获取第一个元素作为索引以更新列表中的其余元素

Posted 2023-02-16

【中文标题】获取第一个元素作为索引以更新列表中的其余元素

【英文标题】：Get first element as index to update the rest of the elements within the list

【发布时间】：2021-03-29 23:04:28

【问题描述】：

This is my web output using flask

registrant_record = [['1', 'James Dommenick Asaria', '[e-mail]', '09057367450', 'reg'], ['2', 'Dominador Sultan', '[e-mail] ', '09363319670', 'reg']]

我想在点击更新按钮时获取第一个元素。

【参考方案1】：

    registrant_record = [['1', 'James Dommenick Asaria', '[e-mail]', '09057367450', 'reg'], ['2', 'Dominador Sultan', '[e-mail]', '09363319670', 'reg']]
    registrant_dict=
    for i in registrant_record:
        registrant_dict[int(i[0])]=i[1:]


    print(registrant_dict[1])
    output
    ['James Dommenick Asaria', '[e-mail]', '09057367450', 'reg']

   ##### if you want just the first name ####
    registrant_record = [['1', 'James Dommenick Asaria', '[e-mail]', '09057367450', 'reg'], ['2', 'Dominador Sultan', '[e-mail]', '09363319670', 'reg']]
    registrant_dict=
    for i in registrant_record:
        # you want to get the first change i[1] or second element i[2]
        registrant_dict[int(i[0])]=i[1]
    
    print(registrant_dict[1])
    output
    ['James Dommenick Asaria']