如何通过类名获取类类型?
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【中文标题】如何通过类名获取类类型?【英文标题】:How to get class type by its class name? 【发布时间】:2013-08-20 21:44:45 【问题描述】:namespace Myspace
public class MyClass
//This class is in another file.
using Myspace;
static void Main(string[] args)
Regex regexViewModelKey = new Regex(RegularExpr.ViewModelKeyPattern);
string viewModel = regexViewModelKey.Match(match.Value).Value;
//Now, vieModel is a string, and its value is "MyClass". So, I only know the class name, this is why I ask this question.
//Now, I'm only allowed to use the string form of this class name to get its type.
//I have tyied like this, but its no use.
Type t = Type.GetType(viewModel);
//it's return a null.
//Then I tyied another method like this, but there is an exception when calling Assembly.Load
Assembly assembly = Assembly.Load("Myspace");
Type ty = assembly.GetType("Myspace" + viewModel);
我希望我的问题很清楚。谁能帮帮我.THX 我只允许使用这个类名的字符串形式来获取它的类型。
谢谢大家。 我自己就这样解决了这个问题。
Type t = Type.GetType(string.Concat(viewModel, ",", "Myspace"));
【问题讨论】:
也许这会有所帮助***.com/questions/17045635/… 试试这个方法 string model = "Myspace.MyClass";改用程序集限定名 ***.com/questions/648160/… 【参考方案1】:只需使用函数 typeof()。参数就是那个类名。
Type type = typeof(FIXProtoClientTest);
MSDN on typeof()
【讨论】:
仅当类型在编译时已知。【参考方案2】:一般来说,您几乎不需要进行类型比较,除非您使用反射或接口进行操作。尽管如此:
如果您知道要与之比较的类型,请使用 is
或 as
运算符:
if( unknownObject is TypeIKnow ) // run code here
as
运算符执行转换,如果失败而不是异常则返回 null
:
TypeIKnow typed = unknownObject as TypeIKnow;
如果您不知道类型并且只需要运行时类型信息,请使用.GetType()
方法:
Type typeInformation = unknownObject.GetType();
// int is a value type
int i = 0;
// Prints True for any value of i
Console.WriteLine(i.GetType() == typeof(int));
// string is a sealed reference type
string s = "Foo";
// Prints True for any value of s
Console.WriteLine(s == null || s.GetType() == typeof(string));
// object is an unsealed reference type
object o = new FileInfo("C:\\f.txt");
// Prints False, but could be true for some values of o
Console.WriteLine(o == null || o.GetType() == typeof(object));
// Get the type of a specified class.
Type myType1 = Type.GetType("System.Int32");
Console.WriteLine("The full name is 0.", myType1.FullName);
// Since NoneSuch does not exist in this assembly, GetType throws a TypeLoadException.
Type myType2 = Type.GetType("NoneSuch", true);
Console.WriteLine("The full name is 0.", myType2.FullName);
// FileSystemInfo is an abstract type
FileSystemInfo fsi = new DirectoryInfo("C:\\");
// Prints False for all non-null values of fsi
Console.WriteLine(fsi == null || fsi.GetType() == typeof(FileSystemInfo));
【讨论】:
我已经更改了我的问题,以便更清楚。你能再看一遍吗?谢谢【参考方案3】:如果您使用完全限定的类名(包括其命名空间),您的行 Type.GetType(model) 将起作用。
此外,如果它与进行调用的代码位于不同的程序集中,则当引用的程序集对象是包含该类型的程序集的实例时,您应该使用 Assembly.GetType(typeName)。
【讨论】:
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