Access-Control-Allow-Origin 和 Angular.js $http
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【中文标题】Access-Control-Allow-Origin 和 Angular.js $http【英文标题】:Access-Control-Allow-Origin and Angular.js $http 【发布时间】:2014-01-12 07:38:22 【问题描述】:每当我制作 web 应用程序并遇到 CORS 问题时,我都会开始制作咖啡。在搞砸了一段时间后,我设法让它工作了,但这次不行,我需要帮助。
这是客户端代码:
$http(method: 'GET', url: 'http://localhost:3000/api/symbol/junk',
headers:
'Access-Control-Allow-Origin': '*',
'Access-Control-Allow-Methods': 'GET, POST, PUT, DELETE, OPTIONS',
'Access-Control-Allow-Headers': 'Content-Type, X-Requested-With',
'X-Random-Shit':'123123123'
)
.success(function(d) console.log( "yay" ); )
.error(function(d) console.log( "nope" ); );
服务器端是带有 express 应用的常规 node.js。我有一个名为 cors 的扩展,它以这种方式与 express 一起使用:
var app = express();
app.configure(function()
app.use(express.bodyParser());
app.use(app.router);
app.use(cors(origin:"*"));
);
app.listen(3000);
app.get('/', function(req, res)
res.end("ok");
);
如果我这样做了
curl -v -H "Origin: https://github.com" http://localhost:3000/
返回:
* Adding handle: conn: 0x7ff991800000
* Adding handle: send: 0
* Adding handle: recv: 0
* Curl_addHandleToPipeline: length: 1
* - Conn 0 (0x7ff991800000) send_pipe: 1, recv_pipe: 0
* About to connect() to localhost port 3000 (#0)
* Trying ::1...
* Trying 127.0.0.1...
* Connected to localhost (127.0.0.1) port 3000 (#0)
> GET / HTTP/1.1
> User-Agent: curl/7.30.0
> Host: localhost:3000
> Accept: */*
> Origin: https://github.com
>
< HTTP/1.1 200 OK
< X-Powered-By: Express
< Date: Tue, 24 Dec 2013 03:23:40 GMT
< Connection: keep-alive
< Transfer-Encoding: chunked
<
* Connection #0 to host localhost left intact
ok
如果我运行客户端代码,它会引发此错误:
OPTIONS http://localhost:3000/api/symbol/junk No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:8000' is therefore not allowed access. angular.js:7889
XMLHttpRequest cannot load http://localhost:3000/api/symbol/junk. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:8000' is therefore not allowed access. localhost/:1
nope
检查 Chrome 标头:
Request URL:http://localhost:3000/api/symbol/junk
Request Method:OPTIONS
Status Code:200 OK
Request Headersview source
Accept:*/*
Accept-Encoding:gzip,deflate,sdch
Accept-Language:en-US,en;q=0.8,es;q=0.6,pt;q=0.4
Access-Control-Request-Headers:access-control-allow-origin, accept, access-control-allow-methods, access-control-allow-headers, x-random-shit
Access-Control-Request-Method:GET
Cache-Control:max-age=0
Connection:keep-alive
Host:localhost:3000
Origin:http://localhost:8000
Referer:http://localhost:8000/
User-Agent:Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_0) AppleWebKit/537.36 (Khtml, like Gecko) Chrome/31.0.1650.63 Safari/537.36
Response Headersview source
Allow:GET
Connection:keep-alive
Content-Length:3
Content-Type:text/html; charset=utf-8
Date:Tue, 24 Dec 2013 03:27:45 GMT
X-Powered-By:Express
检查请求标头我看到我的测试字符串 X-Random-Shit 存在于“Access-Control-Request-Headers”中,但它的值不存在。此外,在我的脑海中,我希望看到我设置的每个标题都对应一行,而不是一个 blob。
更新 ---
我把我的前端改成了 jQuery 而不是 Angular,我的后端是这样的:
var app = express();
app.configure(function()
app.use(express.bodyParser());
app.use(app.router);
);
app.all('*', function(req, res, next)
res.header("Access-Control-Allow-Origin", "*");
res.header('Access-Control-Allow-Methods', 'OPTIONS,GET,POST,PUT,DELETE');
res.header("Access-Control-Allow-Headers", "Content-Type, Authorization, X-Requested-With");
if ('OPTIONS' == req.method)
return res.send(200);
next();
);
app.get('/', function(req, res)
res.end("ok");
);
现在它适用于 GET,但不适用于其他任何东西(PUT、POST..)。
我会看看你们中是否有人提出了解决方案。与此同时,我们将 RESTful 概念抛到脑后,并使用 GET 完成一切。
【问题讨论】:
咖啡解决了很多问题... =~) 【参考方案1】:我是 AngularJS 的新手,遇到了这个 CORS 问题,差点失去理智!幸运的是,我找到了解决此问题的方法。就这样吧……
我的问题是,当我使用 AngularJS $resource 发送 API 请求时,我收到了这个错误消息 XMLHttpRequest cannot load http://website.com. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost' is therefore not allowed access.
