点阵字模显示

Posted 2022-12-09 9reyson

LED点阵显示并放大的要点 ： * 先根据字模提取的方式将其储存在 16*16 two-dimension array 中，方便读取 * 在读取字模时，利用二维数组，同时读取前16个byte和后16个byte * 4中取膜方式的读取方法都大同小异
1. 点阵格式：阴码 取膜方式：逐行 取膜走向：顺向 输出数制：16进制

/****************************************
FileName: YinCode_Row_FirstHigh
Description: output "暨", extract font mask of "暨" by yin code, row by row, first bit is high
Reversion History: 2
Author: greyson
Date: 2014/04/26
****************************************/
#include<stdio.h>

#define uchar unsigned char

void ExtractJi();
void display( uchar );

uchar Ji[16][16];
uchar size;

uchar JiMask[32]=0x7D,0xFC,0x44,0x20,0x7D,0x20,0x45,0xFE,0x7C,0x50,0x48,0x52,0x54,0x92,0x65,0x0E,
0x1F,0xF0,0x10,0x10,0x1F,0xF0,0x10,0x10,0x1F,0xF0,0x00,0x00,0xFF,0xFE,0x00,0x00;

int main()

	ExtractJi();

	while(1)
		printf("请输入字体扩大的倍数(1至5之间的整数，按其他数字则退出)\\n");
		scanf("%d",&size);
		if (size >= 6)
			return 0;
		display(size);
	

	return 0;


/* transform JiMask into 2-dimension array(16*16) */
void ExtractJi()

	uchar bit;
	uchar i, j;
	for(i=0; i<16; i++)
		bit=0x80;
		for(j=0; j<8; j++)
			if( (JiMask[2*i] & bit) != 0 )
				Ji[i][j]=1;
			else
				Ji[i][j]=0;

			if( (JiMask[2 * i + 1] & bit) != 0 )
				Ji[i][j+8]=1;
			else
				Ji[i][j+8]=0;

			bit=bit>>1;	
		
	


/* display "暨" according to array Ji */
void display(uchar n)

	uchar i, j, m, k;

	for (i = 0; i < 16; i++)
		for (m = 1; m <= n; m++)
			for (j = 0; j < 16; j++)
				for(k = 1; k <= n; k++)
					if ( Ji[i][j] == 1)
						printf("*");
					else
						printf(" ");
				
			
			printf("\\n");
		

1.  点阵格式：阴码 取膜方式：列行式 取膜走向：逆向（低位在前）

/****************************************
FileName: YinCode_RowByCol_FirstLow
Description: output "暨", extract font mask of "暨" by yin code, row by column, first bit is low
Reversion History: 1
Author: greyson
Date: 2014/04/27
****************************************/
#include<stdio.h>

#define uchar unsigned char

void ExtractJi();
void display( uchar );

uchar Ji[16][16];
uchar size;

uchar JiMask[32]=0x00,0xFF,0x95,0x55,0x35,0xDF,0x00,0x8D,0x49,0x39,0x0F,0x79,0x89,0x89,0xE8,0x00,
0x40,0x40,0x40,0x5F,0x55,0x55,0x55,0x55,0x55,0x55,0x55,0x5F,0x40,0x40,0x40,0x00;

int main()

	ExtractJi();

	while(1)
		printf("请输入字体扩大的倍数(1至5之间的整数，按其他数字则退出)\\n");
		scanf("%d",&size);
		if (size >= 6)
			return 0;
		display(size);
	

	return 0;


/* transform JiMask into 2-dimension array(16*16) */
void ExtractJi()

	uchar bit;
	uchar i, j;
	bit=0x01;
	for(i=0; i<8; i++)
		for(j=0; j<16; j++)
			if( (JiMask[j] & bit) != 0 )
				Ji[i][j]=1;
			else
				Ji[i][j]=0;

			if( (JiMask[j + 16] & bit) != 0 )
				Ji[i+8][j]=1;
			else
				Ji[i+8][j]=0;
		
		bit=bit<<1;	
	


/* display "暨" according to array Ji,which store data by display format*/
void display(uchar n)

	uchar i, j, m, k;

	for (i = 0; i < 16; i++)
		for (m = 1; m <= n; m++)
			for (j = 0; j < 16; j++)
				for(k = 1; k <= n; k++)
					if ( Ji[i][j] == 1)
						printf("*");
					else
						printf(" ");
				
			
			printf("\\n");