如何对按客户分组的多列和多行求和

Posted 2023-03-23

【中文标题】如何对按客户分组的多列和多行求和

【英文标题】：How to sum multiple columns and rows grouped by customer

【发布时间】：2014-01-21 02:20:01

【问题描述】：

我正在尝试获得一个最终列，它将所有兴趣列加起来作为一个最终数字，这样每个客户就有一个数字。我目前有：

+--------+--------+-------+-------+-------+-------+
|Customer|Number  |IntMax |IntMin |IntMin1|IntMax1|
+--------+--------+-------+-------+-------+-------+
|Jones   |72352516|$0.00  |$381.47|$0.00  |$0.00  |
+--------+--------+-------+-------+-------+-------+
|Jones   |72352516|$455.31|$0.00  |$0.00  |$0.00  |
+--------+--------+-------+-------+-------+-------+
|Brett   |70920356|$0.00  |$0.00  |$194.56|$129.71|
+--------+--------+-------+-------+-------+-------+
|Gavin   |79023561|$0.00  |$617.29|$0.00  |$0.00  |
+--------+--------+-------+-------+-------+-------+
|Gavin   |79023561|$531.46|$0.00  |$0.00  |$0.00  |
+--------+--------+-------+-------+-------+-------+

我想看到的结果是：

+--------+--------+---------+
|Customer|Number  |IntFinal |
+--------+--------+---------+
|Jones   |72352516|$836.78  |
+--------+--------+---------+
|Brett   |70920356|$324.27  |
+--------+--------+---------+
|Gavin   |79023561|$1,148.76|
+--------+--------+---------+

非常感谢

【参考方案1】：

SELECT Customer, Number, 
       SUM(IntMax + IntMin + IntMin1 + IntMax1) AS IntFinal
  FROM Table1
 GROUP BY Customer, Number

输出：

|客户 |号码 |国际 | |---------|----------|----------| |布雷特 | 70920356 | 324.27 | |琼斯 | 72352516 | 836.78 | |加文 | 79023561 | 1148.75 |

这里是SQLFiddle演示

【参考方案2】：

create table #temp
(
    Customer varchar(12) not null,
    Number  int not null,
    IntMax decimal(19,6),
    IntMin decimal(19,6),
    IntMin1 decimal(19,6),
    IntMax1 decimal(19,6),
)
insert into #temp values('Jones',72352516,'0.00','381.47','0.00','0.00')
insert into #temp values('Jones',72352516,'455.31','0.00','0.00','0.00')
insert into #temp values('Brett',70920356,'0.00','0.00','194.56','129.71')
insert into #temp values('Gavin',79023561,'0.00','617.29','0.00','0.00')
insert into #temp values('Gavin',79023561,'531.46','0.00','0.00','0.00')

select * from #temp

select t1.Customer, t1.Number, SUM(T1.IntMax+t1.IntMax1+t1.IntMin+t1.IntMin1) as    IntFinal from #temp t1 group by t1.Customer, t1.Number

drop table #temp

【参考方案3】：

<!-- language: lang-sql -->
  SELECT Customer,Number,SUM((IntMax+IntMin+IntMin1+IntMax1)) as IntFinal
    FROM tablename
GROUP BY Customer,Number

【参考方案4】：

感谢您的所有回答，我最终也找到了以下答案：

SELECT Interest_Min_Max1.Customer, CCur(Sum([IntMax])+Sum([IntMin])+Sum([IntMax1])+Sum([IntMin1])) AS Total 从表 1 GROUP BY Interest_Min_Max1.Customer, Interest_Min_Max1.Number;