Leetcode 102. Binary Tree Level Order Traversal

Posted 2022-12-12 zhangwj0101

Question

Given a binary tree, return the level order traversal of its nodes’ values. (ie, from left to right, level by level).

For example:
Given binary tree 3,9,20,#,#,15,7,

    3
   / \\
  9  20
    /  \\
   15   7

return its level order traversal as:

[
  [3],
  [9,20],
  [15,7]
]

Code

 public List<List<Integer>> levelOrder(TreeNode root) 
        List<List<Integer>> results = new ArrayList<>();
        if (root == null) 
            return results;
        
        Queue<TreeNode> queues = new ArrayDeque<>();
        queues.add(root);
        while (!queues.isEmpty()) 
            int len = queues.size();
            List<Integer> temp = new ArrayList<>();
            for (int i = 0; i < len; i++) 
                TreeNode remove = queues.remove();
                temp.add(remove.val);
                if (remove.left != null) 
                    queues.add(remove.left);
                
                if (remove.right != null) 
                    queues.add(remove.right);
                
            
            results.add(temp);
        

        return results;