AFNetworking：从 Http 响应中获取 JSON 值

Posted 2023-03-16

【中文标题】AFNetworking：从 Http 响应中获取 JSON 值

【英文标题】：AFNetworking: Get JSON Value From Http Response

【发布时间】：2014-07-09 23:02:38

【问题描述】：

我主要是一名 android 开发人员，对 ios 非常陌生。我正在使用 AFNetworking 1.0，因为我正在使用现有源，并且我正在发送标准的 http Post 请求并返回如下数据：

   //Sending the post request and getting the result
    AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:[NSURL URLWithString:@"http://testsite.org/mobile_app"]];
    [httpClient setParameterEncoding:AFFormURLParameterEncoding];
    NSMutableURLRequest *request = [httpClient requestWithMethod:@"POST"
                                                            path:@"http://testsite.org/mobile_app/studentregister.php"
                                                      parameters:@@"username":username, @"displayname":displayname, @"password":password, @"passwordc":passwordc, @"email":email, @"teacherCode":teacherCode];
    AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:request];
    [httpClient registerHTTPOperationClass:[AFHTTPRequestOperation class]];
    [operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) 
        // Print the response body in text
        NSLog(@"Response: %@", [[NSString alloc] initWithData:responseObject encoding:NSUTF8StringEncoding]);
     failure:^(AFHTTPRequestOperation *operation, NSError *error) 
        NSLog(@"Error: %@", error);
    ];
    [operation start];

响应应该包含根据 burp suit 看起来像这样的 JSON 数据：

"userCharLimit":"Your username must be between 5 and 25 characters in length"

"displaynameCharLim":"Your displayname must be between 5 and 25 characters in length"

"passLimit":"Your password must be between 8 and 50 characters in length"

"emailInvalid":"Not a valid email address"

"teacherCodeLength":"Your teacher code is not 5 to 12 characters".

如何获取这些 JSON 值？我已经看过很多 AFNetworking 2.0 JSON 示例并发送 JSON Post 请求，但我似乎可以在 1.0 版中找到很多东西，更不用说从标准 post 请求中获取值了。 有什么想法或资源吗？

【问题讨论】：

您是否在NSLog 行遇到异常，您实际上并没有说出问题所在...

【参考方案1】：

您只需更改代码以注册 AFJSONRequestOperation 而不是 AFHTTPRequestOperation。

[httpClient registerHTTPOperationClass:[AFJSONRequestOperation class]];

然后您可以在 AFHTTPClent 上使用此方法来创建实际类型为 AFJSONRequestOperation 的操作。

AFHTTPRequestOperation *operation = [httpClient HTTPRequestOperationWithRequest:request success:nil failure:nil];
[httpClient enqueueOperation:operation];