AttributeError:模块 Django.contrib.auth.views 没有属性

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【中文标题】AttributeError:模块 Django.contrib.auth.views 没有属性【英文标题】:AttributeError: module Django.contrib.auth.views has no attribute 【发布时间】:2018-04-14 09:29:02 【问题描述】:

在我的 Django 应用用户帐户中,我为我的注册创建了一个注册表单和一个模型。但是,当我运行 python manage.py makemigrations 时,遇到错误:AttributeError: module Django.contrib.auth.views has no attribute 'registration'。其次,我在 forms.py 中正确编码 SignUpForm 吗?我不想在模型中使用 User 模型,因为它会请求用户名,我不希望我的网站要求用户名。

这是我的代码:

models.py

from django.db import models
from django.db.models.signals import post_save
from django.dispatch import receiver
from django.contrib.auth.models import User

class UserProfile(models.Model):
    first_name = models.CharField(max_length=150)
    last_name =  models.CharField(max_length=150)
    email = models.EmailField(max_length=150)
    birth_date = models.DateField()
    password = models.CharField(max_length=150)

@receiver(post_save, sender=User)
def update_user_profile(sender, instance, created, **kwargs):
    if created:
        UserProfile.objects.create(user=instance)
    instance.profile.save()

forms.py

from django.forms import forms
from django.contrib.auth.models import User
from django.contrib.auth.forms import UserCreationForm
from useraccounts.models import UserProfile

class SignUpForm(UserCreationForm):

    class Meta:
        model = User

        fields = ('first_name',
                  'last_name',
                  'email',
                  'password1',
                  'password2', )

views.py

from django.shortcuts import render, redirect
from django.contrib.auth import login, authenticate
from useraccounts.forms import SignUpForm

# Create your views here.
def home(request):
    return render(request, 'useraccounts/home.html')

def login(request):
    return render(request, 'useraccounts/login.html')

def registration(request):
    if request.method == 'POST':
        form = SignUpForm(request.POST)
        if form.is_valid():
            user = form.save()
            user.refresh_from_db()
            user.profile.birth_date = form.cleaned_data.get('birth_date')
            user.save()
            raw_password = form.cleaned_data.get('password1')
            user = authenticate(password=raw_password)
            login(request, user)
            return redirect('home')
        else:
            form = SignUpForm()
        return render(request, 'registration.html', 'form': form)

urls.py

from django.conf.urls import url
from . import views
from django.contrib.auth import views as auth_views

urlpatterns = [

    url(r'^$', views.home),
    url(r'^login/$', auth_views.login, 'template_name': 'useraccounts/login.html', name='login'),
    url(r'^logout/$', auth_views.logout, 'template_name': 'useraccounts/logout.html', name='logout'),
    url(r'^registration/$', auth_views.registration, 'template_name': 'useraccounts/registration.html', name='registration'),

]

【问题讨论】:

请发布您的完整错误回溯 原来我弄乱了 url.py 部分进行注册。感谢您的回答! 始终编写 Django 版本,因为版本中正在进行大量开发。 【参考方案1】:

应该是:

url(r'^registration/$', views.registration, 'template_name': 'useraccounts/registration.html', name='registration'),

auth_views 没有注册,你的意见有

【讨论】:

谢谢。但是现在当我打开 useraccounts/registration.html 时,我收到错误:“视图 useraccounts.views.registration 没有返回 HttpResponse 对象。它返回了 None。”另外,我的表单和视图是否正确?【参考方案2】:

我不能离开 cmets 所以我决定留下一个答案。 你在 else 块附近有额外的缩进。您的注册函数应如下所示:

def registration(request):
    if request.method == 'POST':
        form = SignUpForm(request.POST)
        if form.is_valid():
            user = form.save()
            user.refresh_from_db()
            user.profile.birth_date = form.cleaned_data.get('birth_date')
            user.save()
            raw_password = form.cleaned_data.get('password1')
            user = authenticate(password=raw_password)
            login(request, user)
            return redirect('home')
    else:
        form = SignUpForm()
    return render(request, 'registration.html', 'form': form)

