python3.3.5运行报can't assign to fuunction call,咋回事?
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参考技术Apython3.3.5运行报can't assign to fuunction call出现这个的原因以及解决的方法如下:
1、电脑上面可以带有相关的病毒。需要使用杀毒软件对电脑进行病毒查杀。
2、电脑硬件老化,配置较低,已经担负不起多任务的处理。在条件运行的状况下更换一台配置好一点电脑就可以有效解决出现卡死的问题。
3、电脑上面缓存的垃圾文件较多。可以使用杀毒软件对电脑里面进行垃圾清理。
4、关闭和卸载电脑上面不常使用到的软件。多任务处理会增加CPU的负荷,可以关闭和卸载一些没有使用到的软件来减轻电脑的运行负荷。
5、电脑本身的硬件出现故障。使用检测软件检测硬盘是否出现坏道,电脑是否出现什么异常的声音。
python2.7安装etuptools-36.6.0报ascii' codec can't decode byte 0xce in position 7问题
解决办法1:
原文链接:http://blog.csdn.net/all_over_servlet/article/details/45112221
修改编码为gbk,修改D:\\Python27\\Lib\\ntpath.py(位置由个人python安装目录决定)文件中的def join(path, *paths)函数,在函数内第一行加入
reload(sys)
sys.setdefaultencoding(‘gbk‘)
即:
# Join two (or more) paths. def join(path, *paths): """Join two or more pathname components, inserting "\\\\" as needed.""" reload(sys) sys.setdefaultencoding(‘gbk‘) result_drive, result_path = splitdrive(path) for p in paths: p_drive, p_path = splitdrive(p) if p_path and p_path[0] in ‘\\\\/‘: # Second path is absolute if p_drive or not result_drive: result_drive = p_drive result_path = p_path continue elif p_drive and p_drive != result_drive: if p_drive.lower() != result_drive.lower(): # Different drives => ignore the first path entirely result_drive = p_drive result_path = p_path continue # Same drive in different case result_drive = p_drive # Second path is relative to the first if result_path and result_path[-1] not in ‘\\\\/‘: result_path = result_path + ‘\\\\‘ result_path = result_path + p_path ## add separator between UNC and non-absolute path if (result_path and result_path[0] not in ‘\\\\/‘ and result_drive and result_drive[-1:] != ‘:‘): return result_drive + sep + result_path return result_drive + result_path
解决办法2:(PS:这是网上最多解答的帖子,不一定能够解决,楼主自己是依照解决方法1解决了问题)
注意Python语法缩进原则。
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