pd.read_sql - 不支持的格式字符错误 (0x27)
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【中文标题】pd.read_sql - 不支持的格式字符错误 (0x27)【英文标题】:pd.read_sql - Unsupported format character error (0x27) 【发布时间】:2021-06-06 08:13:44 【问题描述】:如上所述,我正在尝试使用 pd.read_sql 来查询我们的 mysql 数据库,并收到双引号/单引号错误。
当我从 LIKE 子句(第 84-87 行)中删除 % 运算符时,查询运行,但这些是必需的。我知道我需要格式化字符串,但我不知道如何在这么大的查询中。
这是查询:
SELECT
s.offer_id,
s.cap_id,
vi.make,
vi.model,
vi.derivative,
i.vehicle_orders,
s.lowest_offer,
CASE
WHEN f.previous_avg = f.previous_low THEN "n/a"
ELSE FORMAT(f.previous_avg, 2)
END as previous_avg,
f.previous_low,
CASE
WHEN ( ( (s.lowest_offer - f.previous_avg) / f.previous_avg) * 100) = ( ( (s.lowest_offer - f.previous_low) / f.previous_low) * 100) THEN "n/a"
ELSE CONCAT(FORMAT( ( ( (s.lowest_offer - f.previous_avg) / f.previous_avg) * 100), 2), "%")
END as diff_avg,
CONCAT(FORMAT( ( ( (s.lowest_offer - f.previous_low) / f.previous_low) * 100), 2), "%") as diff_low,
s.broker,
CASE
WHEN s.in_stock = '1' THEN "In Stock"
ELSE "Factory Order"
END as in_stock,
CASE
WHEN s.special IS NOT NULL THEN "Already in Specials"
ELSE "n/a"
END as special
FROM
( SELECT o.id as offer_id,
o.cap_id as cap_id,
MIN(o.monthly_payment) as lowest_offer,
b.name as broker,
o.stock as in_stock,
so.id as special
FROM
offers o
INNER JOIN brands b ON ( o.brand_id = b.id )
LEFT JOIN special_offers so ON ( so.cap_id = o.cap_id )
WHERE
( o.date_modified >= DATE_ADD(NOW(), INTERVAL -1 DAY) OR o.date_created >= DATE_ADD(NOW(), INTERVAL -1 DAY) )
AND o.deposit_value = 9
AND o.term = 48
AND o.annual_mileage = 8000
AND o.finance_type = 'P'
AND o.monthly_payment > 100
GROUP BY
o.cap_id
ORDER BY
special DESC) s
INNER JOIN
( SELECT o.cap_id as cap_id,
AVG(o.monthly_payment) as previous_avg,
MIN(o.monthly_payment) as previous_low
FROM
offers o
WHERE
o.date_modified < DATE_ADD(NOW(), INTERVAL -1 DAY)
AND o.date_modified >= DATE_ADD(NOW(), INTERVAL -1 WEEK)
AND o.deposit_value = 9
AND o.term = 48
AND o.annual_mileage = 8000
AND o.finance_type = 'P'
AND o.monthly_payment > 100
GROUP BY
o.cap_id ) f ON ( s.cap_id = f.cap_id )
LEFT JOIN
( SELECT a.cap_id as cap_id,
v.manufacturer as make,
v.model as model,
v.derivative as derivative,
COUNT(*) as vehicle_orders
FROM
( SELECT o.id,
o.name as name,
o.email as email,
o.date_created as date,
SUBSTRING_INDEX(SUBSTRING(offer_serialized, LOCATE("capId", offer_serialized) +12, 10), '"', 1) as cap_id
FROM moneyshake.orders o
WHERE o.name NOT LIKE 'test%'
AND o.email NOT LIKE 'jawor%'
AND o.email NOT LIKE 'test%'
AND o.email NOT LIKE '%moneyshake%'
AND o.phone IS NOT NULL
AND o.date_created > DATE_ADD(NOW(), INTERVAL -1 MONTH)
) a JOIN moneyshake.vehicles_view v ON a.cap_id = v.id
GROUP BY
v.manufacturer,
v.model,
v.derivative,
a.cap_id) i ON ( f.cap_id = i.cap_id )
INNER JOIN
( SELECT v.id as id,
v.manufacturer as make,
v.model as model,
v.derivative as derivative
FROM moneyshake.vehicles_view v
GROUP BY v.id ) vi ON s.cap_id = vi.id
WHERE
( ( s.lowest_offer - f.previous_low ) / f.previous_low) * 100 <= -15
GROUP BY
s.cap_id
谢谢!
【问题讨论】:
您用于尝试运行提供的查询的实际 Python 代码是什么? 【参考方案1】:发生该错误后,DBAPI 层(例如,mysqlclient)本机使用“格式”paramstyle,并且百分号 (%
) 被误解为格式字符而不是 LIKE
通配符。
解决方法是将 SQL 语句包装在 SQLAlchemy text()
对象中。例如,这将失败:
import pandas as pd
import sqlalchemy as sa
engine = sa.create_engine("mysql+mysqldb://scott:tiger@localhost:3307/mydb")
sql = """\
SELECT * FROM million_rows
WHERE varchar_col LIKE 'record00000%'
ORDER BY id
"""
df = pd.read_sql_query(sql, engine)
但只需将 read_sql_query()
调用更改为
df = pd.read_sql_query(sa.text(sql), engine)
会起作用的。
【讨论】:
听起来确实可以解决我的问题。我明天就知道了:)谢谢!以上是关于pd.read_sql - 不支持的格式字符错误 (0x27)的主要内容,如果未能解决你的问题,请参考以下文章
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