每天刷个算法题20160525:快速排序的递归转非递归解法
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http://blog.csdn.net/xiaofei_it/article/details/51524798
为了防止思维僵化,每天刷个算法题。已经刷了几天了,现在发点代码。
我已经建了一个开源项目,每天的题目都在里面:
https://github.com/Xiaofei-it/Algorithms
绝大部分算法都是我自己写的,没有参考网上通用代码。读者可能会觉得有的代码晦涩难懂,因为那是我自己的理解。
最近几天都是在写一些原来的东西,大多数是非递归。以后准备刷点DP、贪心之类的题。
下面是快速排序的递归转非递归解法。
是不是没有人像我这样蛋疼地把快速排序写成非递归的???
/**
*
* Copyright 2016 Xiaofei
*
* Licensed under the Apache License, Version 2.0 (the "License");
* you may not use this file except in compliance with the License.
* You may obtain a copy of the License at
*
* http://www.apache.org/licenses/LICENSE-2.0
*
* Unless required by applicable law or agreed to in writing, software
* distributed under the License is distributed on an "AS IS" BASIS,
* WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
* See the License for the specific language governing permissions and
* limitations under the License.
*
*/
package xiaofei.algorithm;
import java.util.Stack;
/**
* Created by Xiaofei on 16/5/25.
*
*/
public class QuickSort
private static int[] array;
private static void sortCorecursively(int l, int r)
class Element
int l;
int r;
int i;
int state;
//这里用state表示通用状态,和之前非递归代码风格不一样。
Element(int l, int r)
this.l = l;
this.r = r;
this.i = -1;
this.state = 0;
Stack<Element> stack = new Stack<>();
stack.push(new Element(l, r));
while (!stack.isEmpty())
Element element = stack.peek();
if (element.state == 0)
int i = element.l, j = element.r, m = array[(i + j) / 2];
do
while (array[i] < m)
++i;
while (m < array[j])
--j;
if (i <= j)
int temp = array[i];
array[i] = array[j];
array[j] = temp;
++i;
--j;
while (i <= j);
element.i = i;
if (element.l < j)
stack.push(new Element(element.l, j));
element.state = 1;
else if (element.state == 1)
if (element.i < element.r)
stack.push(new Element(element.i, element.r));
element.state = 2;
else if (element.state == 2)
stack.pop();
public static void sort(int[] array)
QuickSort.array = array;
sortCorecursively(0, array.length - 1);
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