如何使用 swift 2.0 制作 http post json 请求参数

Posted 2023-03-16

【中文标题】如何使用 swift 2.0 制作 http post json 请求参数

【英文标题】：how to make http post json request params using swift 2.0

【发布时间】：2016-02-23 06:51:01

【问题描述】：

我需要在swift2.0中使用nsurl会话将json请求参数发送到服务器。我不知道如何创建 json 请求参数。我创建了这样的参数

让 jsonObj = ["Username":"Admin", "Password":"123","DeviceId":"87878"]

   // print("Params are \(jsonObj)")

    //request.HTTPBody = try! NSJSONSerialization.dataWithJSONObject(jsonObj, options: [])

    // or if you think the conversion might actually fail (which is unlikely if you built `params` yourself)

     do 
        request.HTTPBody = try NSJSONSerialization.dataWithJSONObject(jsonObj, options:.PrettyPrinted)
      catch 
        print(error)
     

但它没有 ping 到方法体，所以我得到了失败响应

【参考方案1】：

试试下面的代码。

    let parameters = ["Username":"Admin", "Password":"123","DeviceId":"87878"] as Dictionary<String, String>
    let request = NSMutableURLRequest(URL: NSURL(string:YOURURL)!)

    let session = NSURLSession.sharedSession()
    request.HTTPMethod = "POST"

    //Note : Add the corresponding "Content-Type" and "Accept" header. In this example I had used the application/json.
    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

    request.HTTPBody = try! NSJSONSerialization.dataWithJSONObject(parameters, options: [])

    let task = session.dataTaskWithRequest(request)  data, response, error in
        guard data != nil else 
            print("no data found: \(error)")
            return
        

        do 
            if let json = try NSJSONSerialization.JSONObjectWithData(data!, options: []) as? NSDictionary 
                print("Response: \(json)")
             else 
                let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)// No error thrown, but not NSDictionary
                print("Error could not parse JSON: \(jsonStr)")
            
         catch let parseError 
            print(parseError)// Log the error thrown by `JSONObjectWithData`
            let jsonStr = NSString(data: data!, encoding: NSUTF8StringEncoding)
            print("Error could not parse JSON: '\(jsonStr)'")
        
    

    task.resume()

希望对你有用！！

【讨论】：

谢谢 :) 很有帮助