NSMutableDictionary 没有得到预期的输出。

Posted 2023-03-15

【中文标题】NSMutableDictionary 没有得到预期的输出。

【英文标题】：NSMutableDictionary not getting expected output.

【发布时间】：2011-12-07 17:08:14

【问题描述】：

它只为 NSMutableDictionary 输出一组，而不是两者。我想使用 NSMutableDictionary (JSONRepresentation) 创建一个 JSON 请求。

// My code    

NSArray *keysEndpoint = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint = [NSArray arrayWithObjects:@"622", @"Brand", @"0", nil];

NSArray *keysEndpoint1 = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint1 = [NSArray arrayWithObjects:@"595", @"CK-05052011", @"1", nil];

NSMutableArray *keys1 = [[NSMutableArray alloc] initWithCapacity:0];
NSMutableArray *objects1 =  [[NSMutableArray alloc] initWithCapacity:0];

[keys1 addObjectsFromArray:keysEndpoint];
[keys1 addObjectsFromArray:keysEndpoint1];

NSLog(@"Key Dic: %@", keys1);

[objects1 addObjectsFromArray:objectEndpoint];
[objects1 addObjectsFromArray:objectEndpoint1];

NSLog(@"Obje Dic: %@", objects1);

NSMutableDictionary *testMut = [NSMutableDictionary dictionaryWithObjects:objects1  forKeys:keys1];

NSLog(@"Test Dic: %@", testMut);

输出是这样的：

 Test Dic: 
    EndpointType = 1;
    ID = 595;
    Name = "CK-05052011";

我想要的扩展输出是：

Test Dic: 
    EndpointType = 1;
    ID = 595;
    Name = "CK-05052011";
 

    EndpointType = 0;
    ID = 622;
    Name = "Brand";

【参考方案1】：

对于字典，两次添加相同的键将覆盖第一组键。你应该有一个 NSMutableDictionary 的 NSMutableArray

NSArray *keysEndpoint = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint = [NSArray arrayWithObjects:@"622", @"Brand", @"0", nil];

NSArray *keysEndpoint1 = [NSArray arrayWithObjects:@"ID", @"Name", @"EndpointType", nil];
NSArray *objectEndpoint1 = [NSArray arrayWithObjects:@"595", @"CK-05052011", @"1", nil];

NSMutableDictionary *testMut = [NSMutableDictionary dictionaryWithObjects:objectsEndpoint  forKeys:keysEndpoint];


NSMutableDictionary *testMut1 = [NSMutableDictionary dictionaryWithObjects:objectsEndpoint1  forKeys:keysEndpoint1];

NSMutableArray * dictArray = [NSMutableArray arrayWithObjects:testMut,testMut1,nil];

NSLog(@"Test DictArray: %@", dictArray);

【讨论】：

谢谢，这可以工作，但问题是，我有超过 20 个数组用于关键点和对象端点。我无法创建 20 个 NSMutableDictionary。有没有办法以编程方式做到这一点？

@AmitVyawahare 您从哪里获取关键点和对象端点数据？绝对可以动态填充这些数据。要将数据转换为 json 对象，您可以在 SO 上查找 SBJson 或 JSONKit 的示例。