当从 MySQL 数据库动态加载元素时，在 PHP 中连接 2 个 JSON 数组

Posted 2023-03-14

【中文标题】当从 MySQL 数据库动态加载元素时，在 PHP 中连接 2 个 JSON 数组

【英文标题】：Concatenate 2 JSON arrays in PHP when elements loading dynamically from a MySQL database

【发布时间】：2021-01-27 14:48:08

【问题描述】：

我正在使用 Laravel API，我有以下要求。我正在查询数据库并接受一些订单。我正在检查一个contract_id，我正在使用2 个SQL 查询来获取带有合同ID 的订单以及没有合同ID 的订单。

public function totalOrdersTest(Request $request)


    $from = new DateTime($request->query->get('from'));
    $to = new DateTime($request->query->get('to'));
    $manufacturer_id = $request->query->get('manu');
    $article_template_id = $request->query->get('article_template_id');

    if ($article_template_id == '' || $article_template_id == null) 
        $results_not_null = Order::selectRaw('count(*) not_null_order_count, DATE_FORMAT(orders.created_at, "%Y-%m-%d") as order_date')
            ->filterManufacturer($manufacturer_id)
            ->join('order_items', 'order_items.order_id', '=', 'orders.id')
            ->whereNotNull('order_items.tariff_id')
            ->whereBetween('orders.created_at', [$from, $to])
            ->groupBy('order_date')
            ->orderBy('order_date')
            ->get();

        $results_null = Order::selectRaw('count(*) null_order_count, DATE_FORMAT(orders.created_at, "%Y-%m-%d") as order_date')
            ->filterManufacturer($manufacturer_id)
            ->join('order_items', 'order_items.order_id', '=', 'orders.id')
            ->whereNull('order_items.tariff_id')
            ->whereBetween('orders.created_at', [$from, $to])
            ->groupBy('order_date')
            ->orderBy('order_date')
            ->get();
     else 
        $result = Order::selectRaw('count(*) order_count, DATE_FORMAT(created_at, "%Y-%m-%d") as order_date')
            ->filterArticleTemplate($article_template_id)
            ->whereBetween('created_at', [$from, $to])
            ->groupBy('order_date')
            ->orderBy('order_date')
            ->get();
    

    // Need to concatenate ´$results_not_null´ & ´$results_null´ and take a one JSON array. 

从这段代码中，我得到了这个带有 2 个对象的 JSON 数组。

"results_not_null":["not_null_order_count":1,"order_date":"2020-06-09","not_null_order_count":2,"order_date":"2020-06-19","not_null_order_count":1,"order_date":"2020-06-29","not_null_order_count":5,"order_date":"2020-07-06","not_null_order_count":2,"order_date":"2020-07-07","not_null_order_count":1,"order_date":"2020-07-08","not_null_order_count":1,"order_date":"2020-07-15","not_null_order_count":1,"order_date":"2020-07-17","not_null_order_count":2,"order_date":"2020-07-22","not_null_order_count":1,"order_date":"2020-07-31","not_null_order_count":1,"order_date":"2020-08-01","not_null_order_count":1,"order_date":"2020-08-03","not_null_order_count":1,"order_date":"2020-08-15","not_null_order_count":2,"order_date":"2020-08-27","not_null_order_count":1,"order_date":"2020-09-15","not_null_order_count":1,"order_date":"2020-09-17","not_null_order_count":4,"order_date":"2020-09-18","not_null_order_count":2,"order_date":"2020-09-19","not_null_order_count":1,"order_date":"2020-09-20","not_null_order_count":1,"order_date":"2020-09-21","not_null_order_count":2,"order_date":"2020-09-22","not_null_order_count":5,"order_date":"2020-09-23","not_null_order_count":1,"order_date":"2020-09-24","not_null_order_count":2,"order_date":"2020-09-25","not_null_order_count":1,"order_date":"2020-09-26","not_null_order_count":5,"order_date":"2020-09-27","not_null_order_count":5,"order_date":"2020-09-28","not_null_order_count":5,"order_date":"2020-09-29","not_null_order_count":3,"order_date":"2020-09-30","not_null_order_count":4,"order_date":"2020-10-01","not_null_order_count":3,"order_date":"2020-10-02","not_null_order_count":4,"order_date":"2020-10-04","not_null_order_count":1,"order_date":"2020-10-05","not_null_order_count":3,"order_date":"2020-10-06","not_null_order_count":2,"order_date":"2020-10-07","not_null_order_count":1,"order_date":"2020-10-08"],"results_null":["null_order_count":1,"order_date":"2020-06-09","null_order_count":1,"order_date":"2020-06-15","null_order_count":1,"order_date":"2020-06-18","null_order_count":3,"order_date":"2020-06-19","null_order_count":1,"order_date":"2020-06-23","null_order_count":1,"order_date":"2020-06-25","null_order_count":1,"order_date":"2020-06-29","null_order_count":21,"order_date":"2020-07-06","null_order_count":2,"order_date":"2020-07-07","null_order_count":3,"order_date":"2020-07-08","null_order_count":1,"order_date":"2020-07-15","null_order_count":3,"order_date":"2020-07-17","null_order_count":3,"order_date":"2020-07-19","null_order_count":2,"order_date":"2020-07-22","null_order_count":3,"order_date":"2020-07-24","null_order_count":1,"order_date":"2020-07-31","null_order_count":1,"order_date":"2020-08-01","null_order_count":1,"order_date":"2020-08-03","null_order_count":1,"order_date":"2020-08-04","null_order_count":1,"order_date":"2020-08-15","null_order_count":5,"order_date":"2020-08-27","null_order_count":2,"order_date":"2020-09-02","null_order_count":2,"order_date":"2020-09-13","null_order_count":1,"order_date":"2020-09-15","null_order_count":1,"order_date":"2020-09-17","null_order_count":4,"order_date":"2020-10-01"]

但我需要连接这 2 个 JSON 数组。两个数组中最重要的任务是有相同的日期，然后我需要在一个元素中使用它们。例如，

[

"order_date":"2020-12-12",
"not_null_order_count": 2,
"null_order_count":3
,

"order_date":"2020-12-13",
"not_null_order_count": 12,
"null_order_count":5
,

"order_date":"2020-12-14",
"null_order_count":9

]

这是我需要的输出。有时一个日期只有 null_order_count 或 not_null_order_count。

有没有什么方法可以使用一个 mysql 查询来做到这一点？或者如何将这 2 个数组组合成一个 JSON 数组？请指教。

【问题讨论】：

你能发布最终的 sql 查询吗？您可以使用 SUM(CASE WHEN .. 进行 1 个查询，但我很确定您必须使用本机 sql 编写它

@AngelDeykov 嘿，你是说 Laravel ORM 生成的原生 SQL 查询吗？

是的，你也可以发一下

@AngelDeykov 请在此处查看代码：gist.github.com/chanakaDe/0a4d0e89e0f13dd818e0d3aa8437158b

【参考方案1】：

尝试合并两个 json：

   \json_encode(array_merge(\json_decode($json1, true), \json_decode($json2, true)))

【讨论】：

它不工作。我需要组合这两个数组，然后有以下响应。 [ “order_date”：“2020-12-12”，“not_null_order_count”：2，“null_order_count”：3，“order_date”：“2020-12-13”，“not_null_order_count”：12，“null_order_count”： 5 , "order_date":"2020-12-14", "null_order_count":9 ]