万年历编程

Posted 2023-05-08

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c语言或汇编都可以只要求显示年月日信息可调整日期有可以的我把分全加上最好附原理图

参考技术A #include<stdio.h>
void PrintMonthCalender(int startDay,int days);/*函数原型*/
int GetWeekDay(int year,int month);/*函数原型*/
int GetMonthDays(int year,int month);/*函数原型*/
main()

int month,year;/*定义变量*/

printf("input the year and month<YYYY-MM>:");
scanf("%d-%d",&year,&month);/*读入变量*/
printf("\t\t\t%d-%d\n",year,month);
printf("Sun.\tMon.\tTue.\tWed.\tThu.\tFri.\tSat.\n");/*打印日历表头*/

PrintMonthCalender(GetWeekDay(year,month),GetMonthDays(year,month));/*调用函数子程序，打印出某年某月日历*/

return 0;

/*定义打印日历子程序*/
void PrintMonthCalender(int startDay,int days)

int k=0,n=1;

while(k<startDay)

printf(" \t");
k++;

if(k==startDay&&k!=6)

printf("%d\t",n);
k++;
n++;

else if(k==startDay&&k==6)

printf("%d\n",n);
k++;
n++;

while(n<days)

if(k%7==6)

printf("%d\n",n);
k++;
n++;

else

printf("%d\t",n);
k++;
n++;

if(n=days)

printf("%d\n",n);
n++;

/*定义求某月一号为周几子程序*/
int GetWeekDay(int year,int month)

int GetMonthDays(int year,int month);
int n,WeekDay,days;

days=(year-1)*365+(year-1)/400+(year-1)/4-(year-1)/100;

for(n=1;n<month;++n)

days=days+GetMonthDays(year,n);

WeekDay=(days+1)%7;

return WeekDay;

/*定义求某年某月的天数子程序*/
int GetMonthDays(int year,int month)

int MonthDays;
if((year%4==0&&year%100!=0)||year%400==0)

if(month==4||month==6||month==9||month==11)
MonthDays=30;
else if(month==2)
MonthDays=29;
else
MonthDays=31;

else

if(month==4||month==6||month==9||month==11)
MonthDays=30;
else if(month==2)
MonthDays=28;
else
MonthDays=31;

return MonthDays;
参考技术B #include <stdio.h>
long int f(int year,int month)

if(month<3) return year-1;
else return year;

long int g(int month)

if(month<3) return month+13;
else return month+1;

long int n(int year,int month,int day)

return 1461L*f(year,month)/4+153L*g(month)/5+day;

int w(int year,int month,int day)

return(int) ((n(year,month,day)%7-621049L%7+7)%7);

int date[12][6][7];
int day_tbl[ ][12]=31,28,31,30,31,30,31,31,30,31,30,31,31,29,31,30,31,30,31,31,30,31,30,31;

main()

int sw,leap,i,j,k,wd,day;
int year;
char title[]="SUM MON TUE WED THU FRI SAT";

printf("Please input the year whose calendar you want to know:\n");
scanf("%d%*c",&year);

sw=w(year,1,1);
leap=year%4==0&&year%100||year%400==0;
for(i=0;i<12;i++)
for(j=0;j<6;j++)
for(k=0;k<7;k++)
date[i][j][k]=0;
for(i=0;i<12;i++)
for(wd=0,day=1;day<=day_tbl[leap][i];day++)

date[i][wd][sw]=day;
sw=++sw%7;
if(sw==0) wd++;

printf("\n|================== The Calendar of Year %d==================|\n|",year);
for(i=0;i<6;i++)

for(wd=0,k=0;k<7;k++)
wd+=date[i][5][k]+date[i+6][5][k];
wd=wd?6:5;
printf(" %2d %s %2d %s|\n|",i+1,title,i+7,title);
for(j=0;j<wd;j++)

