Android HTTPPost 返回错误“方法不允许”。
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【中文标题】Android HTTPPost 返回错误“方法不允许”。【英文标题】:Android HTTPPost Returns Error "Method not allowed." 【发布时间】:2011-09-10 11:19:11 【问题描述】:我正在编写一个 android 2.2 应用程序,该应用程序将 json 严格性发布到 ReSTfull 网络服务。
Fiddler 调用具有相同 Json 的 Web 服务按预期返回,具有相同 Json 的 aspx Web 应用程序按预期返回。
当我查看服务器日志时,我可以看到服务器正在响应带有 307 重定向的初始 POST 动词,然后立即出现 GET 和 405 错误。
Fiddler 和 aspx 应用程序记录一个 307 重定向的 POST,然后立即另一个 POST 和 200 OK。
发生了什么事?
这是主要活动:
package com.altaver.android_PostJson2;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
public class PostJson extends Activity
private static final String TAG = "MainActivity";
private static final String URL = "http://web2.altaver.com/sdz/avReSTfulLogin1";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
JSONObject jsonObjSend = new JSONObject();
try
jsonObjSend.put("Pass", "sz");
jsonObjSend.put("User", "szechman");
Log.i(TAG, jsonObjSend.toString(2));
catch (JSONException e)
e.printStackTrace();
JSONObject jsonObjRecv = HttpClient.SendHttpPost(URL, jsonObjSend);
//examine JSONObject later
这是执行 Web 服务调用的类代码:
package com.altaver.android_PostJson2;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.Header;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.params.HttpClientParams;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONObject;
import android.util.Log;
public class HttpClient
private static final String TAG = "HttpClient";
public static JSONObject SendHttpPost(String URL, JSONObject jsonObjSend)
try
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpClientParams.setRedirecting(httpclient.getParams(), true);
//added cookie policy, wild shot in the dark
//httpclient.getParams().setParameter(ClientPNames.COOKIE_POLICY, >CookiePolicy.RFC_2109);
HttpPost httpPostRequest = new HttpPost(URL);
StringEntity se;
se = new StringEntity(jsonObjSend.toString());
// Set HTTP parameters
httpPostRequest.setEntity(se);
//httpPostRequest.setHeader("User-Agent", >"com.altaver.android_PostJson2");
httpPostRequest.setHeader("User-Agent", "Mozilla/5.0 (Windows; U; >Windows NT 5.1; en-US; rv:1.9.2.3) Gecko/20100401");
httpPostRequest.setHeader("Accept", "application/json");
httpPostRequest.setHeader("Content-Type", "application/json");
long t = System.currentTimeMillis();
HttpResponse response = (HttpResponse) >httpclient.execute(httpPostRequest);
Log.i(TAG, "HTTPResponse received in [" + >(System.currentTimeMillis()-t) + "ms]");
HttpEntity entity = response.getEntity();
if (entity != null)
InputStream instream = entity.getContent();
Header contentEncoding = response.getFirstHeader("Content-Encoding");
String resultString= convertStreamToString(instream);
instream.close();
resultString = resultString.substring(1,resultString.length()-1); // >remove wrapping "[" and "]"
JSONObject jsonObjRecv = new JSONObject(resultString);
Log.i(TAG,"<jsonobject>\n"+jsonObjRecv.toString()+"\n</jsonobject>");
return jsonObjRecv;
catch (Exception e)
e.printStackTrace();
return null;
private static String convertStreamToString(InputStream is)
/*
* To convert the InputStream to String we use the >BufferedReader.readLine()
* method. We iterate until the BufferedReader return null which means
* there's no more data to read. Each line will appended to a >StringBuilder
* and returned as String.
*
* (c) public domain: http://senior.ceng.metu.edu.tr/2009/praeda/2009/01>/11/a-simple-restful-client-at-android/
*/
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try
while ((line = reader.readLine()) != null)
sb.append(line + "\n");
catch (IOException e)
e.printStackTrace();
finally
try
is.close();
catch (IOException e)
e.printStackTrace();
return sb.toString();
【问题讨论】:
【参考方案1】:在 URL 末尾添加“/”会导致重定向发生,因为您的服务器喜欢以“/”结尾的 URL。您的服务器将您重定向到的 URL 完全支持 POST,但是当客户端根据您的 setRedirecting() 调用运行时,客户端正在执行 GET 请求(cURL 使用 -L 开关执行相同的操作)解决方法是要么放URL 末尾的“/”,或者自己从响应中获取 Location 标头,然后手动发起另一个 POST 请求。
这可以在wireshark中观察到。您可以通过尝试使用浏览器对附加斜杠的 URL 执行 GET 请求来测试该理论。这将导致浏览器收到 405。这是 Android 的固定代码,此代码使用在 URL 上附加“/”的简单修复(未准备好生产):
package com.altaver.demo;
import java.io.IOException;
import java.io.UnsupportedEncodingException;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.HttpResponseException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.params.HttpClientParams;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.Toast;
public class AltaVerDemoActivity extends Activity
private static final String TAG = "MainActivity";
private static final String URL = "http://96.56.2.188/sdz/avReSTfulLogin1/";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
JSONObject jsonObjSend = new JSONObject();
try
jsonObjSend.put("Pass", "sz");
jsonObjSend.put("User", "szechman");
catch (JSONException e)
// TODO Auto-generated catch block
e.printStackTrace();
HttpClient client = new DefaultHttpClient();
HttpPost httpPostRequest = new HttpPost(URL);
httpPostRequest.setHeader("User-Agent", "com.altaver.android_PostJson2");
httpPostRequest.setHeader("Accept", "application/json");
httpPostRequest.setHeader("Content-Type", "application/json");
StringEntity se = null;
try
se = new StringEntity(jsonObjSend.toString());
catch (UnsupportedEncodingException e)
// TODO Auto-generated catch block
e.printStackTrace();
httpPostRequest.setEntity(se);
HttpResponse response = null;
try
response = client.execute(httpPostRequest);
catch (ClientProtocolException e)
// TODO Auto-generated catch block
Toast.makeText(getApplicationContext(),
"Please check your internet connection",
Toast.LENGTH_SHORT).show();
e.printStackTrace();
catch (IOException e)
// TODO Auto-generated catch block
e.printStackTrace();
BasicResponseHandler responseHandler = new BasicResponseHandler();
String strResponse = null;
if (response != null)
try
strResponse = responseHandler.handleResponse(response);
catch (HttpResponseException e)
// TODO Auto-generated catch block
e.printStackTrace();
catch (IOException e)
// TODO Auto-generated catch block
e.printStackTrace();
Log.e("AltaVerDemoActivity", "Response: " + strResponse);
【讨论】:
非常感谢您的帮助,汤姆。这是正确的答案。 @Stuart,你在几毫米之外。你在这个问题上给了我很大的帮助。 我已经工作了3个多小时,非常感谢:)【参考方案2】:如果服务中的请求类型是WebGet,例如,经常会出现上述问题
WebGet(UriTemplate = "login/?name=name&password=password", ResponseFormat = WebMessageFormat.Json)"
然后您尝试通过 android 使用 HttpPost 访问该方法。
我有同样的问题,我花了几个小时才弄明白。
【讨论】:
【参考方案3】:我看了上面的答案,似乎有点太复杂了!!
我为解决这个问题所做的一切(正如一些答案所说,是由于不允许 POST 的服务),就是改变:
HttpPost post = new HttpPost(params[0]);
HttpResponse response = client.execute(post);
对于
HttpGet get = new HttpGet(params[0]);
HttpResponse response = client.execute(get);
这就解决了!
PD:我正在获取状态代码:405!
【讨论】:
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