python 面向对象 super().__init__()

Posted 2023-01-13

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Thu Jun 18 14:01:36 2020

@author: lg
"""

class Init(object):
    
    
    def __init__(self, value):
        self.value=value
        print(start Init,self.value)
        



class Add2(Init):
    def __init__(self, value):

        print(start Add2,value)
        super(Add2, self).__init__(value)
        
#        print(self.value,add,up)
        self.value = 2 + self.value
#        print(self.value,add,down)



class Mul5(Init):
    def __init__(self, value):
        
        print(start Mul5,value)
        super(Mul5, self).__init__(value)
        
#        print(self.value,mul5,up)
        self.value = self.value * 5
#        print(self.value,mul5,down)



class Pro(Mul5, Add2):
    
    print(start Pro)
    pass


class Incr(Pro):
    print(start Incr1)
    def __init__(self, value):
        print(start Incr,value)
        
        
        super(Incr, self).__init__(value)
#        print(self.value,Intr,up)
        self.value = self.value + 1
#        print(self.value,Intr,down)

print(Incr.mro())

[<class __main__.Incr>, <class __main__.Pro>, <class __main__.Mul5>, <class __main__.Add2>, <class __main__.Init>, <class object>]

说实话上面关于super的用法我并不十分理解，姑且说明一我的理解

• 从Incr.mro()中我们可以看出类继承的关系，这里面有单继承和多继承
• 这个例子的特别之处是value，比如在类Incr中并不是马上被执行 print(self.value,‘Intr’,‘up’)而是 super(Incr, self).init(value)被向上传递，一直传到根节点

p = Incr(5)

start Incr 5
start Mul5 5
start Add2 5
start Init 5

• 也就是说根节点类Init中的value是5，然后在顺序执行

print(p.value) #查看你的结果如果是36 x