SQL 交叉应用没有结果
Posted
技术标签:
【中文标题】SQL 交叉应用没有结果【英文标题】:SQL Cross Apply no results 【发布时间】:2018-03-20 15:53:43 【问题描述】:我有 丑陋的 XML,看起来像这样:
<?xml version="1.0"?>
<MainTag xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" RecordID="201801026543210">
<Field Name="TheFieldName">
<FieldValue>Field Contents</FieldValue>
<ListTag>
<ListItem>
<Value>This List Value</Value>
<Source>source.txt</Source>
<ListType>text</ListType>
<ItemNumber>6912</ItemNumber>
<MoreData>some text here</MoreData>
<Address>address data</Address>
<Ranking>102</Ranking>
</ListItem>
<ListItem>
<Value>Another List Value</Value>
<Source>other.txt</Source>
<ListType>text</ListType>
<ItemNumber>7919</ItemNumber>
<MoreData>more text here</MoreData>
<Address>address data</Address>
<Ranking>41</Ranking>
</ListItem>
</ListTag>
</Field>
</MainTag>
我想要的是给我一个电子表格的查询结果,本质上是:
RecordID FieldName FieldValue ListValue ListSource ListType ListItemNumber …
201801026543210 TheFieldName Field Contents This List Value source.txt text 6912
201801026543210 TheFieldName Field Contents Another List Value other.txt text 7919
为了增加乐趣,XML 存储在 varchar 字段中,而不是 XML 字段中。
作为我尝试过的示例数据和查询:
DECLARE @Tbl TABLE (
TblID varchar(15)
, Fld varchar(max)
)
INSERT INTO @Tbl SELECT '201801026543210', '<?xml version="1.0"?><MainTag xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" RecordID="201801026543210"><Field Name="TheFieldName"><FieldValue>Field Contents</FieldValue><ListTag><ListItem><Value>This List Value</Value><Source>source.txt</Source><ListType>text</ListType><ItemNumber>6912</ItemNumber><MoreData>some text here</MoreData><Address>address data</Address><Ranking>102</Ranking></ListItem><ListItem><Value>Another List Value</Value><Source>other.txt</Source><ListType>text</ListType><ItemNumber>7919</ItemNumber><MoreData>more text here</MoreData><Address>address data</Address><Ranking>41</Ranking></ListItem></ListTag></Field></MainTag>'
-- this shows that i am reading the main tag
SELECT t.r.value('@RecordID','varchar(15)') AS RecordID
, t.r.query('.') as fullvalue
FROM (
SELECT top 10 CONVERT(xml, Fld) AS Fld, TblID
FROM @Tbl
) AS s
CROSS APPLY Fld.nodes('/MainTag') AS t(r)
-- and this works to read the attribute from the first field
SELECT t.r.value('@RecordID', 'varchar(18)') AS RecordID
, f.r.value('@Name', 'varchar(100)') AS Field
FROM (
SELECT top 10 CONVERT(xml, Fld) AS Fld, TblID
FROM @Tbl
) AS s
CROSS APPLY Fld.nodes('/MainTag') AS t(r)
CROSS APPLY Fld.nodes('/MainTag/Field') AS f(r)
-- this does NOT work to read the second field
SELECT t.r.value('@RecordID','varchar(18)') AS RecordID
, f.r.value('.', 'varchar(100)') AS ValueF
, p.r.query('.') AS QueryP
, p.r.value('.', 'varchar(100)') AS ValueP
FROM (
SELECT top 10 CONVERT(xml, Fld) AS Fld, TblID
FROM @Tbl
) AS s
CROSS APPLY Fld.nodes('/MainTag') AS t(r)
CROSS APPLY Fld.nodes('/MainTag/Field') AS f(r)
CROSS APPLY Fld.nodes('/MainTag/FieldValue') AS p(r)
-- i honestly feel like this should be using nodes off of the parent nodes method
-- , but this is NOT working either
SELECT t.r.value('@RecordID','varchar(18)') AS RecordID
, p.r.query('.') AS FieldValue
FROM (
SELECT top 10 CONVERT(xml, Fld) AS Fld, TblID
FROM @Tbl
) AS s
CROSS APPLY s.Fld.nodes('/MainTag') AS t(r)
CROSS APPLY t.r.nodes('/MainTag/FieldValue') AS p(r)
我看到了一些其他问题/示例,这些问题/示例仅包含第一个条目。我不要那个。我想要一大堆数据。我希望为每个“ListItem”重复唯一字段。换一种说法:我知道这类似于一对多连接,其中“one”表中的字段将针对“many”表中的每一行重复。
从技术上讲,在我的数据中也可能有多个“字段”。 该字段只有一个 FieldValue。 有一个或多个 ListItem。
【问题讨论】:
顺便说一句:这不是一个丑 XML...这是一个相当漂亮的XML :-) btw2:这是一个很好的问题:样本、MCVE、自己的尝试……我这边+1 我被卡住的部分是 FieldValue。在对这个问题进行缩进后,我意识到我试图在 /MainTag/FieldValue 中访问它,但它位于 /MainTag/Field/FieldValue。 【参考方案1】:用这个查询试试:
SELECT s.Fld.value('(/MainTag/@RecordID)[1]','bigint') AS RecordID
,A.f.value('@Name','nvarchar(max)') as FieldName
,A.f.value('(FieldValue/text())[1]','nvarchar(max)') as FieldValue
,B.li.value('(Value/text())[1]','nvarchar(max)') as ListValue
,B.li.value('(Source/text())[1]','nvarchar(max)') as ListSource
--and so on
FROM (
SELECT top 10 CONVERT(xml, Fld) AS Fld, TblID
FROM @Tbl
) AS s
CROSS APPLY Fld.nodes('/MainTag/Field') AS A(f)
CROSS APPLY A.f.nodes('ListTag/ListItem') AS B(li)
提示
如果有机会将存储空间从 VARCHAR
更改为 XML
,那是值得的......
【讨论】:
等待您的答复以上是关于SQL 交叉应用没有结果的主要内容,如果未能解决你的问题,请参考以下文章