printf(" ");
for(k=0;k<7;k++)
if(date[i][j][k])
printf("%4d",date[i][j][k]);
else printf(" ");
printf(" ");
for(k=0;k<7;k++)
if(date[i+6][j][k])
printf("%4d",date[i+6][j][k]);
else printf(" ");
printf("|\n|");

puts("==============================================================|");
本回答被提问者采纳参考技术C #include <stdio.h>
#include <string.h>
#include <ctype.h>
long year;
int month,day,error_input;
char s[100];
int monthdays[12]=31,28,31,30,31,30,31,31,30,31,30,31;
void inputdate()
long n[3]=0,0,0,k=0,i,len;
error_input=-1;
printf("Please input the year[,month[,day]]:(Enter Q to quit)\n");
gets(s);
len=strlen(s);
printf("%d\n",strcmp(s,"Q"));
if(strcmp(s,"Q")==0) error_input=0;return;

if(!isdigit(s[0])||!isdigit(s[len-1]))
error_input=1;return;
for(i=0;i<len;i++)
if(!isdigit(s[i])) if(isdigit(s[i-1])) k++;if(k>2) error_input=1;return;
else n[k]=n[k]*10+s[i]-48;

year=n[0];
if(!(year%4)&&(year%100)||!(year%400))
monthdays[1]=29;
else
monthdays[1]=28;
if(n[1]>12) error_input=1;return;
if(n[2]>monthdays[n[1]-1]) error_input=1;return;
month=n[1];
day=n[2];

void printCala()
int countyear,countday=0,weekflag,i,j,k,c;
int startmon,endmon,year1;
year1=year-1;
countyear=(year1-year1%4)/4-(year1-year1%100)/100+(year1-year1%400)/400;

weekflag=(countyear*366+(year-1-countyear)*365+1)%7-1;
if(month==0) startmon=1;endmon=12;
else startmon=month;endmon=month;
for(k=1;k<startmon;k++)
weekflag=(weekflag+monthdays[k-1])%7;
for(k=startmon;k<=endmon;k++)

printf("\n %ld year ",year);
switch(k)

case 1: printf("January\n");break;
case 2: printf("February\n");break;
case 3: printf("March\n");break;
case 4: printf("April\n");break;
case 5: printf("May\n");break;
case 6: printf("June\n");break;
case 7: printf("July\n");break;
case 8: printf("August\n");break;
case 9: printf("September\n");break;
case 10: printf("October\n");break;
case 11: printf("November\n");break;
case 12: printf("December\n");break;

printf("___________________________\n");
printf("Sun Mon Tue Whe Thr Fri Sat\n");
if(weekflag!=0)
for(countday=0,j=0;j<weekflag;j++)
printf(" ");
countday++;
for(i=1;i<=monthdays[k-1];i++)
if(countday>0&&countday%7==0)
printf("\n");
printf("%3d ",i);
countday++;
weekflag=(weekflag+monthdays[k-1])%7;
printf("\n___________________________\n");

int main()

inputdate();
while(error_input!=0)

if(error_input==1)
printf("Input ERROR! Please input again:\n");
else
printCala();
inputdate();

2019全球编程语言高薪排行榜：ScalaGo轻松达百万年薪

作者丨赵钰莹

对于开发者来说，不管是初入门者还是具备多年开发经验的老手，都会考虑自己的职业前景。此外，当开发者考虑接触一门新的编程语言时，除了应用场景，一定也希望了解企业愿意为不同的编程语言开发者付出多少薪水。

近日，Stack Overflow 发布了 2019 年的最新调查结果，总结了不同编程语言在行业中可能获得的薪水。当然，在这个过程中也需要关注一些其他因素，比如：语言对使用者是否友好，这有助于更快地学习语言；是否与现在的科技趋势相关。

（注：该数据根据 Stack Oveflow2019 年关于编程语言薪酬排行开发者调查报告得出。）

1 全球十大收入最高的编程语言