这就是您收到此错误的原因

视图 useraccounts.views.registration 未返回 HttpResponse 对象。它返回 None 。

【讨论】:

【参考方案3】:

您的 urlpatterns 应该是:

from django.contrib.auth import views as auth_views

urlpatterns = [
   url( r'^login/$',auth_views.LoginView.as_view(template_name="useraccounts/login.html"), name="login"),
]

【讨论】:

【参考方案4】:

打开urls.py 并替换:

django.contrib.auth.views.logindjango.contrib.auth.views.LoginView

django.contrib.auth.views.logoutdjango.contrib.auth.views.LogoutView

【讨论】:

【参考方案5】:

在 django 2.1 版中,我使用来自身份验证应用程序的自定义 urls 模式

from django.urls import path, re_path
from django.contrib.auth import views as auth_views
from django.conf import settings
from .views import register_view, activate


urlpatterns = [
    # url(r'^$', HomeView.as_view(), name='home'),
    re_path(r'^register/$', register_view, name='signup'),
    re_path(r'^activate/(?P<uidb64>[0-9A-Za-z_\-]+)/(?P<token>[0-9A-Za-z]1,13-[0-9A-Za-z]1,20)/$',
            activate, name='users_activate'),
    re_path('login/', auth_views.LoginView, 
        'template_name': "users/registration/login.html",
        name='login'),
    re_path('logout/', auth_views.LogoutView,
        'next_page': settings.LOGIN_REDIRECT_URL, name='logout'),

    re_path(r'^password_reset/$', auth_views.PasswordResetView,
        'template_name': "users/registration/password_reset_form.html",
        name='password_reset'),
    re_path(r'^password_reset/done/$', auth_views.PasswordResetDoneView,
        'template_name': "users/registration/password_reset_done.html",
        name='password_reset_done'),
    re_path(r'^reset/(?P<uidb64>[0-9A-Za-z_\-]+)/(?P<token>[0-9A-Za-z]1,13-[0-9A-Za-z]1,20)/$',
        auth_views.PasswordResetConfirmView,
        'template_name': "users/registration/password_reset_confirm.html",
        name='password_reset_confirm'),
    re_path(r'^reset/done/$', auth_views.PasswordResetCompleteView,
        'template_name': "users/registration/password_reset_complete.html",
        name='password_reset_complete'),
]

【讨论】:

【参考方案6】:

打开 urls.py 并替换:

更改views.login => views.LoginView.as_view()

【讨论】:

【参考方案7】:

您需要 LoginView 等作为一个类,而不是像 here 所见的函数(Django 1.11 中的新功能为 Should 和 2.1 版起必须)

【讨论】:

【参考方案8】:

Django 2.1 contrib 视图从函数视图更改为类视图,名称也会更改,因此在忘记过程中您需要提供其他视图名称

urls.py

​​>
from django.contrib.auth import views as auth_views

path('password_reset/', auth_views.PasswordResetView.as_view(), 'template_name':'registration/Reset_email.html', name='password_reset'),
    path('password_reset/done/', auth_views.PasswordResetDoneView.as_view(), 'template_name':'registration/Reset_Email_Sent.html', name='password_reset_done'),
    re_path('reset/(?P<uidb64>[0-9A-Za-z_\-]+)/(?P<token>[0-9A-Za-z]1,13-[0-9A-Za-z]1,20)/', auth_views.PasswordResetConfirmView.as_view(), 'template_name' : 'registration/Forgot_password.html', name='password_reset_confirm'),
    path('reset/done/', auth_views.PasswordResetCompleteView.as_view(), 'template_name' : 'registration/Signin.html', name='password_reset_complete'),

Django 你可以自定义用户模型,你可以删除用户名和使用电子邮件地址

models.py

​​>

用户模型,您可以编写自定义列,您可以添加和删除

用户管理你也可以像超级用户一样自定义commond,如果你 您需要提供任何默认值

from django.contrib.auth.models import User
from django.contrib.auth.models import AbstractUser,BaseUserManager
from django.utils.translation import ugettext_lazy as _

class UserManager(BaseUserManager):
    """Define a model manager for User model with no username field."""

