flowable设计器自定义自己的人员选择器

Posted 2021-12-22 小学生05101

@OC](设计器自定义自己的人员、组选择器)

背景

很多外国的设计是不合适国内的使用习惯，就比方说人员选择器和组选择器，他们都是id和第一个名字，中国哪里能看的懂呀，所以我们自定义修改一下。

组选择器

@RestController
@RequestMapping("/app")
public class EditorGroupsResource 
    @Autowired
    protected IdmIdentityService idmIdentityService;
    @RequestMapping(value = "/rest/editor-groups", method = RequestMethod.GET)
    public ResultListDataRepresentation getGroups(@RequestParam(required = false, value = "filter") String filter) 
        if (StringUtils.isNotBlank(filter)) 
            filter = filter.trim();
            String sql = "select * from act_id_group where NAME_ like #name";
            filter = "%" + filter + "%";
            List<Group> groups = idmIdentityService.createNativeGroupQuery().sql(sql).parameter("name", filter).listPage(0, 10);
            List<GroupRepresentation> result = new ArrayList<>();
            for (Group group : groups) 
                result.add(new GroupRepresentation(group));
            
            return new ResultListDataRepresentation(result);
        
        return null;
    

人员选择器

@RestController
@RequestMapping("/app")
public class EditorUsersResource 
    @Autowired
    protected IdmIdentityService idmIdentityService;
    @Autowired
    protected ManagementService managementService;
    @RequestMapping(value = "/rest/editor-users", method = RequestMethod.GET)
    public ResultListDataRepresentation getUsers(@RequestParam(value = "filter", required = false) String filter) 
        if (StringUtils.isNotBlank(filter)) 
            filter = filter.trim();
            String sql = "select * from act_id_user where ID_ like #id or LAST_ like #name";
            filter = "%"+filter+"%";
            List<User> matchingUsers = idmIdentityService.createNativeUserQuery().sql(sql).parameter("id",filter).parameter("name",filter).listPage(0, 10);List<UserRepresentation> userRepresentations = new ArrayList<>(matchingUsers.size());
            for (User user : matchingUsers) 
                userRepresentations.add(new UserRepresentation(user));
            
            return new ResultListDataRepresentation(userRepresentations);
        
       return null;
    

实现效果