数据结构与算法__03--二叉树前序线索化与前序线索化遍历(Java语言版)
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(目录)
1 前序线索化与前序线索化遍历
1.1 前序线索化二叉树
public void threadedPreNode(HeroNode node)
if (node == null)
return;
//线索化当前节点
if (node.getLeft() == null)
node.setLeft(pre);
node.setLeftType(1);
if (pre != null && pre.getRight() == null)
pre.setRight(node);
pre.setRightType(1);
pre = node;
//线索化左子树
if (node.getLeftType() != 1)
threadedPreNode(node.getLeft());
//线索化右子树
if (node.getRightType() != 1)
threadedPreNode(node.getRight());
1.2 前序线索化遍历
public void threadedPreList()
//定义一个变量,存储当前遍历的结点,从root开始
HeroNode node = root;
while (node != null)
//打印当前这个结点
System.out.println(node);
while (node.getLeftType() == 0)
node = node.getLeft();
System.out.println(node);
//如果当前结点的右指针指向的是后继结点,就一直输出
while (node.getRightType() == 1)
//获取到当前结点的后继结点
node = node.getRight();
System.out.println(node);
//替换这个遍历的结点
node = node.getRight();
2 完整代码
package edu.seu.demo10tree.demothreadedbinarytree;
public class Demo01ThreadedBinaryTree
public static void main(String[] args)
//测试一把中序线索二叉树的功能
HeroNode root = new HeroNode(1, "tom");
HeroNode node2 = new HeroNode(3, "jack");
HeroNode node3 = new HeroNode(6, "smith");
HeroNode node4 = new HeroNode(8, "mary");
HeroNode node5 = new HeroNode(10, "king");
HeroNode node6 = new HeroNode(14, "dim");
//二叉树,后面我们要递归创建, 现在简单处理使用手动创建
root.setLeft(node2);
root.setRight(node3);
node2.setLeft(node4);
node2.setRight(node5);
node3.setLeft(node6);
//测试中序线索化 8, 3, 10, 1, 14, 6
ThreadedBinaryTree threadedBinaryTree = new ThreadedBinaryTree();
threadedBinaryTree.setRoot(root);
// threadedBinaryTree.threadedNode();
// 中序 8, 3, 10, 1, 14, 6
// HeroNode leftNode = node5.getLeft();
// HeroNode rightNode = node5.getRight();
// System.out.println("10号结点的前驱结点是=" + leftNode); //3
// System.out.println("10号结点的后继结点是=" + rightNode); //1
// System.out.println("使用线索化的方式遍历 线索化二叉树");
// threadedBinaryTree.threadedList();
// 前序 1,3,8,10,6,14
threadedBinaryTree.threadedPreNode(root);
HeroNode leftNode = node5.getLeft();
HeroNode rightNode = node5.getRight();
System.out.println("10号结点的前驱结点是=" + leftNode);
System.out.println("10号结点的后继结点是=" + rightNode);
System.out.println("使用线索化的方式遍历 线索化二叉树");
threadedBinaryTree.threadedPreList();
class HeroNode
private int no;//英雄编号
private String name;//姓名
private HeroNode left;//左子节点
private HeroNode right;//右子节点
private int rightType;//表示右子节点:指针:0,后继:1
private int leftType;//表示左子节点:指针:0 前驱:1
public int getRightType()
return rightType;
public void setRightType(int rightType)
this.rightType = rightType;
public int getLeftType()
return leftType;
public void setLeftType(int leftType)
this.leftType = leftType;
//构造方法
public HeroNode(int no, String name)
this.no = no;
this.name = name;
//读取与设置私有变量
public int getNo()
return no;
public void setNo(int no)
this.no = no;
public String getName()
return name;
public void setName(String name)
this.name = name;
public HeroNode getLeft()
return left;
public void setLeft(HeroNode left)
this.left = left;
public HeroNode getRight()
return right;
public void setRight(HeroNode right)
this.right = right;
//打印输出
@Override
public String toString()
return "HeroNode" +
"no=" + no +
", name=" + name + \\ +
;
//前序遍历
public void preOrder()
System.out.println(this);//1.输出父节点
if (this.getLeft() != null) //2.向左遍历
this.getLeft().preOrder();
if (this.getRight() != null) //3.向右遍历
this.getRight().preOrder();
//中序遍历
public void infixOrder()
if (this.getLeft() != null)
this.getLeft().infixOrder();
System.out.println(this);
if (this.getRight() != null) //3.向右遍历
this.getRight().infixOrder();
//后序遍历
public void postOrder()
if (this.getLeft() != null)
this.getLeft().postOrder();
if (this.getRight() != null) //3.向右遍历
this.getRight().postOrder();
System.out.println(this);
//前序遍历查找
public HeroNode preOrderSearch(int no)
System.out.println("前序查找比较次数");
if (this.getNo() == no)
return this;
HeroNode resHero = null;
