您使用的代码。

您能否也将存储过程签名添加到您的问题中？

【参考方案1】：

添加参数声明也对我有用，但略有不同：

public Student getStudent(Integer id) 
    SqlParameterSource in = new MapSqlParameterSource().addValue("id", id, Types.INTEGER)
            .addValue("name",Types.VARCHAR)
            .addValue("age", Types.INTEGER);
    Map<String, Object> out = jdbcCall.execute(in);

    Student student = new Student();
    student.setId(id);
    student.setName((String) out.get("name"));
    student.setAge((Integer) out.get("age"));

    return student;

请注意我使用的是 MS SQL Server 而不是 mysql；并且创建的程序略有不同：

CREATE PROCEDURE getRecord
  @id INT,
  @name VARCHAR(20) OUTPUT ,
  @age INT OUTPUT
AS
  SELECT @name = name, @age = AGE
  FROM Student where id = @id

但应该非常相似。

【参考方案2】：

尝试像本例那样使用 SqlOutParameter 声明输出参数，也许警告会消失：

SimpleJdbcCall caller = new SimpleJdbcCall(getDataSource())
.withCatalogName("PKG_REG_REVIEW")
.withFunctionName("fn_get_task_complete_date")
.withoutProcedureColumnMetaDataAccess()
.declareParameters(
new SqlOutParameter("v_maxdate", Types.DATE),
new SqlParameter("p_case_seq", Types.INTEGER),
new SqlParameter("p_task_seq", Types.INTEGER)
);