thinkphp 用jquery ajax前后台交互

Posted 2022-12-03 yuhaiqiang_123

$.ajax(
type:"post",
url:"url room/ajaxchaxun",
data:"num=7&roomid="+'$roomid'+"&shijian="+'$shijian',
success:　function(data)
data =  eval('(' + data + ')'); 
 alert(data.yuename);

);