if (this.left != null)
resHero = this.left.preOrderSearch(no);
if (resHero != null)
return resHero;
if (this.right != null)
resHero = this.right.preOrderSearch(no);
return resHero;
//中序遍历查找
public HeroNode infixOrderSearch(int no)
HeroNode resHero = null;
if (this.left != null)
resHero = this.left.infixOrderSearch(no);
if (resHero != null)
return resHero;
System.out.println("中序查找比较次数");
if (this.getNo() == no)
return this;
if (this.right != null)
resHero = this.right.infixOrderSearch(no);
return resHero;
//后序遍历查找
public HeroNode postOrderSearch(int no)
HeroNode resHero = null;
if (this.left != null)
resHero = this.left.postOrderSearch(no);
if (resHero != null)
return resHero;
if (this.right != null)
resHero = this.right.postOrderSearch(no);
if (resHero != null)
return resHero;
System.out.println("后序查找比较次数");
if (this.getNo() == no)
return this;
return resHero;
//删除节点
public void delHeroNode(int no)
if (this.left != null && this.left.getNo() == no)
this.left = null;
return;
if (this.right != null && this.right.getNo() == no)
this.right = null;
return;
if (this.left != null)
this.left.delHeroNode(no);
if (this.right != null)
this.right.delHeroNode(no);
class ThreadedBinaryTree
private HeroNode root;//根节点
private HeroNode pre = null;
public ThreadedBinaryTree()
public void threadedNode()
threadedNode(root);
//中序遍历线索化二叉树的方法
public void threadedList()
//定义一个变量,存储当前遍历的结点,从root开始
HeroNode node = root;
while (node != null)
//循环的找到leftType == 1的结点,第一个找到就是8结点
//后面随着遍历而变化,因为当leftType==1时,说明该结点是按照线索化
//处理后的有效结点
while (node.getLeftType() == 0)
node = node.getLeft();
//打印当前这个结点
System.out.println(node);
//如果当前结点的右指针指向的是后继结点,就一直输出
while (node.getRightType() == 1)
//获取到当前结点的后继结点
node = node.getRight();
System.out.println(node);
//替换这个遍历的结点
node = node.getRight();
//中序线索化二叉树
public void threadedNode(HeroNode node)
if (node == null)
return;
//线索化左子树
threadedNode(node.getLeft());
//线索化当前节点
if (node.getLeft() == null)
node.setLeft(pre);
node.setLeftType(1);
if (pre != null && pre.getRight() == null)
pre.setRight(node);
pre.setRightType(1);
pre = node;
//线索化右子树
threadedNode(node.getRight());
//前序线索化二叉树
public void threadedPreNode(HeroNode node)
if (node == null)
return;
//线索化当前节点
if (node.getLeft() == null)
node.setLeft(pre);
node.setLeftType(1);
if (pre != null && pre.getRight() == null)
pre.setRight(node);
pre.setRightType(1);
pre = node;
//线索化左子树
if (node.getLeftType() != 1)
threadedPreNode(node.getLeft());
//线索化右子树
if (node.getRightType() != 1)
threadedPreNode(node.getRight());
//前序线索化遍历
public void threadedPreList()
//定义一个变量,存储当前遍历的结点,从root开始
HeroNode node = root;
while (node != null)
//打印当前这个结点
System.out.println(node);
while (node.getLeftType() == 0)
node = node.getLeft();
System.out.println(node);
//如果当前结点的右指针指向的是后继结点,就一直输出
while (node.getRightType() == 1)
//获取到当前结点的后继结点
node = node.getRight();
System.out.println(node);
//替换这个遍历的结点
node = node.getRight();
public HeroNode getRoot()
return root;
public void setRoot(HeroNode root)
this.root = root;
//前序遍历
public void preOrder()
if (this.root != null)
this.root.preOrder();
else
System.out.println("二叉树为空");
//中序遍历
public void infixOrder()
if (this.root != null)
this.root.infixOrder();
else
System.out.println("二叉树为空");
//后序遍历
public void postOrder()
if (this.root != null)
this.root.postOrder();
else
System.out.println("二叉树为空");
//前序遍历查找
public HeroNode preOrderSearch(int no)
if (root != null)
return root.preOrderSearch(no);
else
return null;
//中序遍历查找
public HeroNode infixOrderSearch(int no)
if (root != null)
return root.infixOrderSearch(no);
else
return null;
//后序遍历查找
public HeroNode postOrderSearch(int no)
if (root != null)
return this.root.postOrderSearch(no);
else
return null;
//删除节点
public void delHeroNode(int no)
if (root != null)
if (root.getNo() == no)
root = null;
else
root.delHeroNode(no);
else
System.out.println("二叉树为空");
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