易语言如何处理json数据

Posted 2023-04-25

["id":"64","username":"西瓜都烂了","userll":"0","usernl":"0","usermj":"0","userzl":"0","userhp":"0","usermp":"0","uservocation":"2","usersxdian":"5","userjndian":"1","usergold":"100","userzhijing":"1","userexp":"0","usernextexp":"1000","vip":"0","userwuxing":"5","usergengu":"5","userjingjie":"0","usergongfa":"0","xx_users_id":"56"]

如上面这段，我需要在易语中分别取出不同段所对应的值。求大神帮忙。最后直接上代码。
要用直接json取值，不要分割文本啥的，那个效率不高。

参考技术A …I guess my answer would be determined by different conditions

Hive---如何处理json数据

问题：表中数据像如下这种情况(某个字段是JSON格式)，想要单独取出JSON中的某个字段：id，ids，total_number 怎么办?

hive (first_test)> select * from user;
OK
user.id user.infos      user.device_id
1       {"id": 1701439105,"ids": [2154137571,3889177061],"total_number": 493}   201
2       {"id": 1701439106,"ids": [2154137571,3889177061],"total_number": 494}   301
Time taken: 0.035 seconds, Fetched: 2 row(s)

文章目录

• get_json_object
• json_tuple （官方推荐：效率高）

1、建表

create table user(
id int,infos string,device_id int)
row format delimited
fields terminated by '\\t'
lines terminated by '\\n';

2、导入数据

user.txt

1       {"id": 1701439105,"ids": [2154137571,3889177061],"total_number": 493}   201
2       {"id": 1701439106,"ids": [2154137571,3889177061],"total_number": 494}   301

load data local inpath '/opt/soft/hive/testjob/user.txt' into table user;

get_json_object

使用 get_json_object 函数，对json字符串进行解析
使用方式：
select get_json_object(json所在的列名,’$.json中字段名1’,…)

例如：

hive (first_test)> select get_json_object(infos,'$.id') from user;
OK
_c0
1701439105
1701439106
Time taken: 0.071 seconds, Fetched: 2 row(s)

json_tuple （官方推荐：效率高）

使用json_tuple函数，对json字符串进行解析
使用方式：
select json_tuple(json所在的列名,“json中字段名1”,…) from 表名;

例如：

hive (first_test)> select json_tuple(infos,"total_number") from user_tmp;
OK
c0
493
494
Time taken: 0.033 seconds, Fetched: 2 row(s)