限制分页页码
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【中文标题】限制分页页码【英文标题】:Limit pagination page number 【发布时间】:2012-01-11 19:20:29 【问题描述】:$objConnect = mysql_connect("localhost","root","") or die(mysql_error());
$objDB = mysql_select_db("Test");
$strSQL = "SELECT * FROM UserAddedRecord WHERE (Name LIKE '%".$getname."%' and State LIKE '%".$getstate."%' and Cell LIKE '%".$getcell."%' and Custgroup LIKE '%".$getgroup."%') AND user_id=$id";
$objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]");
$Num_Rows = mysql_num_rows($objQuery);
$Per_Page = 5;
if (!isset($_GET['Page']))
$Page = 1;
else
$Page = $_GET['Page'];
$Prev_Page = $Page - 1;
$Next_Page = $Page + 1;
$Page_Start = (($Per_Page * $Page) - $Per_Page);
if ($Num_Rows <= $Per_Page)
$Num_Pages = 1;
elseif (($Num_Rows % $Per_Page) == 0)
$Num_Pages = ($Num_Rows / $Per_Page) ;
else
$Num_Pages = ($Num_Rows / $Per_Page) + 1;
$Num_Pages = (int) $Num_Pages;
$strSQL .=" order by addedrec_ID DESC LIMIT $Page_Start , $Per_Page";
$objQuery = mysql_query($strSQL) or trigger_error(mysql_error());;
if ($Prev_Page)
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Prev_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'><< Back</a> ";
for ($i=1; $i <= $Num_Pages; $i++)
if ($i != $Page)
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$i&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>$i</a> ";
else
echo "<b> $i </b>";
if ($Page!=$Num_Pages)
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=$Next_Page&txtName=$getname&txtState=$getstate&txtCell=$getcell&txtGroup=$getgroup'>Next>></a> ";
mysql_close($objConnect);
这是我用来为数据搜索创建分页页面的代码。但我只是注意到我有太多的记录,那么它就会有太多的页码。我正在尝试限制显示的页码,并寻找很多例子..它有很多方法可以做到,但我仍然不知道如何限制我的方法......
【问题讨论】:
【参考方案1】:好吧,如果你的意思是显示类似的东西
Prev 1 2 3 4 5 6 .. 40 41 Next
Prev 1 2 .. 6 7 8 9 10 .. 40 41 Next
首先我们需要创建一个函数来处理我们需要输出分页的内容。这是我使用的一个功能,效果很好。
function get_paging_info($tot_rows,$pp,$curr_page)
$pages = ceil($tot_rows / $pp); // calc pages
$data = array(); // start out array
$data['si'] = ($curr_page * $pp) - $pp; // what row to start at
$data['pages'] = $pages; // add the pages
$data['curr_page'] = $curr_page; // Whats the current page
return $data; //return the paging data
现在这个功能非常可靠,对我来说效果很好。
所以你传递了这个函数
$tot_rows = 计算的查询行数 $pp = 每页项目数 $curr_page = 当前页码好的,现在您有了所需的数据,您需要显示它。
这是我使用的内容,请在您思考“啊,太长了”之前先阅读它。其实很简单。
这是它将返回的快照
<!-- Create the query -->
<?php $count = mysql_fetch_assoc( mysql_query ( "SELECT COUNT( rows ) as count FROM table" ) ) ;
<?php $count = $count[0]['count']; ?>
<!-- Call our function from above -->
<?php $paging_info = get_paging_info($count,5,34); ?>
<p>
<!-- If the current page is more than 1, show the First and Previous links -->
<?php if($paging_info['curr_page'] > 1) : ?>
<a href='' title='Page 1'>First</a>
<a href='' title='Page <?php echo ($paging_info['curr_page'] - 1); ?>'>Prev</a>
<?php endif; ?>
<?php
//setup starting point
//$max is equal to number of links shown
$max = 7;
if($paging_info['curr_page'] < $max)
$sp = 1;
elseif($paging_info['curr_page'] >= ($paging_info['pages'] - floor($max / 2)) )
$sp = $paging_info['pages'] - $max + 1;
elseif($paging_info['curr_page'] >= $max)
$sp = $paging_info['curr_page'] - floor($max/2);
?>
<!-- If the current page >= $max then show link to 1st page -->
<?php if($paging_info['curr_page'] >= $max) : ?>
<a href='' title='Page 1'>1</a>
..
