如何在我的数组中添加货币符号？

Posted 2023-03-22

【中文标题】如何在我的数组中添加货币符号？

【英文标题】：How to add a currency symbol to my array?

【发布时间】：2021-12-21 11:23:28

【问题描述】：

目标：

用£符号显示我的佣金支付清单。

问题的解释：

在显示结果时，它不会打印整个结果，而是仅打印 £ 符号。

我尝试过的：

正如您在代码中看到的那样，我尝试将数组转换为字符串（将其放入自己的变量中），然后将货币符号 (£) 添加到其中并要求调用佣金 2。但是，它没有显示。

输出：

Name         Id           Houses Sold  Commission  
£1000

ki           2            2            £  

（1000英镑只是为了表明数据确实存在，但是在列表中打印时由于某种原因没有显示出来……）

所需输出：

Name         Id           Houses Sold  Commission  

ki           2            2            £1000 

我已经做了好几个小时了，所以任何帮助都将不胜感激！

发生错误的代码：

def print_entered_info(names, ids, num_sold_houses):
print()
row_width = 12
comission_per_house = 500
header = ['Name', 'Id', 'Houses Sold', 'Commission']
print(' '.join(f'h:<row_width' for h in header))
commission = [n * comission_per_house for n in num_sold_houses] 
commission2 = commission
commission2 = ''.join(str(e) for e in commission)
commission2= "£" + commission2
print(commission2)
for values in zip(*[names, ids, num_sold_houses, commission2]):
    print()
    print(' '.join(f'v:<row_width' for v in values))

我的完整代码：

def get_int_input(prompt: str) -> int:
    num = -1
    while True:
        try:
            num = int(input(prompt))
            break
        except ValueError:
            print('Error: Enter an integer, try again...')
    return num

def get_yes_no_input(prompt: str) -> bool:
    allowed_responses = 'y', 'yes', 'n', 'no'
    user_input = input(prompt).lower()
    while user_input not in allowed_responses:
        user_input = input(prompt).lower()
    return user_input[0] == 'y'

names = []
ids = []
num_sold_houses= []
def get_single_employee_info(names, ids, num_sold_houses):
 names.append(input('What is the employee\'s name?: '))
 ids.append(get_int_input('What is the employee\'s id?: '))
 num_sold_houses.append(get_int_input('How many houses did the employee sell?: '))

def get_houses_sold_info(names, ids, num_sold_houses):
    get_single_employee_info(names, ids, num_sold_houses)
    add_another_employee = get_yes_no_input('Add another employee [yes/no]?: ')
    while add_another_employee:
        get_single_employee_info(names, ids, num_sold_houses)
        add_another_employee = get_yes_no_input(
            'Add another employee [yes/no]?: ')

def print_entered_info(names, ids, num_sold_houses):
    print()
    row_width = 12
    comission_per_house = 500
    header = ['Name', 'Id', 'Houses Sold', 'Commission']
    print(' '.join(f'h:<row_width' for h in header))
    commission = [n * comission_per_house for n in num_sold_houses] 
    commission2 = commission
    commission2 = ''.join(str(e) for e in commission)
    commission2= "£" + commission2
    print(commission2)
    for values in zip(*[names, ids, num_sold_houses, commission2]):
        print()
        print(' '.join(f'v:<row_width' for v in values))
    print()   
    total_commission = sum(commission)
    print(f'Total Commission: £total_commission.00 (before bonus)')
    print()
    bonus = max(commission)
    if bonus >= max(commission):
     bonus = bonus*0.15
     bonus = (int(max(commission)) + bonus)
     commission = bonus

    print("The person at the top of ranking gets: " + "£" + str(commission)+"0") 
    print()
    rankings = sorted(zip(num_sold_houses, names), reverse=True)
    print('Ranking:')
    for houses_sold, name in rankings:
        print(f'name - houses_sold')

def main() -> None:
    print('Houses Sold Tracker')
    print('===================')
    names, ids, num_houses_sold = [], [], []
    get_houses_sold_info(names, ids, num_houses_sold)
    print_entered_info(names, ids, num_houses_sold)

if __name__ == '__main__':
    main() 

【参考方案1】：

更换

commission2 = ''.join(str(e) for e in commission)

到

commission2 = ["£" + str(e) for e in commission]

并删除它下面的行。您的 ''.join 采用 2 个列表元素并将它们强制转换为单个字符串，这不是您想要的逻辑。您想要一个commission2 变量的列表输出，因此我们创建一个列表并将字符串化的值与货币符号一起附加到它。

输出：

Name         Id           Houses Sold  Commission  

Kevin        1            3            £1500       

Stacey       2            5            £2500       

Total Commission: £4000.00 (before bonus)

The person at the top of ranking gets: £2875.00

Ranking:
Stacey - 5
Kevin - 3

【讨论】：

工作就像一个魅力，感谢您的建议！