51单片机linux环境LED数码管开关循环判断演示

Posted 2021-09-27 zhangrelay

示例程序如下，有bug，能运行但效果可提升：

 

#include <8052.h>         

#define LSA P1_5        
#define LSB P1_6        
#define LSC P1_7 

char SEG[10]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};

void init0(void)
{
LSA = 1;
LSB = 0;
LSC = 0;
} 
void init1(void)
{
LSA = 1;
LSB = 0;
LSC = 0;
}       
void init2(void)
{
LSA = 0;
LSB = 1;
LSC = 0;
}
void init3(void)
{
LSA = 1;
LSB = 1;
LSC = 0;
}
void init4(void)
{
LSA = 0;
LSB = 0;
LSC = 1;
}
void ledsplus(unsigned char leds,unsigned int delay)
{
P0=leds;
while(delay--);
delay=10000;
}
void seg1(unsigned char leds,unsigned int delay)
{
P0=SEG[leds];
//  delay=50000;
while(delay--);
}
int  main(void)     
{
init1();
unsigned char leds=0xff;
unsigned char cnt=0x00;
unsigned int delay=10000;
while(1)        
  {
if(P3_2==0)
    {
for(leds=0xff;leds>0x00;leds--)
      {
ledsplus(leds,delay);
if(P3_4==0)
        {
break;
        }
      }
    }
if(P3_3==0)
    {
for(leds=0x00;leds<11;leds++)
      {
seg1(leds,10000*cnt);
      }
    }
if(P3_4==0)
    {
cnt++;
if(cnt>7)
      {
cnt=0x00;
      }
    }

P0=0xff;
delay=10000;
  }
}