<?php endif; ?>
<!-- Loop though max number of pages shown and show links either side equal to $max / 2 -->
<?php for($i = $sp; $i <= ($sp + $max -1);$i++) : ?>
<?php
if($i > $paging_info['pages'])
continue;
?>
<?php if($paging_info['curr_page'] == $i) : ?>
<span class='bold'><?php echo $i; ?></span>
<?php else : ?>
<a href='' title='Page <?php echo $i; ?>'><?php echo $i; ?></a>
<?php endif; ?>
<?php endfor; ?>
<!-- If the current page is less than say the last page minus $max pages divided by 2-->
<?php if($paging_info['curr_page'] < ($paging_info['pages'] - floor($max / 2))) : ?>
..
<a href='' title='Page <?php echo $paging_info['pages']; ?>'><?php echo $paging_info['pages']; ?></a>
<?php endif; ?>
<!-- Show last two pages if we're not near them -->
<?php if($paging_info['curr_page'] < $paging_info['pages']) : ?>
<a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.($paging_info['curr_page'] + 1); ?>' title='Page <?php echo ($paging_info['curr_page'] + 1); ?>'>Next</a>
<a href='<?php echo str_replace('/page'.$paging_info['curr_page'], '', $paging_info['curr_url']) . '/page'.$paging_info['pages']; ?>' title='Page <?php echo $paging_info['pages']; ?>'>Last</a>
<?php endif; ?>
</p>
【讨论】:
非常感谢您的示例和所有说明,我现在正在努力理解和学习它。 很高兴为您提供帮助。显然,我刚刚从我的代码中获取了这个并对其进行了一些修改,但结构已经存在,供您使用。 这种页面导航的问题是很难到达“...”范围中间的页面(至少通过单击)。您可以考虑使用我在this question 中描述的方法,即使有数千个页面,也可以通过几次鼠标点击轻松访问任何页面。 这对我来说是一个很好的基础,谢谢!一些小调整让我得到了我想成为的地方。 curr_url 的用户是什么以及我们在函数中传递它的位置?【参考方案2】:$count_pages = ceil($total / $items_per_page);
【讨论】:
【参考方案3】:我在这里用非常相似的脚本为其他人解决了一个非常相似的问题:How to limit pages shown in pagination script
此外,我注意到您的脚本还有一些其他异常(除了我修复的不可读格式)。您应该将所有出现的$_SERVER[SCRIPT_NAME]
更改为$_SERVER['SCRIPT_NAME']
。例如,在您的脚本中:
echo " <a href ='$_SERVER[SCRIPT_NAME]?Page=...";
会变成:
echo " <a href ='$_SERVER['SCRIPT_NAME']?Page=...";
【讨论】:
【参考方案4】:简单点,代码如下:
<?php
//put this code on the begining of the page
$page=$_GET['page']; //Getting page number from url | example: www.mydomain.com/index.php?page=3
if(!is_numeric($page)) $page=1; //If there is no page number specified we set number 1
$queryCount = "SELECT * FROM table "; //select from db
$query = $DB->query( $queryCount);
$num = mysql_num_rows ($query); //count num rows
$per_page=5; //default 5 results per page
$start=$per_page*($page-1); //start for select on next page (page2, 3, 4,5)
$end=min($num,$page*$per_page); //end
//here is select for your results. Be careful for LIMIT in the select!
