具有按住动作和释放动作的 UIButton

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【中文标题】具有按住动作和释放动作的 UIButton【英文标题】:UIButton with hold down action and release action 【发布时间】:2013-10-07 12:54:03 【问题描述】:

我想创建一个可以按住的 UIButton,当按住时它会调用一次“按住”动作。 当它被释放时,调用“hold was release”动作。

此代码无法正常工作,因为触摸可以在按钮内移动并且事件未按正确顺序触发

[button handleControlEvent:UIControlEventTouchDown withBlock:^
        [self performMomentaryAction:PXActionTypeTouchDown];
    ];
[button handleControlEvent:UIControlEventTouchUpInside withBlock:^
        [self performMomentaryAction:PXActionTypeTouchUp];
    ];

处理控制事件是基于UIBUtton+block实现

【问题讨论】:

【参考方案1】:

试试这个

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];


 - (void)holdDown
  
     NSLog(@"hold Down");
  

  - (void)holdRelease
  
      NSLog(@"hold release");

  

对于 NSPratik 的情况:你可以使用事件UIControlEventTouchUpOutside 如果用户长按按钮并在一段时间后,用户不会松开手指,而是将他/她的手指移出按钮的边界。只需再添加一个事件。

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];
  [aButton addTarget:self action:@selector(holdReleaseOutSide) forControlEvents:UIControlEventTouchUpOutside]; //add this for your case releasing the finger out side of the button's frame

 //add this method along with other methods 
  - (void)holdReleaseOutSide
  
     NSLog(@"hold release out side");
  

斯威夫特版本

 var  aButton:UIButton = UIButton.buttonWithType(UIButtonType.Custom) as UIButton
 aButton.frame = CGRectMake(xValue,yValue, 45, 45)
 aButton.setTitle("aButton", forState: UIControlState.Normal)
 aButton.backgroundColor = UIColor.greenColor()
 aButton.addTarget(self, action: Selector("holdRelease:"), forControlEvents: UIControlEvents.TouchUpInside);
 aButton.addTarget(self, action: Selector("HoldDown:"), forControlEvents: UIControlEvents.TouchDown)
 self.addSubview(aButton)

 //target functions   
 func HoldDown(sender:UIButton)
 
    print("hold down")
 

 func holdRelease(sender:UIButton)
 
    print("hold release")
 

【讨论】:

它对我有用。但是,有一种情况是行不通的。如果用户长按按钮并在一段时间后,而不是松开手指,用户会将他/她的手指移出按钮的边界。在那种情况下,holdRelease 将不会被调用...【参考方案2】:

试试这个

将 TouchDown 、Touch Up Inside、Touch Up Outside 事件添加到您的按钮

 -(IBAction)theTouchDown:(id)sender
 

    timer = [NSTimer scheduledTimerWithTimeInterval:0.2
                                             target:self
                                           selector:@selector(performFunctionality)
                                           userInfo:nil
  
-(IBAction)theTouchUpInside:(id)sender

[timer invalidate];
timer = nil;
[self performFunctionality];

 


 -(IBAction)theTouchUpOutside:(id)sender
 
[timer invalidate];
timer = nil;
 

-(void)performFunctionality
 
 //write your logic
 

【讨论】:

【参考方案3】:

我自己也遇到过这个问题,我们大多使用这些事件:-

// 这个事件可以正常工作并触发

[aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];

// 这根本不会触发

[aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];

解决方法:-

使用长按手势识别器:-

 UILongPressGestureRecognizer *btn_LongPress_gesture = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleBtnLongPressgesture:)];
[aButton addGestureRecognizer:btn_LongPress_gesture];

手势的实现:-

- (void)handleBtnLongPressgesture:(UILongPressGestureRecognizer *)recognizer


//as you hold the button this would fire

if (recognizer.state == UIGestureRecognizerStateBegan) 

    [self holdDown];


//as you release the button this would fire

if (recognizer.state == UIGestureRecognizerStateEnded) 

    [self holdRelease];


【讨论】:

这种方法是唯一适用于我在 *** 上找到的所有相同答案的方法(ios 7.1.,Xcode 5.1.)。【参考方案4】:
    **in Swift 3.0,**

btnPasswordShow.addTarget(self, action:#selector(btnShowPasswordClickHoldDown), for: .touchDown)

btnPasswordShow.addTarget(self, action:#selector(btnShowPasswordClickRelease), for: .touchUpInside)

 func btnShowPasswordClickHoldDown()
    txtpassword.isSecureTextEntry = false
 

 func btnShowPasswordClickRelease()
     txtpassword.isSecureTextEntry = true
 

【讨论】:

【参考方案5】:

从工具(窗格)中拖动一个按钮并右键单击它。将出现一个列表,找到“内部修饰”并单击并拖动文本前面的圆点并将其移动到 viewcontroller.h 并定义一个名称并在 viewcontroller.m 中执行此操作。

nslog("clicked in"); 重复所有触摸操作并从列表中找到合适的事件

【讨论】:

【参考方案6】:

您需要连接以下两个事件 1.Touch Down ,2.Touch Up Inside 到它的 IBAction Methods 。在 Interface Builder 中会很有趣。但是您也可以使用 addTarget 以编程方式执行此操作: action: forControlEvents:

【讨论】:

【参考方案7】:

您可以使用计时器和按钮修饰来处理此操作


 var timer: Timer?

    @IBAction func dowm(_ sender: UIButton) 
        timer = Timer.scheduledTimer(withTimeInterval: 0.3, repeats: true, block:  (time) in
            print("im hold in ")
        )
    

    @IBAction func up(_ sender: UIButton) 
        timer!.invalidate()

    

这两个@IBAction 用于手柄触摸向上和触摸向下按钮 当按钮按下计时器启动并打印一些东西时,当按钮正在运行时,您会使计时器无效。

从 Github 访问已完成的项目:

https://github.com/sadeghgoo/RunCodeWhenUIbuttonIsHeld

【讨论】:

【参考方案8】:

我对此的最佳解决方案是将以下内容复制到您的 viewDidLoad 中:

// This will start your action.
hornTouchUp.addTarget(self, action: #selector(start), for: .touchDown)

// This will end your action.
hornTouchUp.addTarget(self, action: #selector(end), for: .touchUpInside)

并将这些函数放在您的viewDidLoad 下的同一文件中:

@objc func start()  print("start() triggered."); 
@objc func end()  print("end() triggered"); 

【讨论】:

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