oracle 从系统里取出一个月的第几周

Posted 2023-05-06

oracle
fmww 是年的第几周
一个月的第几周怎么求？

参考技术A select date_col,to_number(to_char(trunc(sysdate,'yyyy'),'d')) year_week_day,first_day_week,week_no,week_no - first_day_week + 1 week_no
from (
select date_col,
to_number(to_char(trunc(sysdate,'mm') + 7 - 1 ,'ww')) first_day_week,
to_number(to_char(date_col + 7 - 1,'ww')) week_no
from (
select trunc(sysdate,'mm') + rownum - 1 date_col
from dba_objects
where rownum <= to_number(to_char(last_day(sysdate),'dd'))))本回答被提问者采纳 参考技术B select date_col,to_number(to_char(trunc(sysdate,'yyyy'),'d')) year_week_day,first_day_week,week_no,week_no - first_day_week + 1 week_no
from (
select date_col,
to_number(to_char(trunc(sysdate,'mm') + 7 - 1 ,'ww')) first_day_week,
to_number(to_char(date_col + 7 - 1,'ww')) week_no
from (
select trunc(sysdate,'mm') + rownum - 1 date_col
from dba_objects
where rownum <= to_number(to_char(last_day(sysdate),'dd'))))

python小问题:给定一个日期，如何确定这是今年的第几周？

使用python time模块来确定是一个很棒的想法：

import time
print (time.strftime("%W"))

今天是Fri Mar 23 12:47:48 2018.打印的数字是12，那么这就是今年的第12周