$query = "SELECT * FROM page LIMIT $start, $per_page ";
//page bottom, where you want to put your numbers
$pages=ceil($num/$per_page);
for($s=1; $s<=$pages; $s++)
if($s==$page)
$numPage .= "[$s] ";
else
$numPage .= "<a href='index.php?page=$s'>$s</a> ";
echo $numPage;
?>
我没有测试它,但我认为它必须工作:-)
问候,伊万
【讨论】:
代码有效,但这只是简单地打印所有页码。问题是将页码限制为例如 10 页码。如果用户在第 12 页,那么它应该显示例如 10 到 20 等。【参考方案5】:我的代码总是显示至少 9 页,以防总页数>9 无论您在第 1、2、3 页上是什么
<ul class="pagination pagination-sm" style="align:center">
<li><a href="./?page=1"><</span></a></li>
<?php
if ($current_page <4)
if ($total_pages<9)
for($i = 1; $i <= $total_pages; $i++)
if ($i == $current_page)
echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
else
echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
else
for($i = 1; $i <= 9; $i++)
if ($i == $current_page)
echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
else
echo ' <li><a href="./?trang='.$i.'">'; echo $i.'</a></li>'."\n";
elseif ($current_page >$total_pages-4)
if ($total_pages<9)
for($i = 1; $i <= $total_pages; $i++)
if ($i == $current_page)
echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
else
echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
else
for($i = $total_pages-8; $i <= $total_pages; $i++)
if ($i == $current_page)
echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
else
echo ' <li><a href="./?page='.$i.'">'; echo $i.'</a></li>'."\n";
else
for($i = max(1, $current_page - 4); $i <= min($current_page + 4, $total_pages); $i++)
if ($i == $current_page)
echo '<li class="active"><a href="#">'; echo $i.'</a></li>'."\n";
else
echo ' <li><a href="./?trang='.$i.'">'; echo $i.'</a></li>'."\n";
?>
<li>
<a href="./?trang=<?php echo $total_pages ?>">></a>
</li>
</ul>
【讨论】:
【参考方案6】:您需要在 sql 语句中使用 LIMIT
子句。例如:
SELECT <column>
FROM <table>
LIMIT 0, 5
参考:SELECT Syntax
【讨论】:
感谢您的回复。是这一行吗?$strSQL .=" order by addedrec_ID DESC LIMIT $Page_Start , $Per_Page";
【参考方案7】:
此代码的目的只是显示分页中确定的(特定)页数
从url获取当前页码并定义$curr_pg_numb
从mysql获取总页数并定义$total_pages
这是分页的代码
$counter=0;
$init_num_to_left = 3;//initial number of pages to show to left from current page
$init_num_to_right = 4;
if( $curr_pg_numb - $init_num_to_left < 1 )
$init_num_to_right = $init_num_to_right + ( 1 - ($curr_pg_numb - $init_num_to_left) );
$init_num_to_left = $curr_pg_numb - 1;
else if( $curr_pg_numb + $init_num_to_right > $total_pages )
$init_num_to_left = $init_num_to_left + ( ($curr_pg_numb + $init_num_to_right) - $total_pages );
$init_num_to_right = ($curr_pg_numb + $init_num_to_right) - $total_pages;
while($counter <= $total_pages )
if ( $counter > 0 )
if ($curr_pg_numb==$counter)
echo '<strong> '. ( htmlspecialchars($curr_pg_numb , ENT_QUOTES, "UTF-8") + 0 ). '</strong> ';
else
if ( $counter >= ($curr_pg_numb - $init_num_to_left ) and $counter <= ($curr_pg_numb + $init_num_to_right ) )
echo '<a href="?cpn='. htmlspecialchars(($counter), ENT_QUOTES, "UTF-8"). '" style="margin:5px;">'. htmlspecialchars(($counter), ENT_QUOTES, "UTF-8"). '</a>';
//else
//if ( $counter > 0 )
$counter++;
//while($counter <= $total_pages )
【讨论】:
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