打印日历和当前时间（简单易懂）

Posted 2021-11-22 无痕恋雪

想打印当前时间先了解tm数据类型，懂得c结构库

头文件

#pragma once
#include<iostream>
using namespace std;
#include<string>
#include<ctime>
void show();//打印操作步骤
int judge(int year);//判断平年（365），闰年（366）
void add(int year, int month);//从1921年开始定义，计算1921年1月到输入的日历共有多少天
void print(int year, int month);//打印日历
void printnowtime();//打印当前的时间
#pragma warning(disable:4996);//因为使用打印当前的时间所需要用的函数
//（vs准备弃用strcpy的，安全性较低，所以微软提供了strcpy_s来代替）有报错
//若要继续使用要加上#pragma warning(disable:4996);

函数文件

#include"日历.h";
int leapmonth[13] = { 0,31,29,31,30,31,30,31,31,30,31,30,31 };//闰年
int ordinarymonth[13] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 };//平年
int year, month;
int temp;
int day;
int sum = 0;
int year2 ;
void show()//打印操作步骤
{
  cout << "**********************" << endl;
  cout << "*****1.查询日历*******" << endl;
  cout << "*****2.退出日历*******" << endl;
  cout << "**********************" << endl;
}
int judge(int year)//判断平年（365），闰年（366）
{
  if (year % 100 == 0)
  {
    if (year % 400 == 0)
    {
      return 2;
    }
    else
    {
      return 1;
    }
  }
  else
  {
    if (year % 4 == 0)
    {
      return 2;
    }
    else
    {
      return 1;
    }
  }
}
void add(int year, int month)//从1921年开始定义，计算1921年1月到输入的日历共有多少天(sum)
{
  year2 = 1921;
  for (int k = 0; k < year - 1921; k++)
  {
    int temp2 = judge(year2);
    if (temp2 == 1)
    {
      for (int i = 0; i < 13; i++)
      {
        sum = sum + ordinarymonth[i];
      }
    }
    else
    {
      for (int i = 0; i < 13; i++)
      {
        sum = sum + leapmonth[i];
      }
    }
    year2++;
  }
  temp = judge(year);
  for (int i = 0; i < month; i++)
  {
    if (temp == 1)
    {
      sum = sum + ordinarymonth[i];
    }
    else
    {
      sum = sum + leapmonth[i];
    }
  }
  
}
void print(int year, int month)//打印日历
{
  day = (sum + 6) % 7;
  if (day == 0)
  {
    day = 7;
  }
  int a = day;
  cout << year << "年" << month << "月" << endl;
  cout << " 一 " << \\t << " 二 " << \\t << " 三 " << \\t << " 四 " << \\t << " 五 " << \\t << " 六 " << \\t << " 日 " << endl;
  for (int i = 0; i < day - 1; i++)
  {
    cout << "   " << \\t;
  }
  if (temp == 1)
  {
    for (int i = 1; i <= ordinarymonth[month]; i++)
    {
      cout << " " << i << " " << \\t;
      if (a == 7)
      {
        cout << endl;
        a = 0;
      }
      a++;
    }
  }
  else
  {
    for (int i = 1; i <= leapmonth[month]; i++)
    {
      cout << " " << i << " " << \\t;
      if (a == 7)
      {
        cout << endl;
        a = 1;
      }
      a++;
    }
  }
  sum = 0;
  cout << endl;
}
void printnowtime()//打印当前的时间
{
  string xingqi[8] = { "日" ,"一","二","三","四","五","六"};
  time_t systemtime = time(NULL);
  tm* nowtime = localtime(&systemtime);
  cout << "当前时间为：";
  cout << 1900 + nowtime->tm_year << "年" << 1 + nowtime->tm_mon << "月" << nowtime->tm_mday << "日" << endl;
  cout << "星期" << xingqi[nowtime->tm_wday] << endl;
  cout << nowtime->tm_hour << ":" << nowtime->tm_min << ":" << nowtime->tm_sec << endl;
  cout << "----------------------------------------------------" << endl;
}

主文件

#include<iostream>
using namespace std;
#include<string>
#include"日历.h"
int main()
{
  int sum = 0;
  int year, month;
  int n = 0;
  show();//打印操作步骤
  cout << "请输入数字进行操作：";
  cin >> n;
  if (n <= 100000 && n >= -1000000)
  {
    while (true)
    {
      sum = 0;
      if (n == 1 || n == 2)
      {
        if (n == 1)
        {
          cout << "请输入年份：";
          cin >> year;
          cout << "请输入月份：";
          cin >> month;
          printnowtime();//打印当前的时间
          judge(year);//判断平年（365），闰年（366）
          add(year, month);//从1921年开始定义，计算1921年1月到输入的日历共有多少天
          print(year, month);//打印日历
          
        }
        else
        {
          cout << "欢迎下次使用！" << endl;
          return 0;
        }

      }
      else
      {
        cout << "输入错误，请重新输入！" << endl;
      }
      show();
      cout << "请输入数字进行操作：";
      cin >> n;
      system("cls");//清屏
    }
  }
  else
  {
    cout << "输入错误，请退出重试！！！" << endl;
    return 0;
  }
  return 0;
}

效果