    use_in_migrations = True

    def _create_user(self, email, password, **extra_fields):
        """Create and save a User with the given email and password."""
        if not email:
            raise ValueError('The given email must be set')
        email = self.normalize_email(email)
        user = self.model(email=email, **extra_fields)
        user.set_password(password)
        user.save(using=self._db)
        return user

    def create_user(self, email, password=None, **extra_fields):
        """Create and save a regular User with the given email and password."""
        extra_fields.setdefault('is_staff', False)
        extra_fields.setdefault('is_superuser', False)
        return self._create_user(email, password, **extra_fields)

    def create_superuser(self, email, password, **extra_fields):
        """Create and save a SuperUser with the given email and password."""
        extra_fields.setdefault('is_staff', True)
        extra_fields.setdefault('is_superuser', True)

        if extra_fields.get('is_staff') is not True:
            raise ValueError('Superuser must have is_staff=True.')
        if extra_fields.get('is_superuser') is not True:
            raise ValueError('Superuser must have is_superuser=True.')

        return self._create_user(email, password, **extra_fields)


class User(AbstractUser):

    username = None
    email = models.EmailField(_('email'), unique=True)
    first_name = models.CharField( _('first name'), max_length=250)
    last_name = models.CharField(_('last name'), max_length=250)
    email_confirmed = models.BooleanField(default=False)

    USERNAME_FIELD = 'email'
    REQUIRED_FIELDS = ['first_name', 'last_name',]

    objects = UserManager()

    def __str__(self):
        return "%s" %(self.email)

settings.py

​​>

您需要为自定义用户模型设置的设置

# AUTH USER MODEL
AUTH_USER_MODEL = "Accounts.User" 

LOGIN_URL = '/login/'
#LOGIN_REDIRECT_URL  = 'login_success'

LOGOUT_REDIRECT_URL = '/login/'

admin.py

​​>

admin 你需要注册用户模型

## user model view
from django.contrib.auth.admin import UserAdmin as DjangoUserAdmin
from django.utils.translation import ugettext_lazy as _

@admin.register(User)
class UserAdmin(DjangoUserAdmin):
    """Define admin model for custom User model with no email field."""

    fieldsets = (
        (None, 'fields': ('email', 'password')),
        (_('Personal info'), 'fields': ('first_name', 'last_name', 'email_confirmed')),
        (_('Permissions'), 'fields': ('is_active', 'is_staff', 'is_superuser',
                                       'groups', 'user_permissions')),
        (_('Important dates'), 'fields': ('last_login', 'date_joined')),
    )

    add_fieldsets = (
        (None, 
            'classes': ('wide',),
            'fields': ('email', 'password1', 'password2', 'first_name', 'last_name'),
        ),
    )
    list_display = ('email', 'first_name', 'last_name',)
    search_fields = ('email', 'first_name', 'last_name')
    ordering = ('-id',)

【讨论】:

【参考方案9】:

非常简单的步骤:

转到项目urls.pyviews.login 更改为views.LoginView.as_view()

如果你正在使用 Logout 属性,那么对它做同样的事情

【讨论】:

【参考方案10】:

打开url.py文件并替换

views.loginviews.LoginView

【讨论】:

您能否添加更多上下文以使您的答案更合适?例如代码是什么?您正在用类替换函数,因此语法可能不一样。您可能还想提一下,这仅适用于 Django>=1.11 从 2 升级到 2.2.3 时,我在 django 2 中遇到此错误。我修复了我的网址,例如... url(r'^accounts/login/$', django.contrib.auth.views.LoginView,name="login"), url(r'^accounts/logout/$', django .contrib.auth.views.LogoutView,'next_page': '/',name="logout"),【参考方案11】:

你必须在你的 urls.py 中导入 LoginView:

from django.contrib.auth.views import LoginView

改变

auth_view.login

LoginView.as_view()

【讨论】:

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