如何从数据框中迭代值并将值传递给 Python 中的发送电子邮件函数

Posted 2023-03-15

【中文标题】如何从数据框中迭代值并将值传递给 Python 中的发送电子邮件函数

【英文标题】：How to iterate values from a dataframe and pass the values to a send email function in Python

【发布时间】：2020-10-13 01:50:06

【问题描述】：

我有一个数据框(df)，如下所示

Subject                       To_Address       CC_Address                       Backup_Address
Invoice 2345 is invalid       [e-mail]     koke@gmail,[e-mail]         [e-mail]
Invoice 3456 is invalid       [e-mail]     [e-mail],ali.gmail.com     [e-mail]
Invoice 3673 is invalid       [e-mail]     [e-mail],ali.gmail.com    [e-mail]
Invoice 8978 is invalid                         [e-mail],ali.gmail.com     [e-mail]
Invoice 8078 is invalid                         [e-mail],ali.gmail.com     [e-mail]
Invoice 3173 is invalid       [e-mail]     [e-mail],ali.gmail.com     [e-mail]

我需要为数据框的每一行发送唯一的电子邮件

Email Subject = df[Subject] ,Email To Address =df[To_Address], Email_CC_Address = df[CC_Address]

还需要添加期望条件，Email To Address 为 null 或 NaN，则应通过 Email To Address =df[Backup_Address]

如何在 python 中做到这一点。

我当前使用静态值运行的代码

def create_message(send_from, send_to,cc_to,subject, plain_text_body):
    message = MIMEMultipart('alternative')
    message['From'] = send_from
    message['To'] = COMMASPACE.join(send_to)
    message['Cc'] = cc_to
    message['Subject'] = subject
    message.attach(MIMEText(plain_text_body, 'plain'))
    return message


subject = "Invoice is invalid"
sender_address = "[e-mail]"
to = "[e-mail]"
cc_to = "[e-mail]"
mail_content="This is a test message"

message = create_message(sender_address,[to],cc_to,subject,mail_content)

send_message(message)

【问题讨论】：

如果是 CSV/TSV 文件，也许使用普通 CSV 模块比在这里使用 Pandas 更好。

@Arunmozhi，我将 pandas 数据框写入 CSV 文件，我不知道如何迭代和传递值并发送单独的电子邮件。

如果消息实际上只有一个正文部分，则不要创建多部分容器。顾名思义，multipart 适用于您拥有多个正文部分的情况，例如主消息和附件。

这能回答你的问题吗？ How to iterate over rows in a DataFrame in Pandas

【参考方案1】：

尝试使用zip 并行遍历数据框中的行和多列：

def create_message(send_from, send_to, cc_to,subject, plain_text_body):
    sender_address = "[e-mail]"
    mail_content="This is a test message"
    for a, b, c, d in zip(df['Subject'], df['To_Address'], df['CC_Address'], df['Backup_Address']):
        if b == '':
            send_to = d
        else:
            send_to = b
        subject = a
        cc_to = c
        message = MIMEMultipart('alternative')
        message['From'] = send_from
        message['To'] = COMMASPACE.join(send_to)
        message['Cc'] = cc_to
        message['Subject'] = subject
        message.attach(MIMEText(plain_text_body, 'plain'))
        return message


message = create_message(sender_address,[to],cc_to,subject,mail_content)

send_message(message)

【讨论】：

这个else: to = d应该else:send_to = d，我是对的

【参考方案2】：

要遍历 Pandas DataFrame，您可以使用 DataFrame.iterrows()。

但不推荐对 df 进行迭代，因为它被视为“反模式”..

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