js 获取某年某月有几周，以及每周的周一和周末是几号到几号

Posted 2023-03-16

出现跨月的情况，从第一个 周一开始算第一周，前面的算是上个月的最后一周，最后一周不满用下个月补上
java 实现也行

<script>
    function getInfo(year, month) 
     var d = new Date();
     // what day is first day
     d.setFullYear(year, month-1, 1);
     var w1 = d.getDay();
     if (w1 == 0) w1 = 7;
     // total day of month
     d.setFullYear(year, month, 0);
     var dd = d.getDate();
     // first Monday
     if (w1 != 1) d1 = 7 - w1 + 2;
     else d1 = 1;
     week_count = Math.ceil((dd-d1+1)/7);
     document.write(year + "年" + month + "月有" + week_count +"周<br/>");
     for (var i = 0; i < week_count; i++) 
     var monday = d1+i*7;
     var sunday = monday + 6;
     var from = year+"/"+month+"/"+monday;
     var to;
     if (sunday <= dd) 
     to = year+"/"+month+"/"+sunday;
      else 
     d.setFullYear(year, month-1, sunday);
     to = d.getFullYear()+"/"+(d.getMonth()+1)+"/"+d.getDate();
    
     document.write("第"+(i+1)+"周 从" + from + " 到 " + to + "<br/>");
    
    
    getInfo(2013,12);
</script>

参考技术A <h1><span id="year"></span>年月份周数</h1>
<script type="text/javascript">
var time = new Date();
var year = time.getFullYear();
var countweek;
document.getElementById('year').innerhtml = year;

for(var i = 0 ; i < 12; i++)
countweek = 0;
var mondays;

//判断月份的天数
if(i == 0 ||i == 2 ||i == 4 ||i == 6 ||i == 7 ||i == 9 ||i == 11)
mondays = 31;

if(i == 3 ||i == 5 ||i == 8 ||i == 10)
mondays = 30;

if(i == 1)
if((year%4 == 0 && year%100 != 0) || year%400 == 0)
mondays = 28;
else
mondays = 29;



for(var j = 1 ; j < ( mondays + 1) ; j++ )
time.setMonth(i,j);
var date = time.getDay();
if(date == 1)
countweek = countweek + 1;




document.write(( i + 1 ) + '月有 ' + countweek + ' 周 , ' );

</script>

好问题，通过这个问题，我知道了很多东西。这个代码也是我花了几个小时研究写出来的，我还写了显示日历那样的，还在想用JS写个日历牌出来，但是现在还没想到。一起学习，一起进步！思路清晰了的话，很好懂。 参考技术B 看看js的Date()对象参考手册吧，够你完成功能的了追问

求详细代码，大神

追答

for语句一天一天的查呗，还能怎样

或者你也可以找到第一个星期一，然后计算

Date()对象是可以返回星期的

PHP获取一年有几周以及每周开始日期和结束日期

代码一：

<?php
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year = (int)$_GET[‘year‘];
$week = (int)$_GET[‘week‘];
$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
echo $year . ‘年一共有‘ . $weeks . ‘周<br />‘;
if ($week > $weeks || $week <= 0)
{
 $week = 1;
}
if ($week < 10)
{
 $week = ‘0‘ . $week;
}
$timestamp[‘start‘] = strtotime($year . ‘W‘ . $week);
$timestamp[‘end‘] = strtotime(‘+1 week -1 day‘, $timestamp[‘start‘]);
echo $year . ‘年第‘ . $week . ‘周开始时间戳：‘ . $timestamp[‘start‘] . ‘<br />‘;
echo $year . ‘年第‘ . $week . ‘周结束时间戳：‘ . $timestamp[‘end‘] . ‘<br />‘;
echo $year . ‘年第‘ . $week . ‘周开始日期：‘ . date("Y-m-d", $timestamp[‘start‘]) . ‘<br />‘;
echo $year . ‘年第‘ . $week . ‘周结束日期：‘ . date("Y-m-d", $timestamp[‘end‘]);
?>

代码二：

<?php
header("Content-type:text/html;charset=utf-8");
function getIsoWeeksInYear($year)
{
 $date = new DateTime;
 $date->setISODate($year, 53);
 return ($date->format("W") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
 $week_start = date(‘d-m-Y‘, strtotime(‘this week monday‘, $custom_date));
 $week_end = date(‘d-m-Y‘, strtotime(‘this week sunday‘, $custom_date));
 $week_array[0] = $week_start;
 $week_array[1] = $week_end;
 return $week_array;
}
echo ‘<br> Weeks in 2013<br>‘ . getIsoWeeksInYear(2013);
$weekday = weekday(strtotime(date(‘d-m-Y‘, strtotime(‘5-8-2013‘))));
echo ‘<br> 10-8-2013‘;
echo ‘<br>Start: ‘ . $weekday[0];
echo ‘<br>End: ‘ . $weekday[1];
?>