是的,我已经添加了 callback="JSON_CALLBACK" 但它不起作用。
我做了什么来解决这个问题,而不是使用 GET 方法或诉诸 $http.get,我使用了 JSONP。只需将 GET 方法替换为 JSONP,并将 api 响应格式也更改为 JSONP。
myApp.factory('myFactory', ['$resource', function($resource)
return $resource( 'http://website.com/api/:apiMethod',
callback: "JSON_CALLBACK", format:'jsonp' ,
method1:
method: 'JSONP',
params:
apiMethod: 'hello world'
,
method2:
method: 'JSONP',
params:
apiMethod: 'hey ho!'
);
]);
我希望有人觉得这很有帮助。 :)
【讨论】:
【参考方案2】:我在表达和编辑res.header
方面取得了成功。我的和你的很接近,但我有一个不同的Allow-Headers
,如下所述:
res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");
我也在使用 Angular 和 Node/Express,但我没有在 Angular 代码中仅调用节点/express 中的标头
【讨论】:
【参考方案3】:编写这个中间件可能会有所帮助!
app.use(function(req, res, next)
res.header("Access-Control-Allow-Origin", "*");
res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");
next();
);
详情请访问http://enable-cors.org/server_expressjs.html
【讨论】:
【参考方案4】:将下面添加到 server.js 解决了我的问题
server.post('/your-rest-endpt/*', function(req,res)
console.log('');
console.log('req.url: '+req.url);
console.log('req.headers: ');
console.dir(req.headers);
console.log('req.body: ');
console.dir(req.body);
var options =
host: 'restAPI-IP' + ':' + '8080'
, protocol: 'http'
, pathname: 'your-rest-endpt/'
;
console.log('options: ');
console.dir(options);
var reqUrl = url.format(options);
console.log("Forward URL: "+reqUrl);
var parsedUrl = url.parse(req.url, true);
console.log('parsedUrl: ');
console.dir(parsedUrl);
var queryParams = parsedUrl.query;
var path = parsedUrl.path;
var substr = path.substring(path.lastIndexOf("rest/"));
console.log('substr: ');
console.dir(substr);
reqUrl += substr;
console.log("Final Forward URL: "+reqUrl);
var newHeaders =
;
//Deep-copy it, clone it, but not point to me in shallow way...
for (var headerKey in req.headers)
newHeaders[headerKey] = req.headers[headerKey];
;
var newBody = (req.body == null || req.body == undefined ? : req.body);
if (newHeaders['Content-type'] == null
|| newHeaders['Content-type'] == undefined)
newHeaders['Content-type'] = 'application/json';
newBody = JSON.stringify(newBody);
var requestOptions =
headers:
'Content-type': 'application/json'
,body: newBody
,method: 'POST'
;
console.log("server.js : routes to URL : "+ reqUrl);
request(reqUrl, requestOptions, function(error, response, body)
if(error)
console.log('The error from Tomcat is --> ' + error.toString());
console.dir(error);
//return false;
if (response.statusCode != null
&& response.statusCode != undefined
&& response.headers != null
&& response.headers != undefined)
res.writeHead(response.statusCode, response.headers);
else
//404 Not Found
res.writeHead(404);
if (body != null
&& body != undefined)
res.write(body);
res.end();
);
);
【讨论】:
【参考方案5】:@Swapnil Niwane
我能够通过调用 ajax 请求并将数据格式化为“jsonp”来解决此问题。
$.ajax(
method: 'GET',
url: url,
defaultHeaders:
'Content-Type': 'application/json',
"Access-Control-Allow-Origin": "*",
'Accept': 'application/json'
,
dataType: 'jsonp',
success: function (response)
console.log("success ");
console.log(response);
,
error: function (xhr)
console.log("error ");
console.log(xhr);
);
【讨论】:
【参考方案6】:我找到了一种在$http
中直接使用JSONP
方法并在配置对象中支持params
的方法:
params =
'a': b,
'callback': 'JSON_CALLBACK'
;
$http(
url: url,
method: 'JSONP',
params: params
)
【讨论】:
【参考方案7】:试试这个:
$.ajax(
type: 'POST',
url: URL,
defaultHeaders:
'Content-Type': 'application/json',
"Access-Control-Allow-Origin": "*",
'Accept': 'application/json'
,
data: obj,
dataType: 'json',
success: function (response)
// BindTableData();
console.log("success ");
alert(response);
,
error: function (xhr)
console.log("error ");
console.log(xhr);
);
【讨论】:
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