oracle 英文时间转换 Tue Sep 08 14:52:07 CST 2015

Posted 2023-05-09

怎么转换成 2015/9/8 4:21:47 年月日时分秒格式

参考技术A SELECT TO_CHAR(SYSDATE,'YYYY/MM/DD HH24:MI:SS') FROM DUAL;

Oracle 11g 将结果表旋转 90 度

【中文标题】Oracle 11g 将结果表旋转 90 度

【英文标题】：Oracle 11g Rotate Result Table 90 Degrees

【发布时间】：2018-07-03 11:47:40

【问题描述】：

我需要将结果集旋转 90 度。我一直在玩 pivot 和 unpivot，但到目前为止还没有成功。结果集如下所示：

2018-07-03  TUE 20:00   12:15   465 (null)
2018-07-02  MON 20:00   20:05   -5  FAIL
2018-06-29  FRI 19:30   19:04   26  (null)
2018-06-28  THU 20:00   19:07   53  (null)
2018-06-27  WED 20:00   19:37   23  (null)

我需要能够将整个结果集旋转 90 度，以便第 1 列（日期）成为列标题，并且数据的重置位于这些列下方，如下所示：

2018-06-27  2018-06-28  2018-06-29  2018-07-02  2018-07-03
WED         THU         FRI         MON         TUE
20:00       20:00       19:30       20:00       20:00
19:37       19:07       19:04       20:05       12:15
23          53          56          -5          465
(null)      (null)      (null)      FAIL        (null)

是否有其他功能可以实现这一点，或者可能是我还没想出来的枢轴/取消枢轴方法？

【问题讨论】：

现在每一列都包含不同类型的数据，结果集中的每一行都需要一列。以这种方式消费数据对哪个系统有利？

【参考方案1】：

你可以生成这样的逻辑，比如使用这个 SQL

select vl as date1, myCol as myCol1
    from 
       (
        select to_char(myDate,'yyyy-mm-dd') as mD, 
               to_char(myDate,'DY') as Dy, 
               to_char(myVal) as mVl, t.* from tab t
         where to_char(mydate,'yyyy-mm-dd') = <a_date_parameter>
       )
        unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status))

由unpivot概念的贡献为：

create table tab( myDate date, myHourStart varchar2(5), myHourEnd varchar2(5), myVal int, status varchar2(15) );
insert all 
   into tab values( date'2018-07-03','20:00','12:15', 465, null )
   into tab values( date'2018-07-02','20:00','20:05', -5, 'FAIL' )
   into tab values( date'2018-06-29','19:30','19:04', 26,  null )
   into tab values( date'2018-06-28','20:00','19:07', 53, null )
   into tab values( date'2018-06-27','20:00','19:37', 23,  null ) 
select * from dual;

select date1, date2, date3, date4, date5 from
(  select vl as date1, myCol as myCol1
    from 
       (
        select to_char(myDate,'yyyy-mm-dd') as mD, 
               to_char(myDate,'DY') as Dy, 
               to_char(myVal) as mVl, t.* from tab t
         where to_char(mydate,'yyyy-mm-dd') = '2018-06-27'
       )
        unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status)) 
         ) q1 join
  (  select vl as date2, myCol as myCol2
      from 
         (
          select to_char(myDate,'yyyy-mm-dd') as mD, 
                 to_char(myDate,'DY') as Dy,
                 to_char(myVal) as mVl, t.* from tab t
           where to_char(mydate,'yyyy-mm-dd') = '2018-06-28'
         )
          unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status)) 
           ) q2 on ( q1.myCol1 = q2.myCol2  )  
join
  (  select vl as date3, myCol as myCol3
      from 
         (
          select to_char(myDate,'yyyy-mm-dd') as mD, 
                 to_char(myDate,'DY') as Dy,
                 to_char(myVal) as mVl, t.* from tab t
           where to_char(mydate,'yyyy-mm-dd') = '2018-06-29'
         )
          unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status)) 
           ) q3 on ( q1.myCol1 = q3.myCol3  ) 
join
  (  select vl as date4, myCol as myCol4
      from 
         (
          select to_char(myDate,'yyyy-mm-dd') as mD, 
                 to_char(myDate,'DY') as Dy,
                 to_char(myVal) as mVl, t.* from tab t
           where to_char(mydate,'yyyy-mm-dd') = '2018-07-02'
         )
          unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status)) 
           ) q4 on ( q1.myCol1 = q4.myCol4  )            
join
  (  select vl as date5, myCol as myCol5
      from 
         (
          select to_char(myDate,'yyyy-mm-dd') as mD, 
                 to_char(myDate,'DY') as Dy,
                 to_char(myVal) as mVl, t.* from tab t
           where to_char(mydate,'yyyy-mm-dd') = '2018-07-03'
         )
          unpivot (vl for myCol in (mD,Dy,myHourStart, myHourEnd,mVl,status)) 
           ) q5 on ( q1.myCol1 = q5.myCol5  );

SQL Fiddle Demo